资源简介 2025年高三年级模拟考试(二)物理(考试时间:上午9:00一10:15)注意事项:1.答题前,考生务必将自己的姓名、准考证号填写在本试题相应的位置。2.全部答案在答题卡上完成,答在本试题上无效。3.回答选择题时,选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。誕如需改动,用橡皮擦干净后,再选涂其他答案标号。回答非选择题时,将答案用0.5mm黑色笔迹签字笔写在答题卡上。4,考试结束后,将本试题和答题卡一并交回。长一、选择题:本题共7小题,每小题4分,共28分。在每小题给出的四个选项中,只有一项是符合题目要求的。1.某实验室利用水平向右的匀强电场,研究放射性元素的衰变产物。αB、y三束射线均垂直射人电场,如图为射线在电场中运动的径迹示意图,下列说法正确的是②粥A.径迹①对应α射线,其动量最大且电离能力最强①B.径迹②对应β射线,其速度为光速的0.99倍掘C.径迹③对应y射线,其穿透能力最强阁D.若将电场换为同方向匀强磁场,三束射线在图示示意图中都在径迹②所在直线龈2.某款智能电动汽车进行自动驾驶测试,在沿直线行驶的一段过程中,若汽车在中间时刻的动能与在中间位置的动能相等,则其可能的运动是A.汽车做匀加速直线运动B.汽车做加速度减小的加速直线运动C,汽车做加速度增大的减速直线运动D.汽车先做加速度减小的减速直线运动,紧接着又做加速度增大的加速直线运动物理试题第1页(共6页)3.现代喷气式飞机的燃气轮机工作循环简化如下:1→2过程空气被绝热压缩,2→3过程燃料燃烧气体等压膨胀,3+4过程高温气体绝热膨胀推动叶轮转动,4→+1过程废气等压压缩至初始状态。若气体始终可看作理想气体,下列说法正确的是PA.1+2过程中,气体温度升高B.2→3过程中,气体对外做负功C.3→4过程中,气体内能不变D.4→+1过程中,气体吸收热量04.燃气灶点火原理如图,直流电经转换器输出u=10sin100mt(V)的交流电,再经理想变压器升压。已知打火针和金属板间电压大于10kV才可引发电火花,下列选项正确的是A.2<1n11415B.1打火针金属板21000C.用电压表测原线圈两端电压,示数为10VD.副线圈输出交变电流的频率是100Hz5.如图所示为半圆形轨道,半径为R、0为圆心、A为圆弧最高点、C为圆弧上的一点,C0连线与竖直方向的夹角为。小球从地面上的D点斜向上抛出,到达C点时速度与OC垂直,且小球对轨道的压力为0,不计空气阻力,下列说法正确的是A.小球一定会停在A点B.小球一定会从C点沿圆轨道开始运动C.小球可能会从C点斜向上抛出后,落到A点D.小球一定会从C点斜向上抛出后,落到与C点关于OA对称的B点6.航天器飞过行星表面,利用行星引力改变其速度和轨道的一种技术叫做引力弹弓效应。某探测器原在半长轴为α的绕日椭圆轨道上运动,飞掠木星后进人一个半长轴为2α的绕日椭圆轨道。忽略其他行星的影响,下列说法正确的是A.木星的引力对探测器做正功,探测器机械能减少B.探测器在新轨道上的运行周期是在原轨道上的V8倍C.探测器在新轨道近日点的速率等于其在原轨道远日点的速率D.探测器在新轨道上近日点的加速度小于其在新轨道上远日点的加速度7.如图所示,质量为3m的斜面体静止在光滑水平地面上,其AB面粗糙、BC面光滑,顶端装有光滑的轻质定滑轮。质量分别为2m、m的物块P、Q通过轻绳连接并静置在斜面上,P与AB面之间的动摩擦因数为。现使整体在水平方向上加速,PQ始终在同一竖直面内且相对斜面体静止,重力加速度为g,下列说法正确的是物理试题第2页(共6页)太原市 2025 年高三年级模拟考试(二)物理参考答案与评分建议一、单项选择题:本题包含 7小题,每小题 4分,共 28分。题号 1 2 3 4 5 6 7选项 D D A B C B B二、多项选择题:本题包含 3小题,每小题 6分,共 18分。题号 8 9 10选项 AC AC ABC三、实验题:共 16分。11.(7分)(1)10 (1分)(2)50 (2分)(3)不变 (1分) 越小 (1分)(4)偏小 (2分)12.(9分)(1)R1(1分)(2)PTC(1分) NTC (1分)(3)变小(2分)(4)2.12(1分) 1.48(1分) 偏大(2分)四、计算题:共 38分。13.(8分)(1)光源 1到亮纹的距离为 r1,光源 2到亮纹的距离为 r2,光源 1到 r2的距离与两个光源1距离的夹角为θ,若亮纹到光屏中心的距离为 x2a ··········································································(1分)····················································································(1分)2a ····················································································(1分)····················································································(1分)(2)五条连续亮纹间距为 x = 6cm,因为 5条亮纹间有 4个间距,相邻亮纹间距=1.5cm = 0.015m······································································(1分)···················································································(1分)λ=750nm·····················································································(2分)14.(14分)(1)M刚到达 C点尚未与 N发生碰撞时,对 BC管道的压力恰好为 0,此时M只受重力··················································································· (1分)M由 A到 C,根据机械能守恒定律··············································· (1分)···························································(1分)(2)M与 N发生弹性正碰,碰撞过程中动量守恒、机械能守恒。设碰撞后M的速度为 ,N的速度为 v·······································································(1分)·································································(1分)···················································································(1分)(3)根据牛顿第二定律2对于 P: ································································ (1分)对于 Q: ···················································(1分)对于 P: ··························································(1分)对于 Q: ········································(1分)······················································································(1分)对于 N: ·····························································(1分)对于 Q: ········································································(1分)P与 N右端的最大距离··············································(1分)15.(16分)(1)设正离子经 bc间电压加速后从 d处喷出时的速度为 v,····························································(2分)选取研究对象- 0··········································· (2分)·····························································(1分)(2)根据动量定理,N车对离子的作用力为 ,以初速度方向为正········································(2分)······························································(2分) '=2F··································································(1分)(3)正离子在磁场中做匀速圆周运动,洛伦兹力提供向心力,轨道半径 R = 2r3··························································· (2分)·························································(1分)粒子扫过的面积如图中阴影部分所示N车中匀强磁场区域垂直投影到纸面内的面积至少为··································································· (3分)4 展开更多...... 收起↑ 资源列表 山西省太原市2025年高三年级模拟考试(二)物理.pdf 山西省太原市2025年高三年级模拟考试(二)物理答案.pdf