资源简介 中小学教育资源及组卷应用平台复数的四则运算1.的共轭复数为( ).A. B. C. D.【答案】A【详解】因为,则其共轭复数为.故选:A2.若,则( )A. B. C. D.【答案】B【详解】因为,所以.故选:B3.已知,则( )A. B.0 C. D.1【答案】A【详解】设,则,故,解之得,所以.故选:A4.已知(其中i为虚数单位),若是的共轭复数,则( )A. B.1 C. D.i【答案】D【详解】由,则,则,所以.故选:D.5.( )A. B.C. D.【答案】D【详解】.故选:D6.若复数满足,则( )A.2 B. C.3 D.5【答案】D【详解】,.故选:D.7.若为实数,且,则( )A.2 B.1 C. D.【答案】C【详解】由题意得,,故选:C.8.( )A. B. C. D.【答案】C【详解】;故选:C.9.已知复数,则( )A.1 B. C.2 D.【答案】B【详解】因为,所以.故选:B10.,则( )A. B.C. D.【答案】B【详解】,,.故选:B.11.设,则( )A. B. C.1 D.0【答案】A【详解】由题意可得,则,所以.故选:A12.已知为虚数单位,复数,则( )A.2 B. C. D.【答案】C【详解】,则.故选:C.13.已知为虚数单位,复数满足,则( )A. B. C. D.【答案】D【详解】依题意,,所以.故选:D14.若复数,则( )A.25 B.20 C.10 D.5【答案】D【详解】因为,所以,故选:D.15.设复数满足,则( )A.2 B.1 C. D.2【答案】A【详解】由,得,所以.故选:A.16.已知复数在复平面对应的点在实轴上,则( )A. B. C.2 D.-2【答案】C【详解】依题意,,因为复数在复平面对应的点在实轴上,所以,解得.故选:C.17.已知复数满足,则( )A.0 B.i C. D.【答案】D【详解】∵,∴,故选:D.18.若复数z满足,则( )A. B. C. D.【答案】B【详解】由已知可得,,从而.故选:B.19.设i为虚数单位,若复数z满足,则z的虚部为( )A. B. C.1 D.2【答案】D【详解】由,则,所以z的虚部为2.故选:D.20.已知复数满足,则的虚部为( )A. B. C. D.2【答案】C【详解】,故虚部为.故选:C21.已知,为虚数单位,则( )A. B. C. D.【答案】C【详解】因为,则.故选:C.22.已知复数满足,则的虚部为( )A. B. C.3 D.【答案】C【详解】因为,所以的虚部为3,故选:C.23.已知复数满足,则的值为( )A. B.2 C. D.【答案】D【详解】因为,所以,解得,故选:D24.已知复数z是方程的一个根,则( )A.1 B.2 C. D.【答案】C【详解】因为方程是实系数方程,且,所以该方程有两个互为共轭复数的两个虚数根,即,所以.故选:C25.若复数是纯虚数,则( )A.-2 B.2 C.-1 D.1【答案】D【详解】由题意设(),,即,则,解得:.故选:D26.已知复数满足,则复数( )A. B. C. D.【答案】B【详解】因为,则,因此,.故选:B.27.已知复数,则( )A. B. C.1 D.【答案】C【详解】法一:由复数乘法运算得,则,法二:由,则,故选:C28.已知复数满足,则___________.【答案】【详解】由得,因为,所以,故答案为:.29.______【答案】【详解】.故答案为:30.复数满足(是虚数单位),则的虚部为___________.【答案】-1【详解】令,则,所以,故的虚部为.故答案为:-1.31.设复数z满足(i为虚数单位),则____________.【答案】【详解】∵,则.故答案为:.32.复数,在复平面上对应的点分别为,,则________.【答案】/-i+3【详解】因为复数,在复平面上对应的点分别为,,所以,,所以,故答案为:.33.若复数(为虚数单位),则___________.【答案】【详解】,所以.故答案为:.34.若复数z满足(是虚数单位),则复数_____________.【答案】.【详解】由可得.故答案为:.35.若,则______【答案】【详解】因为,所以,故.故答案为:.36.若复数满足(其中i是虚数单位),则______.【答案】【详解】由,得,,则.故答案为:.37.已知复数,则的虚部为______.【答案】【详解】解:由题意得,则,所以的虚部为-4,故答案为:-438.已知复数满足,则_____________.【答案】【详解】因为,即,所以,或,若,则,则,若,则,则.综上所述,.故答案为:.39.已知复数满足(为虚数单位),则的虚部为_____________.【答案】/【详解】由得:,的虚部为.故答案为:.40.在复平面内,复数z所对应的点为,则___________.【答案】2【详解】由题意可知 ,所以,故答案为:241.已知复数z满足(其中i为虚数单位),则复数z的共轭复数为___________.【答案】【详解】由,得,则复数z的共轭复数为;故答案为:42.复数的值是_____________.【答案】【详解】解:.故答案为:.21世纪教育网 www.21cnjy.com 精品试卷·第 2 页 (共 2 页)21世纪教育网(www.21cnjy.com)中小学教育资源及组卷应用平台复数的四则运算1.的共轭复数为( ).A. B. C. D.2.若,则( )A. B. C. D.3.已知,则( )A. B.0 C. D.14.已知(其中i为虚数单位),若是的共轭复数,则( )A. B.1 C. D.i5.( )A. B.C. D.6.若复数满足,则( )A.2 B. C.3 D.57.若为实数,且,则( )A.2 B.1 C. D.8.( )A. B. C. D.9.已知复数,则( )A.1 B. C.2 D.10.,则( )A. B.C. D.11.设,则( )A. B. C.1 D.012.已知为虚数单位,复数,则( )A.2 B. C. D.13.已知为虚数单位,复数满足,则( )A. B. C. D.14.若复数,则( )A.25 B.20 C.10 D.515.设复数满足,则( )A.2 B.1 C. D.216.已知复数在复平面对应的点在实轴上,则( )A. B. C.2 D.-217.已知复数满足,则( )A.0 B.i C. D.18.若复数z满足,则( )A. B. C. D.19.设i为虚数单位,若复数z满足,则z的虚部为( )A. B. C.1 D.220.已知复数满足,则的虚部为( )A. B. C. D.221.已知,为虚数单位,则( )A. B. C. D.22.已知复数满足,则的虚部为( )A. B. C.3 D.23.已知复数满足,则的值为( )A. B.2 C. D.24.已知复数z是方程的一个根,则( )A.1 B.2 C. D.25.若复数是纯虚数,则( )A.-2 B.2 C.-1 D.126.已知复数满足,则复数( )A. B. C. D.27.已知复数,则( )A. B. C.1 D.28.已知复数满足,则___________.29.______30.复数满足(是虚数单位),则的虚部为___________.31.设复数z满足(i为虚数单位),则____________.32.复数,在复平面上对应的点分别为,,则________.33.若复数(为虚数单位),则___________.34.若复数z满足(是虚数单位),则复数_____________.35.若,则______36.若复数满足(其中i是虚数单位),则______.37.已知复数,则的虚部为______.38.已知复数满足,则_____________.39.已知复数满足(为虚数单位),则的虚部为_____________.40.在复平面内,复数z所对应的点为,则___________.41.已知复数z满足(其中i为虚数单位),则复数z的共轭复数为___________.42.复数的值是_____________.21世纪教育网 www.21cnjy.com 精品试卷·第 2 页 (共 2 页)21世纪教育网(www.21cnjy.com) 展开更多...... 收起↑ 资源列表 专题05 复数的四则运算(原卷版).docx 专题05 复数的四则运算(解析版).docx