?@:A ( BC: 、 D: 、 =E:F ),A GHI ; =J KL9=:;!

2020年普通高等学校招生全国统一考试高考仿真模拟信息卷&押题卷(全国一卷)理综(1-6套)(PDF版含答案)

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2020年普通高等学校招生全国统一考试高考仿真模拟信息卷&押题卷(全国一卷)理综(1-6套)(PDF版含答案)

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!"

#
1 
$

2020
!"#$%&'()*+,-./
%&'()*+,-

./-
!"#$%&
!"
7.【
01
】C

23

456789!":;!<=:>?@:A

BC:

D:

=E:F
),A
GHI

=J
KL9=:;!,B
GHI

MNOPJ89!":;!QC:
,C
GRS

TU=:;!
<5V:

9CWOXY

Z[
,D
GHI

8.【
01
】D

23

\]O!8^_CA
,?
abcd2ef
,A
GHI
;HF
g
SiO2efc<SiF4>H2O,h
ijklm
,HF
nop
,B
GHI

qrpsatu!l

:u!
HI,C
GHI

vpwntxo
py

K2c
{|}zu!w~\bcK2ef
,D
GRS

9.【
01
】D

23

?!?K2??zu!???

??U7?K?

????Q
Fe3++3H2 幑幐O Fe(OH)3
+3H+,A
GRS

?!?sau!l

:?u!?

Ui???=????\

????Q
2Fe3+ ???+Cu 2Fe2++Cu2+,BGRS;?!?g???~\bc?K2ef,????QFe3+
+3HCO ???3 Fe(OH)3↓+3CO2↑,CGRS;?!??KSCN~\???,?nc
GHI

10.【
01
】A

23
】n(Al)=2mol,Al3++3e???- Al,c<2mol?8;?6mol=?,AGRS;¤?;!
<
1mol
¤?§¨?8
C—H
???
6mol,B
GHI

????°
,SO3±??,CGHI;1
?

2He??? 1? ?,n(

2He)=3mol,3mol

2He?3mol?,DGHI。
11.【
01
】D

23

?[?·°
,NO2±???,Na2O2gKefcO2,??,RQ???,XQ
u??
,Y
Qw??
,Z
Q???

????
:Cl->N3->O2->Na!,A
GHI
;H2O? NH3?
?
,B
GHI
;HClO
nop
,C
GHI
;Na2O、Na3N?n??!??,}????°:?=,DG
RS

12.【
01
】B

23

?=?ef?

?=??

???K

=2m~\q???
,A
GRS

zu!wnt
x

zu!?~izu!w~\

?Uzu!w~\??]K

=?ef?Q
3MnO2+Al+H2O
???+NaOH 3MnO(OH)+NaAlO2,BGHI;R?×?u!?bc??ef,CGRS;;?
1mol
=?8??×??
1molMnO2,;?0.3mol=?,??×??MnO2?mAQ0.3mol×
87g·mol-1=26.1g,D
GRS

13.【
01
】C
!"

#
2 
$


23

????op=????>=????
,E
Q
HC2O

4,FQH2C2O4,GQC2O
2-
4 ,AGH
I
;E
?à

á
HC2O

4q???8~\±pl,?? HC2O

4?=??iK2,BGHI;a?
~\±pl

a
c(OH-)<c(H!),
??=??è?
c(Na!)+c(H!)=c(OH-)+c(HC2O

4)+
2c(C2O
2-
4 ),é?:c(Na!)<c(HC2O

4)+2c(C2O
2-
4 ),CGRS;Ka2=
c(H+)·c(C2O
2-
4 )
c(HC2O

4)

10-4.19=100.81×10-5,
?
,1<100.81<10,
ê??AìQ
10-5,D
GHI

26.【
01
】(1)-1(2
d

(2)Li2CO3+2H ???! 2Li! +CO2↑+H2O(3d)
(3)
í?
LiCl
K2
(3
d

(4)2Cl--2e???- Cl2↑(3d)
(5)1?1(3
d


23
】(1)
?z??zQ?!??
。(2)
vp?òóvp?

?~iK
。(3)
?!??K2

÷?!???K2

}?!zOùú??!?~\ü??K?!?
。(4)
=2?!?

?
?×???!u!c。(5)
?z??gKef???Q
LiAlH4+2H2 ???O LiAlO2+
4H2↑,u!"?g??"??nH2,#$?m?A%?Q1?1。
27.【
01
】(1)
&'O·

(rp)T°*
(3
d

(2)
[?+
(2
d

(3)SO2+2OH ???
- SO23
-+H2O(3d)
(4)
,-"./0

?12

34".gWO567!u!F??01
(3
d

(5)S2O
2-
4 +3Br2+4H2 ???O 2SO
2-
4 +6Br
-+8H!(3
d


23
】(1)
8?9

:;d\<=>J>

(?·t?F
。(2)
?ef@A?

BCD?[?

E[?+
。(3)SO2gzu!wefcIJ?Kb

:?Frpw?!
O2u!F,??LMYIJNO?P?。(5)Q???"?Q
Br-,
G/H
,S2O
2-
4 !u!<SO
2-
4 。
28.【
01
】(1)+378(3
d

(2)
[?%i
T0℃8,R!?0STl(UR!?VWlZX)F??01(3d)
(3)①?i(1d) ②80%(3d) ③17.28(3d)
(4)
?
(2
d


23
】(1)
??YZ?[?
,① ×2-② -③ ×32ü:2CH4(g幑幐) C2H2(g)+3H2(g) ΔH=
+378kJ·mol-1。
(2)“
\]8^_¤?;!`

ab×ec?n!"efd`

efgefd`h?d3i/


?

?

j%[?

efd`??
;B
?8efd`kN,?

feR!?l?m?h

R!
??an?T![?

[??%

R!?0STl

UVWlZX
),
?oefd`p,

(3)
eq

rY

ef}è[ès@A°tu

·tgO??m?A
           2CH4(g幑幐) C2H2(g)+3H2(g)
wx??m?A
(mol):  2      0    0
!"

#
3 
$

;!??m?A
(mol):  2x       x    3x
&'??m?A
(mol): (2-2x)    x    3x
y[ys@A°

O?z·tgO?z?m?A
2-2x+x+3x=3.6,

:x=0.8mol。
①M?8,ef{R?{tu,Refd`?i|efd`。
②10min8}?&',¤??&';!`Q0.8mol×22mol ×100%=80%。
③&'8,c(CH4)=0.2mol·L
-1,c(C2H2)=0.4mol·L
-1,c(H2)=1.2mol·L
-1,K=
c(C2H2)·c
3(H2)
c2(CH4)
=1.2
3×0.4
0.22
mol2·L-2=17.28mol2·L-2。
(4)
¤?P~=?

¤?}??bcu!ef

¤?}????

35.【
01
】(1)1s22s22p63s23p63d74s2(
U
[Ar]3d74s2)(2
d

(2)c(1
d

(3)P(1
d
) 
??

?
3p
:ì×}??????
,P
?#n=?:?i
S;P
??????i
??]iy??
(2
d

(4)sp2(1
d
) 
&??l?
(1
d
) SO3(1d)
(5)>(1
d
) [Co(H2O)6]
3+
R=????

?=?^????
(2
d

(6)
??????
(A3?)(1d) 
101×6×1030
槡3
4a
2c×6×NA
(2
d


23
】(1)
?n
27
???

(2)H2Od??}?l?、σ?,z??n!"?。
(3)
y?????#n=?:g????a?

y?????#n=?:g????

??=
???a?

á??????=???}????

???>?W8

#n=?:?i???
?

(4)PO-3P??a 3? =??,?
¤!

W^
??Q&??l?

g
SO3、CO


-、NO-3F?QF=??。
(5)
??d?:?§

¨????R=????

??????

?

=?^????

d?
:??

(6)
Bq??Q???

????Q??????

?°??q±?

???????R?l??
<

R?l??%
(h)
Q
槡3
2a,??R?l????(S)=
槡3
4a
2。
n???
,12?
???]i
??
、2
????]i?¨
、3
????]i?_

??
,1
????

????
。ρ(Ru)=
101×6×1030
槡3
4a
2c×6×NA
g·cm-3。
36.【
01
】(1)
??

·?
(2
d
) C12H16O3(2d)
(2)?
?ef
(1
d

!"

#
4 
$

(3)a、c(2
d

(4) 帨

?師2
CH2CH2
?
OH
OCH2C6H
?

+(CH3)2SO4 →? 帨

?師+2NaH 2
CH2CH2OCH
?

OCH2C6H
?

+Na2SO4+2H2↑(2d)
(5)
??p

U
HNO3)(2d)
(6)15(2
d

師 師
?
師? ?  HO C
CH
?

CH
?

?OH(2d)

23
】(1)
?????u?:?Q·?

??

?H

??????

a5d???

??
??

??

??

???<
4?
???

??

??d??Q
2? 、3?
?

??
4?
?Uz?
?

N?

?dò+?
C、H、O
????
。(2)C→Dbc??ef,?"?Q?!z。(3)C?
?·?

:gQbc??

gpl%?p?~\bcu!ef

??pl?
H2CO3o,?:g
vpzwef
。(4)
z!w?g·?efczO

?wg
(CH3)2SO4(rp¤?)bc
??efc。(5)
???p?~\%×

U?p>?A?x
。(6)
G/H
,G
d??
2?
·?

?n?·?g?§?5?:

?n????

?:a

???
:1 OH、
?

OH、
?

OH、?
OH

、?
OH
5,???@A?yd???a15?,?%????
?}?E?àzá×a

??

!"

#
5 
$

!#
7.【
01
】A

23

????????N????A?dè?

é
??

ìí

?ín
cT???????ê???m
,A
GRS

?Cef?Y?A?C

?U??ònó?hl
??o????h
,B
GHI

{|?n%d?!??
,C
GHI

???÷?n???;???
ef?ü?a5?<ù~
,D
GHI

8.【
01
】C

23

ú/&?a5???glm

H}&?é?:?>W^ü?:?

ê???:????
?y

ê?%^?ny??
,A
GHI

ê?????

??:bcK2ef
,B
GHI

·?

!
??:gwefc<
H2,F?m?A?"#?p?T#z???%?Q4?3,??,"c H2?
mA%?Q
4?3,C
GRS

d$p?d??Q
C10H10O6,DGHI。
9.【
01
】B

23

%A
pH
8?:U&'?
pH
()
,A
GHI

?tp?*op?+[?

GRS

(
Br2
?
CCl4~\,???a?->.c<,/?n?n??,CGHI;?Cefa0,-A?
KClO3n?}?C?×??,DGHI。
10.【
01
】C

23

?gKúO}%[°?ef
:3Fe+4H2O(g)???
%[
Fe3O4+4H2,?hi12ef,}3e
f
3mol
?0S
8mol
=?
,A
GHI

?i
NH4Cl~\4???bcK2,?~\4?
???5?i
0.1NA,BGHI;?[?·°,17g¤?(—
14CH3)n1mol,?????8NA,

GRS
;Fe(OH)3?6n??Fe(OH)3?7??,??6?5?i0.5NA,DGHI。
11.【
01
】D

23

ú/&?=2m~\>~\??q?????

H}&?8?:?>9q:?

?
°q±?
,b<7,
??~\±pl

?
NaHA
?=????iK2??
,A
GHI
;F
??±
NaHA
>
NaOH
~\:;??efc<
Na2A,ê?K2:??NaHAt,?tiE?(?f?~
mn
NaHA
>
Na2A),G??f?~mnNa2A>NaOH,H??f?~mnH2A>NaCl,K?
?f?~mn
NaCl、HCl
>
H2A,?G、H、K??f?~\í?K?=?,F??f?~\K
=?????
,B
GHI
;E
??f?~\?}=??è?
:c(Na!)+c(H!)=c(OH")+
c(HA")+2c(A2"),E
?~\±l

?
c(H!)=c(OH")
ü
:c(Na!)=c(HA")+2c(A2"),C
G
HI
;F
??f?~mn
Na2A,??q??????Qc(Na!)>c(A
2-)>c(OH")>c(HA")>
c(H+),D
GRS

12.【
01
】C

23

"?<=?>TU?=???

?h?

??T#
,R
7??

@?7R?
,A
GRS
;R
??n??T#??

AF
,B
GRS

}oxlBK?Cbc^u??
,C
GHI

u??
?R?×bc??ef
,D
GRS

13.【
01
】B
!"

#
6 
$


23

?éCY
X、Y、Z、W
d?Qu

?

r

?
。S2-、Cl-
=?????y
,O2-、Al3+
=??
???y??
S2-、Cl-
-n?=??

????
:r(S2-)>r(Cl-)>r(O2-)>r(Al3+),A
GH
I
;Y
?u!?
Al2O3:gzu!w~\efcK,?:g?rpefc?gK
,B
GRS

?
H2SO3Qop? CGHI;Z?O?z!? H2S???l? W?O?z
!?
HCl
o
,D
GHI

26.【
01
】(1)H2SO4(2d) ????gWO?56?,?2efd`,E%?~TU`(2d)
(2)2MoS2+7O2???
%[
2MoO3+4SO2(3d)
(3)3?3?2(2
d

(4)
[?j%

]OKb?2

ef?q?ZX

3efn?Cef

j%[?

3&'{F?G
(3
d

(5)c(Ca2!)≥a×105mol·L-1(2d)

23

ú/&??5!6ù?

HIu!??ef

!"efd`

~??+?F

H}&?J
?:?

(1)SO2K?!、R!u!、 _??*rp。LMNO?????gWO56??,?2ef。
(2)
?r!P}WOQJc
SO2。
(3)
U=??è2dRC

STUü
1molMo,
BC
6mol
=?

??-BC
3molH2、3molCO、
2molAl。
(4)
/5E±??u!Pg]Kefn?Cef

?u!Pg]Kef??}?n?V?

e
]KKb

efV?#???2W[?j%?PXY`?fg

(5)
TU~??+?YY??q?Z[
。c(Ca2!)≥
Ksp(CaMoO4)
c(MoO2-4 )

27.【
01
】(1)
??qzu!w~\

?C

U&'???O\()]0c
()?^?
(2
d

(2)①2KClO3
R!?
????

2KCl+3O2↑(U2KMnO4???

K2MnO4+MnO2+O2↑)(2d)
②2MnO4" +5SO2+2H2 ???O 2Mn
2++5SO4

" +4H!(3
d

③X_??`?,/?,?;Y?ab(2d)
(3)
*???n*8~\?^?:;?Q????dc?de
(2
d

16c1V1-8c2V2
5w (2d)
(4)
DX
(2
d


23
】(1)
]04???

f7C?n??qzu!w~\

?C

U&'???O\()]
0

g?n????^?

(2)①hi(U?1uO,Anbcj1,k±:?:U?uK?uO。②U?Krp?]0H2O,

j1Ui]0
SO2,Ej1UilSSO2,Fj1UiS?SO2nmln,hQSO2o?pCO2
?]0
。E
efQ
2KMnO4+5SO2+2H2 ???O K2SO4+2MnSO4+2H2SO4。③eqrj1
!"

#
7 
$

r
,X
j1(?

?A
”,
êa??7U

]0
SO2、lSSO2、SsSO2ln,a0g?nt?~
\?`
———
]0ulS
SO2,?,?———??SO2vln?。
(3)
Ur?rpw~\*??A?
I2,U?L~\7w±?。*?×x(?L~\?^?,á
x????8^????
。SO2+I2+2H2 ???O 2HI+H2SO4,a:2n(SO2)+n(Na2S2O3)=
2n(I2),ω(S)=
2c1V1-c2V2
1000 mol×32g· mol
-1
wg ×

2×100%=
16c1V1-8c2V2
5w %。
(4)
u!

8
,O2?A,?A?uOy}SO2O?,UzC?LlSO2。B??lSuO,}
K~\obcef
:2SO2+O2+2H2 ???O 2H2SO4,??%üV2D?,%üS??mAd?D
X

28.【
01
】(1)CO2(g)+3H2(g???) CH3OH(l)+H2O(l) ΔH=-93.8kJ·mol
-1(3
d

(2)①?C (2d)
②0.17mol·L-1·min-1(3d) 0.50mol·L-1(3d)
(3)2a27(3d)

23
】(1)
??
CO(g)
>
H2(g)?PJC(ΔH),?{C!"???:(Ⅰ)CO(g)+

2O2(g ???)
CO2(g) ΔH=-283.0kJ·mol
-1;(Ⅱ)H2(g)+

2O2(g???) H2O(l) ΔH=-285.8kJ·mol
-1;
?
?q|?à?!?}YC!"???
(Ⅲ):CO(g)+2H2(g ???) CH3OH(g) ΔH= -(510
-419)kJ·mol-1=-91kJ·mol-1。
??YZ?[

TU
(Ⅱ)+(Ⅲ)-(Ⅰ),?ü~?C!
"???
:CO2(g)+3H2(g???) CH3OH(l)+H2O(l) ΔH=-93.8kJ·mol
-1。
(2)①650℃8,????tua?????:
      CO(g)+H2O(g幑幐) CO2(g)+H2(g)
wx
/mol    4    2     0    0
;!
/mol 1.6 1.6 1.6 1.6
&'
/mol 2.4 0.4 1.6 1.6
?
650℃
8
,CO
;!`Q
1.6÷4=0.4>13,?[??%,;!`?X,?RefQ?Cef。
②900℃8,??CO?;!`,????tua?????:
      CO(g)+H2O(g幑幐) CO2(g)+H2(g)
wx
/mol 3 2 0 0
;!
/mol 1 1 1 1
&'
/mol 2 1 1 1
v(H2O)=1mol/(2L×3min)≈0.17mol·L
-1·min-1,c(H2)=1mol/2L=0.50mol·L
-1。
(3)
bc
2H2S(g幑幐) 2H2(g)+S2(g)ef,?q|??,[?QT4℃8,H2S&';!`Q40%,?
???
H2S??m?AQ0.20mol×40%=0.08mol,??H2S??m?AQ0.20mol-0.08mol=
!"

#
8 
$

0.12mol,
c<
H2??m?AQ0.08mol,c<S2??m?AQ0.04mol,÷p(H2S)=

2MPa,p(H2)
=a3MPa,p(S2)=

6MPa,?&'??Kp=(

3MPa)
2×a6MPa/(

2MPa)
2=2a27MPa。
35.【
01
】(1)33(1
d
) B(1
d

(2)As>Se>Ge(2
d

(3)PH3?AsH3???d?mA?,Z???7Uo,???:PH3<AsH3;NH3d?%^?}z
?

???
:NH3>AsH3(2d)
(4)①&??l?(1d) BF3、SO3(2d,?@??01??)
②H3AsO4(1d) H3AsO4??·?u?5??,¨ As??????%,?·?u?^?:
??t

·?z?s?=?Y?
(2
d

(5)InAs(1
d
) 7.6×10
32
a3NA
(2
d


23
】(1)As
Q#
33
???

n#
VA
??

??????=??a?W^?G??a
33
?

??=????Q
4s24p3。A
G???:A?X??
,C
G????j+÷
,D
G????T
??

?a

GRS

(2)As
?#n=?:?%??hn
As
?
4p
???i???????

??=???vK}?
???:ì?n???????

??0=?????

(3)NH3d?%^?}z?,?NH3???%,AsH3???d?mA?i PH3???d?mA,
d?^7U???

???%i
PH3。
(4)①AsO-3 ?¨???Usp

¤!

W^??Q&??l?

??F=????§??
BF3、
SO3?nAsO

3 ?F=??。
②H3AsO4??·?u?5??,¨As??????%,?·?u?^?:??t,·?z?
s?=?Y?

(5)
???>???????a
4? In
??>
4? As
??

?3!???!"?Q
InAs;
1?
???mA
m=760/NA g,1?????? V=a
3×10-30cm3,
?????
=m/V=
7.6×1032
a3NA

36.【
01
】(1)
q
HNO3、qH2SO4、?C(2d) ??ef(1d)
(2帨

?師)
COOH
NO2
(1
d
) 
!?

??
(2
d

(3)
!
"#
$
%#
%
&
"#
#
$
"
!
"
"#
%
&"#
'
&#
$
%
(2
d

!"

#
9 
$

(4)13(2
d
師 師
?
師) ?HCOO NO? 2 (2d)
(5)
!"
#
!"
$%&'
(
'"
'
"!)
*+
,"
-
,'
-
,"
'
!
.%*
/'!)
-
,
!)
!
(3
d


23
】(1)
?
A(
¤?
)→B(???¤?),?BC?(?nqHNO3>qrp?yp,@An?
C

?
D→E???q?,??rYbc?n?§×???ef。(2)? B???q


?師
?
CH
?

NO2

??ef@A??}pl%?p?~\

?§×?¤?bcu!efc??¤p

?

???q 帨

?師?Q
COOH
NO2

??a??:?Q??>!?
。(3)
?

>

?? ? q ?

? ?

? d ? ?

? ? } Y
E→ G e f ? ! " ? ? ?:
!
"#
$
%#
%
&
"#
#
$
"
!
"
"#
%
&"#
'
&#
$
%
。(4)
??§:a
HCOO—
>
—NO2#?
???

?a

???

?
、 、
?
);
??§×:a
—CHO、—NO2>—OH,???a10?,?a
13
?

??E?àzáa

??????Q
1?2?2
?a5???q
師 師
?

?Q
?HCOO NO? 2 。(5)9¤?UplKMnO4u!?$ b c ? 帨

?師? e f c < ?C
??

? 帨

?師?NH ,3 ? m ? g SOCl2e f ü ? "


?師
?
?C

?

? 帨

?師?N 。
!"

#
10 
$

!$
7.【
01
】B

23

?[°vpY?:d2"c
CO2,BGHI。
8.【
01
】D

23

!??>zOef
,A
GHI

a5??d??Q
C14H20O2,BGHI;? a??O??
?

?:+???
,C
GHI

?§×?????a

?
,D
GRS

9.【
01
】C

23

[??X

??d?^?Koc,A
GRS

?*??

]0
SO2、l SO2、Ss SO2
ln

?*?Q??

?95?f??9tO

??9YO
,B
GRS

j1ⅡUilSSO2,B?
2
o????
,C
GHI

?Q??~i??!v

??Uú?f7d?E
?".
,D
GRS

10.【
01
】C

23

~\????S

?~\?z??????>+?
,A
GHI

??°
22.4L
?O?
?m?AQ
1mol,
7?O>?ef??Q
-1
?

?
1mol
?Oef?;?
2NA?=?,BGH
I

uO>?u??u???<

?
32g
uO>
32g
?u?a?u????m?A?Q
2mol,?
?Q
2NA,CGRS;28g????m?AQ1mol,71???d??1?vv?
?

?
1mol
???vv???Q
NA,DGHI。
11.【
01
】C

23

???f?~\??}
:H+、OH-、NH+4、Cl
-,A
GRS
;c(H+)=c(OH-)+c(NH3·H2O)
Q
NH4Cl~\?m??è,BGRS;?>??N?>P?fgK=????,CGHI;M?~
\
c(NH4Cl)=c(HCl),?????>????è,DGRS。
12.【
01
】B

23

?j1q?

??QR?

=?ef?Q
O2+4e
-+2H2 ???O 4OH
-,
??Q??

??
ef?Q
2VB2-22e
-+22OH ???- V2O5+2B2O3+11H2O,??ef??OH
-,OH-
??2?
F?{????
,A
GHI
;B
GRS

??c<
OH-,
??BCn?8^

???¤=2m~
\
pH
??
,C
GHI
;?
aw??Onm?i

????
”,
?:??????
22.4L· mol-1
+?
,D
GHI

13.【
01
】B

23
】X
>

????????=??n??????

??

Q#??????a
4?
=
?

?Qv??
,M
Q#??????a
6?
=?

Qr??
,Y、Z、N
?%?u!??f?K!
?##%^:??ef

??Qw

?>???
。X、Y、Z、M、N
d?Q
C、Na、Al、S、Cl。
??h
l?o?t?)§n
X、M、N,A
GHI
;?
??????=??d?Q
4、1、3、6、7,
??)§Q
Y、Z、X、M、N,B
GRS
;AlCl3h??!??,?????=,CGHI;\mw???Xi\m
????
,D
GHI

26.【
01
】(1)FeTiO3+2H2SO4???

TiOSO4+FeSO4+2H2O(2d)
(2)Fe(1
d
) 
úbq?

????

??
(2
d

(3)
?K?Wef?
(1
d
) 
?x>c
?CF
(1
d

(4)TiO2+4e???
- Ti+2O2-(2
d
) 4480(1
d

(5)Fe2++2HCO-???3 FeCO3↓+CO2↑+H2O(2d) 1.013×10
-5(2
d


23
】(1)
h??N?CFeTiO3,??\1????TiO
2+
???}

????Cef!"
???Q
FeTiO3+2H2SO4???

TiOSO4+FeSO4+2H2O。(2)3ù??a?"? FeSO4·7H2O,
?B9~X"??
Fe3+
lS

?m

Q
Fe,“
n?{f7

??úbq?

????

??

(3)“
K2

efQ
TiO2++(x+1)H2 ???O TiO2·xH2O↓ +2H
+,
??&'?G??

QE%
TiO2·xH2O?"`???K?Wef?、?x>cef
:TiO2+4e???
- Ti+2O2-,
??ef
:2O2--4e???- O2↑,??ü?hTi9.60g,÷n(Ti)
=n(O2)=0.2mol,V(O2)=4480mL(????°)。(5)?/H?3ef!"???QFe
2+ +
2HCO-???3 FeCO3↓ +CO2↑ +H2O;??[° FeCO3->~\q?Q 4.5×10
-6mol·L-1,
!"

#
11 
$

Ksp(FeCO3)=2.025×10
-11mol2·L-2,
÷
c(CO2-3 )=
2.025×10-11
2×10-6
=1.013×10-5mol·L-1。
27.【
01
】(1)?
°
(1
d

(2)
efrp?A

}q???

?rp±??q

qrp?^Kl(
CuSO4·5H2O0K
?<
CuSO4(2d)
(3)2Cu2++2NH3·H2O+SO
2-???4 Cu2(OH)2SO4↓+2NH

4(3d)
(4)
rp?]????s??Cd2
(2
d

(5)
&'O·
,?
??·>?^
(2
d
) 
(0.5V1-0.5V2)×10
-3×17
w (3d)
(6)BD(2
d


23
】(1)
?J?mn?}?°tu
。(2)
9?ü?
CuSO4~\???núb??Cq?
?a??Yg

??3Y????a??L?

3??L?Q
CuSO4,?hnefrp?
A

}q???

?rp±??q

qrp?^Kl(
CuSO4·5H2O0K?<CuSO4。(3)?
f7ù???

rp?~\>?A]Kefc<
Cu2(OH)2SO4??,??}Y?????。
(4)
rp?4??????*??

??????ZXrp?]?????~2?

aTi
??3Y
。(5)
á

>·???8

??9\?×j

(

>·???

??*?US?
zu!w??m?A??+?Yg]ef?yp??m?A

t7+?"c?]O??m?
A

? + ? Y
NH3 ? m A ? d ?。(6)G ? ? .  ] ? m A d ? ? } ?
(0.5V1-0.5V2)×10
-3×17
w ,?f7?wV2D?,÷(]?A%???D%,??d3。
28.【
01
】(1)②(1d) CO(g)+2H2(g???) CH3OH(g) ΔH=-126.5kJ· mol
-1(2
d

(2)①0.02mol·L-1·min-1(2d) 25(2d) ②{F?G(1d)
(3)①200~800℃^,[?j%d`??;800~1000℃^R!?Tl(UVWl)ZX,d`,?(2
d
) ②BD(2d)
(4)
R!7U
(1
d
) ①(1d)

23
】(1)
RefT!:?

?xefd`??

efCFiR

|efT!:%?

??Ye
f①、②、③?efC,?YZ?[?,5?ef =① ×12+② ×2-③ ×

2。(2)①v(H2)=
2v(CH3OH)=
2×0.05mol·L-1
5min =0.02mol·L
-1·min-1,
&'8
,c(CH3OH)=0.05mol·L
-1,
c(CO)=0.05mol·L-1,c(H2)=0.20mol·L
-1。K=
c(CH3OH)
c(CO)·c2(H2)
= 0.05
0.05×0.22
=25。②}
(T1+100)℃8,&'??K<25,Qc=
0.3
0.1×0.22
=75>25,
ef{Ftu
。(3)①?y8^_
?"`?áiefd`

d#2W

×n

j[

efd`??

?n

j[

R!?Tl
UVWlZX

"`ZX
。②e&'?Gl?,??·t>??zOq??:E%efd`,
(&'{??G

E%
CO2?;!`。(4)? °??ef?,KwR!7U,7K?g#①?e
f

#①?ef??,D???ef?efd`。
35.【
01
】(1)4s24p4(1
d
) H2S(1d)
(2) V11.2(2d)
(3)SeO2-3 (1d)
(4)CO2(1d) ???\?????i\??\?????(2d)
(5)sp2(1
d
) ∏65(2d)
(6)槡2R×10
-3(2
d
)  M
8NA·R
3×10
30(2
d


23
】(1)
???a
34?
=?

?r?????=????é??????=????
。H2Od?
%^?}z?

??j%

u???O?z!?????§
:H2O>H2Te>H2Se>H2S。(2)CO2?
!"

#
12 
$

???Q ? ?O C O,1? CO2d?? 2? π?> 2? σ?。(3)CO
2-
3 、SeO
2-
3 、SeO
2-
4 ????
?G?Q&??l?

?l??

R????
。(4)CO2> O2n??ld?,H2O> CH3OHd
?n?ld?

?
,CO2n??l????ld?。}HCHOd?,?=??????i
???\??????i\?%^????

×$?l?
i?$
。(5)
??§QYb?

????

?s?gQbc?
G/H
,R
d??:gQbc?
??ê??} π
?

?}?π?。??é?,Rd?? 5? ????U sp2¤!,hQ sp2¤!?d?±&??
?

???a
6?
?=?

?
2?
?=?g

???<\?
,1?
?=????
1?
??

?
a
2?
?=?g
4?
v???
4?
=??àn?

??????Fi??n?
。8
??]i?????
,6
??]i????¨
,1
?

]i?
6?
??
?ê?!"?Q
Cu3SnP。ρ=

NA·(2R)
3=

8NA·R
3×
1030g·cm-3。
?g???%^?¤??Q
槡2
2a=
槡2
2×2R×10
-3
槡nm=2R×10
-3nm。
36.【
01
】(1
師 師
?
師) ?CH CHCH? 3 (2d) ?¤?(1d)
(2)b(1
d

(3)
vv??

??
(2
d
) 
?(1
d

(4
師 師
?
師) ?CHCHCOOH
?
Br
?
Br
+3NaOH
??
→?
師 師
?
師△ ? 帒C CCOONa+2NaBr+3H2O(2d)
(5)5(2
d

師 師
?
師 ?  COOCH
CH
??

師 師
?
師U ? ?HCOO CH CH? 2 (1d)
(6)
!"#
!"
#
$%%&
'
!"
!"
()*+$
%
!
(3
d


23

T

?d??Q
CnHm,÷12n+m=118,??n,m????m<2n+2,éü:n=9,m=10。?A
?d??Q
C9H10。?D?lmIv?+,,B、C、D????,???B???
師Q ? ?CH CHCHO,é? CQ CH3CHO。A
師 師
?
師n ?CH CHCH? 3,G?é?,E
師 師
?

Q
? ?CH CHCOOH,F
師 師
?
師Q ?CHCHCOOH
?
Br
?
Br
,G
師 師
?
師Q ? 帒C CCOOH。(5)G/
H
,X
?
HCOO—,
vv??

×?

??§×?n????

÷???a#?
: ?HCOOCH CH—,
—C(OOCH?) CH2,a#?yd???;??§×a 2? ???,? ??Q—OOCH,— ?CH CH2,
??a

?
。5
?????C??§×z????

??@Aa
師 師
?
師: ?COOCH
CH
??

師 師
?

U
? ?HCOO CH CH? 2 。(6)G/H,5?"?Q§,hi?*?.。2-??g???
<

?S

?<<§

!"

#
13 
$

!%
7.【
01
】B

23

????WO?uO

aó?
?WO???6??K?°

àá?WO?
~
,A
GHI

?xy???n
KI
U
KIO3,BGRS;vB??Ui??B×?{???A,
??8?Uê^_è}K?×??{

?;?é·

9vB?_??{tuê_

????~?
mc<

bc???!
,C
GHI

%d?n??d?mA}?ìU?íì?d?

??p?hi
%d?

{|?hi%d?
,D
GHI

8.【
01
】C

23

??n->n??

???n->???

???:??5?y

?ny??
,A
GHI

§¨?d??a
4?
->v??

??.?????d??av????:?&?
,B
GH
I

d??Q
C5H10O2??a:¤p??(4?)、?p??(2?)、?p??(1d)、?p¤?(2
?
),
?

?
,C
GRS

?§¨??????a

?
,D
GHI

9.【
01
】A

23

?K?u!x??

?g?????l
:I->Fe2+,A
GRS

c
?ypQ?
up

?:????hl
,B
GHI

?[°
Fe
?q?pbc?!

?g??:???hl
,C
G
HI

??q?ò?

?:??
Ksp??,DGHI。
10.【
01
】B

23
】10.6gNa2CO3n0.1mol,/CO
2-
3 K2nóo?,?K2Y? OH

??-i
0.1NA,A
GHI
;22.4L(
????
)NH3n1mol,?a?m?n10mol,m??Q10NA,BGRS;90g
?p

??p

n
1mol,HOOC—COOH
?a#?!?

??a!??Q
2NA,CGHI;C2H5OH
g
CH3COOH}qrp、?C°?efn?|?,?1molC2H5OHg CH3COOH}qrp、?
C°efü??
NA?CH3COOC2H5d?,DGHI。
11.【
01
】B

23

?/?
,NH4HCO3~\?xl,??vpz???K2???i4???,÷
Kb(NH3·H2O)>Ka1(H2CO3),AGRS;pH=6.5?~\c(H2CO3)=c(HCO

3),±**?
zu!w~\8
,c(HCO-3)?±???,ápH?i7.8??~\pH??,4???q?±?
,?

7vpz???÷?x,?
,B
GHI

~\?}?~?è
:c(NH+4)+c(NH3·H2O)
=c(HCO-3)+c(CO
2-
3 )+c(H2CO3),CGRS;??q|??,~\? pH=98,~\6?
q???
:c(HCO-3)>c(NH

4)>c(NH3·H2O)>c(CO
2-
3 ),DGRS。
12.【
01
】B

23

9!":;!Q=:?j1Q?=?

3j1n?z=?

hi?=?
,A
GRS

?6
7??q??

F?~\Qxl

??~\Qpl

?????2??ù?F??xl~\>
???pl~\bc>ef
,B
GHI

?67??q??

F?^??

×zO0=?g
zu???c
bc?u!efQ??

?=?ef?Q
H2-2e
-+2OH ???- 2H2O,CG
RS

R?=?efn
2H++2e???- H2,ü?zef??????Q H
++OH-

???

H2O,D
GRS

13.【
01
】B

23

G/H

q

?±]d?

ú?l?mn??p

??

Q???
,Z
Q???
。X
>

?\m?
?K~\?g
CO2ef,"c??,?"c????~i
?A?
CO2?K~\,÷XQw??,Y?:Q???U???。Y?:]i#???#ⅣA
?
,A
GHI

????
:Na>Si(Al)>Cl,B
GRS
;AlCl3、SiCl4n??!??,CGHI;
HNO2、HClO?nop,?no=2m,DGHI。
26.【
01
】(1)
??56??

?2XYd`

E%?~TU`
(2
d

(2)
34??!??3Y
(1
d

(3)①>p,(Fe3+?ü;!QFe(OH)3(2d)
!"

#
14 
$

②MnO2+2Fe
2++4H ???+ Mn2++2Fe3++2H2O(2d) 3(2d)
③¤(2d)
(4)70℃(1
d

(5)?
??n?NO\i(9

*??pp!

?*?
AgNO3~\,??????c<,÷N
O??

?a????c<

÷òNO??
(2
d


23
】(1)
????g\??56??

?2efd`

E%?~TU`
。(2)
?CX??3
4aU?~m3Y

?f7Uü??!??~\

?5?n34??!??3Y
,?
???!
??/0
。(3)①MnCO3+2H ???
+ Mn2++CO2↑+H2O,?t?????K2c②?u!?sau!l,}pl?m:u!F???。c(OH-)=
3Ksp[Fe(OH)3]
c(Fe3+槡 )
=1.0×
10-11mol·L-1,c(H+)=1.0×10-3mol·L-1,pH=3。③?1¤f7q!,???~¤m。?
1?BC%?
pH,
f7?e¤???4y¤m
。(4)?
°q|

VWXY`?%??:?X?
@AQ?"@A
,70~90℃
%^XY`5¤
,70℃
8#:

<úX
。(5)
vp???^?a?
??

vp???F

]0???nm?}

?RCvp?nmNO??

27.【
01
】(1)
??$
(1
d
) 100mL
sA>
(1
d

(2)
??a0①?ü??,*??rp(U?ypF)??A,? °??nm~2(2d)
(3)Cu2O+2H ???
+ Cu+Cu2++H2O(2d)
(4)Cu+(1
d
) Cu2+(1
d

(5)
"c
NO2O?,%&§'(2d)
(6)
{ef??~\;??AWO
(2
d
) 
?~\?^

÷ST(2
d


23
】(1)
a0B(?
100mL0.50mol·L-1CuSO4~\,hB???)La?**9、J+、
??$
、100mL
sA>
。(2)
#lzu!?:~itptx~\

??BC]0zu!?nm
~izu!wUrp

??a0①?ü??,*??rp(U?ypF)??A,? °??n
m~2
。(3)
??/?+,d3

u!F?>rpefc?

?????Q
Cu2O+
2H ???+ Cu+Cu2++H2O。(4),-?C?1000℃?×,.?L??ü??

??á[?}
1000℃
?×8
Cu+
??

/grpefc
??}pl~\
Cu2+
??
。(5)
?>q?pefc
%&§'
。(6)
?u!?>uO>Kefc<
?p

?{ef??~\;??AWO

efc
?u!??0

?~\?^

÷ST

28.【
01
】(1)H2S+2Fe ???
3+ 2Fe2++S↓+2H+(2d)
(2)1.5~1.9(2
d
) 
?Z[/<0?
Fe2+
a?2?u!d`1??cFe3+
?(3
d

(3)①CH4(g)+H2O(g???) CO(g)+3H2(g) ΔH=+204kJ·mol
-1(2
d

②>(2d)
③0.48(2d)
(4)CO2-3 +CO2+H2 ???O 2HCO

3(2d)

23
】(1)
?q??

??
H2S?< S,S??!??? -2??<0?,Fe
3+
!???<
Fe2+,
??=??è

??

???ef???Q
H2S+2Fe ???
3+ 2Fe2+ +S↓ +2H+。(2)?
①??Fe3+}pH=1.98?x??,o?oFe3+q?ZX,÷Fe2+>Fe3+q??oZX,d`
ZX

?
pH
f?i
1.9。
?②??,pH}1.58u!d`?2,? pH??2Z[n1.5~
1.9。
?Z[/<0?
Fe2+
a?2?u!d`1??cFe3+
?。(3)①?q??
3efQ^Cef
,ΔH=2582kJ·mol-1-2378kJ·mol-1=+204kJ·mol-1,3???C!"
???n
CH4(g)+H2O(g???) CO(g)+3H2(g) ΔH=+204kJ·mol
-1。②?q??,[?
n?

·t??

&'|{?G
,CH4???d???,÷P1>P2。
③{Y?u?,T;!?CH4??m?AQx。
!"

#
15 
$

       CH4(g)+H2O(g???) CO(g)+3H2(g)
wx
(mol)     1    1     0    0
?!
(mol) x x x 3x
&'
(mol) 1-x 1-x x 3x
??wx8y?O????n&'8?
1.4
?

O??zmA??

??gO??z?m?A

÷
(2+2x)
2 =1.4,2üx=0.4,sL?s?Q2L,÷&'8,CH4、H2O、CO、H2?q?
d?Q
0.3mol·L-1、0.3mol·L-1、0.2mol·L-1、0.6mol·L-1,
÷3ef?&'??Q
K=
c(CO)×c3(H2)
c(CH4)×c(H2O)
=0.2×0.6

0.3×0.3=0.48。(4)?q±v?^_?U?n K2CO3~\, _
CO2,÷?????nCO
2-
3 +CO2+H2 ???O 2HCO

3。
35.【
01
】(1)3d84s2(1
d

(2)>(1
d
) 
0S
2?
=??
,Mn2+
?
3d
??}??????

????
,Fe2+
?
3d
??ò
}??????
(2
d

(3)
&??l?
(1
d
) SO3、SeO3、BCl3、BF3F(1d) sp
3(1
d

(4)
3?
(1
d
) 
?4O

?

5

3??n????

????????

?????????
?

?:??
(2
d

(5)
v
(1
d
) 24(1
d

(6)
??????
(1
d
)  59×6
槡3
4(a×10
-10)2×(c×10-10)×6×NA
(2
d


23
】(1)
?n
28
???
。(2)
???j+÷jvd3

?f?h????[=????

?
?=????
)。(3)SiO2-3 ?????=???Q
4+2
2 =3,3?
¤!

ê?????Q&??l?

?U?,>éF=??

g
SiO2-3 ?QF=???a SO3、SeO3、
BF3、BCl3F。??òó?.,????Usp

¤!
。(4)
?4O

?

5>3??n????

?
??g????:a?
。(5)CN"


?=?l?i
N,N
?????=??^???

?

?

E6?=??

(]??nσ?。1? NH3d?? 3? σ?,1? NH3:gNi
2+
?<
1?
(]?
。1mol[Co(NH3)6]
3+
?σ?:(3+1)mol×6=24mol。(6)Bq??Q???,????
Q??????

?°??q±?

???????R?l??<

R?l??%
(h)
Q
槡3
2a,??R
?l????
(S)=槡34a
2。
}???
,12? Co
??]i??
、2? Co
??]i?¨
、3? Co
??
]i?_

??
,1?
????
6? Co
??
。ρ(Co)= 59×6
槡3
4(a×10
-10)2×(c×10-10)×6×NA
g·cm-3。
36.【
01
】(1)2,4-
?????
(1
d
) 
??

??
(2
d

(2)
!"
#
$%
&
!%
!%
'
(2
d
) 
??ef
(1
d

(3帨

?師)
?
Cl
+2HNO3
q
H2SO4
→???? 帨

?師

NO
?

?
Cl
NO2
+2H2O(2d)
!"

#
16 
$

(4)10(2
d
)  !"#
!##"
(2
d

(5帨

?師)
Cl2
→? 帨

?師Fe
?
Cl
H2
→??? ? ?
/Ni
?
Cl
NaOH/
?
→???? ? 帪

KMnO2/H
→????
+ ??? COOH
COOH
(3
d


23
】(1)C
?7?
Cl—
Q

?]?89

?n
2,4-
?????U?

?

?????
,H
?u?:?n
—NO2?:??、—COO—?:??。(2)C→Dn C????!¤???
?

÷efò?n??ef
。(3)B
Q??

?
B→C 帨

?師?!"??n
?
Cl
+2HNO3
q
H2SO4
→????


?師

NO
?

?
Cl
NO2
+2H2O。(4)
!
!
!
?d??n
C5H6O3,?yd??? M:bc?;ef,?
?a
—CHO,
>
NaHCO3~\ef"cO?,??a—COOH,?° C3H4,??n ?C C—CU

:×#??:?

Q
8+2=10
?

?d??a

??y!"§'?z

÷??@7?

???q?n
!"#
!##"

!"

#
17 
$

!&
7.【
01
】B

23

\,A
GHI
;PM2.5
nw6???i
2.5μm??6,2.5μm=2.5×10-6m,BG
RS

TU?n?c?

???l
,C
GHI

=>?O?u!??"c?@iWO??Ogu
O%[!?
,D
GHI

8.【
01
】D

23

?Ln??e¤?MN%d?!??
,A
GRS

???p?????q??éY?p
???q?Q
CH3CHOHCOOH,?!?:gzu!w~\ef,7?·??:gzu!w~
\ef
,B
GRS

?pd???·?>!??:bc??ef

?·?:bcu!ef

u?
?p???guObcef
,C
GRS

?ò?mn??:~i->vpw~\
,D
GHI

9.【
01
】D

23
】“H! +NO"3”:u!Fe
2+,A
GHI
;SO2:(pl%?p?~\,?,SO2?g??l,B
GHI
;Cu、Cu2O?~i??p,f93??L?~i?rp(Uyp),CGHI;vpz
4d2c<
NH3、CO2>H2O,O?;?xO3,CO2、H2O(g)!xO3^_,ü???? NH3,D
GRS

10.【
01
】D

23

=???è
,A
GHI

QK?A8

:u!F???
,B
GHI
;H2SO3nop,RS?
?????Q
HSO"3+H ???! SO2↑+H2O,CGHI;CaCO3?~2??i CaSO4?~2?,?
CaSO4??;!<CaCO3,DGRS。
11.【
01
】C

23

??d3??
:W
Q
H,Q
Q
O,X
Q
Mg,Y
Q
Si,Z
Q
Cl。
??°
HCl
QO?
,A
GH
I

yn??eF{?????±?,?

÷????
W<Y<X,B
GHI
;SiO2>SiH4?n?
?!??

d????a?l???
,C
GRS

??hl
:O>Cl>Si,
÷q\z!???l

Q>Z>Y,D
GHI

12.【
01
】C

23

??m;!?
,H2Ou??!u!,bcu!ef,F?Q??A。=B=?,a?
QR?
,A
GHI

??cCH3OH> H2O,H2SO4??m?A??,rp?q?,?,BG
HI

??×
CO2bc??efc< CH3OH,CGRS;??ef?Q2H2O-4e???" 4H! +
O2↑,c<1mol8a4molH! e?2?F?{????,DGHI。
13.【
01
】B

23

}ò?zu!w8

??~?èü
:c(HR-)+c(H2R)+c(R
2-)=0.05mol·L-1,
?
H2R?Ka1=10
-1.85,
??

??f~\
c(H2R)=c(HR
-),
/??
NaOH
~\??

?

?
??6??zq?°Z

÷

??f~\
:2c(H2R)+c(R
2-)<0.05mol·L-1,A
GHI
;d
?
?f~\
pH=8,
~\±xl
,c(OH-)>c(H+),
?
Ka2=10
-7.19,
RC}

?~\
c(R2-)=
c(HR-),
7e

?

,-*??zu!w

?
c(Na+)>c(R2-)>c(HR-)>c(OH-)>
c(H+),B
GRS
;b
??f?n
NaHR
~\
,pH=4.52,
~\±pl

??
HR-
?=????
iK2??

?K?=?ní??
,C
GHI

*?C?~\Q
Na2R~\,pH=9.85,~\?x
l

fVW}xl@A???w±?

VW?D:w±?

*?C?_??!Q???Q`?
?
,D
GHI

26.【
01
】(1)
E??ê9

U?ê9
)(1
d
) 
qrp
(2
d

(2)
??O?g\??56??

??efd`
(2
d

(3)2MnO"4+10Cl" +16H ???! 2Mn
2++5Cl2↑+8H2O(2d)
(4)d(2
d

(5)?
F?
(1
d
) 97.8℃(2
d

(6)CH3CH2OH、CH3CH2Cl>CH3CH2OCH2CH3F(2d)

23
】(1)
?*??

?1??O
,B
j->GyK
,C
jqrp
。(2)
?HE?:??O
?g\??56??

?2ef
。(3)
qypg%?p?efc
??!?

?O>
K
。(4)
U??!v^_?!z??O
。(5)
????????S?[?
。(6)
G/H

?
!"

#
18 
$

?g?!zefc
??}qrp7U°?:c
27.【
01
】(1)
??pXd`
(1
d
) Fe(OH)3、Al(OH)3(2d)
(2)3Cd4++CH3OH+H2 ???O 3Cd
2++CO2↑+6H!(2d)
(3)b(1
d

(4)5(2
d
) 
,-"./0
(2
d

(5)9(2
d

(6)73600(2
d


23

d3ù?q?

?u!??~irp

pXü?~\?
Cd4+、Fe2!、Fe3!
>
Al3+
F??

(1)
????>\??56??

:E%efd`

u!F???c
?I

?C<
dnzu!?>zu!?
。(2)
G/H

¤?!u!<
CO2,Cd
4+
!??<
Cd2+。(3)
?uK
nJ?u!?

fVW?uKu!F???
。(4)?
°?h?????
pH
?

(
Al3+
????
??X
pH
n
5。
G/H

".?~iK

?~i??

U??NO".

,-"./0
。(5)
?
?~??+?
,c(Cd4+)=
Ksp(CdCO3)
c(CO2-3 )
=1.0×10-9mol·L-1,pCd=9。(6)n[Cd(BrO3)2]=
n(Cd)=100×10
6g×28%×(1-20%)
112g·mol-1
=2.0×105mol。m[Cd(BrO3)2]=2.0×10
5mol×
368g·mol-1=73600kg。
28.【
01
】(1)+8(2
d

(2)b(2
d

(3)①b、c(2d)
②[?%iT0℃,efⅡ&'{??G???iefⅠ,?oCO2??m?A,?(2d)
(4)x+y3 ×100(2d) 
y(6-x+2y)
x(x-2y) (2d)
(5)
R
(1
d
) CO2+6e" +6H ???! CH3OH+H2O(2d)

23
】(1)ΔH1=E1-E2=57.5kJ·mol
-1-8.5kJ·mol-1=+49kJ·mol-1。ΔH2=(283+
151.5-0-393.5)kJ·mol-1=+41kJ·mol-1。ΔH1-ΔH2=+8kJ·mol
-1。(2)
efⅠ?R
efnK?ef

L?ef

??M?:R??

}?%[?°:Mbtu

?V
b。(3)①}è
s@A°

×NefO?m?nO?

??xC??
,a
GHI

O?d??????

zmA
??

O??&???d?mA,?

á??8}?&'
,b
GRS

C?
1molH—C
?y8c
<
1molH—H
?

?C?
H—H
?>?<
H—H
?d`?F

}?&'??
,c
GRS
;H2、CO2
q?%?xCFi
3,d
GHI

?V
b、c。②×N#?ef?n^Cef,efⅠ}?&'
?

j[(&'{??G
,CO2??d???;á[??} T0℃8,efⅡ&'{??G???
?

?o
CO2??d?ZX。
(4)
efⅠ:     CH3OH(g)+H2O(g幑幐) CO2(g)+3H2(g)
wx?m?A
(mol)   1     2      0    0
;!?m?A
(mol) a a a 3a
&'?m?A
(mol) 1-a 2-a a 3a
efⅡ:       CO2(g)+H2(g幑幐) CO(g)+H2O(g)
wx?m?A
(mol)   a   3a     0    2-a
;!?m?A
(mol) b b b b
&'?m?A
(mol) a-b 3a-b b 2+b-a
G/H
,b=y,3a-b=x,

:a=x+y3 。
&'8
,CH3OH;!`α(CH3OH)=
x+y
3 ×100%。
&'8
,n(CO2)=
x-2y
3 mol,n(H2)=xmol,n(CO)=ymol,n(H2O)=
6-x+2y
3 mol。
efⅡnO?d???F?ef,T??Q1L(???fg&'??+?)。
!"

#
19 
$

K=
c(CO)·c(H2O)
c(CO2)·c(H2)
=y(6-x+2y)x(x-2y) 。
(5)
??m;!?
,H2Ou??!u!,bcu!ef,F?Q??A。PB=?,a?QR
?

??×
CO2bc??efc<CH3OH,???=?ef?QCO2+6e" +6H ???! CH3OH
+H2O。
35.【
01
】(1)7(1
d
) 15(1
d

(2)>(1
d
) <(1
d

(3)
?l??
(2
d
) sp3(2
d

(4)N2UCO(1d) R???(2d)
(5)
????
(1
d
) 
??
(1
d
) 
4π×10-30NAρ(r

Ga+r

As)
3(MGa+MAs)
×100%(2
d


23
】(1)
????=???Q
1s22s22p63s23p63d104s1,
??a
7?


???Q
15。(2)
Ga
>
As
]i#???

×$?=???

????????[d3

y????

???=?
???

??,?

#n=?:??
。(3)AsCl3d? As????=????Q3+
5-3×1

=4
??an??=??

????=??????RC3d??????Q?l??
,As
?
?¤!ò?Q
sp3。(4)
F=??nw??z??y

?=?z???y?ó6

??
CN-
d
3

??n
N2U CO;?9[Cu(CN
-)4]
2-
??
CN-
2Q
Cl-,
?an???

??÷
[Cu(CN-)4]
2-

CN-
?i?y?]1

?

??????W^]1??QR???
。(5)
GaAs
???Q
1238℃,
???%

???????
??Qρg·cm-3,??
??>+?
,As
???Q
8×18+6×

2=4,Ga???Q4×1=4,??????????
?
V1=(

3πr

As×4+

3πr

Ga×4)×10
-30,
?????
V2=

ρ

4×
(MGa+MAs)
NA
ρ

?
GaAs
??
 ? ? ? ? ? ? ? d ` Q
V1/V2 ×100%,9 V1、V2 ? ? + ? ü ? d ` Q
4π×10-30NAρ(r

Ga+r

As)
3(MGa+MAs)
×100%。
36.【
01
】(1)1,2-
?¤?

??¤?
)(2
d

(2帨

?師)
CH2Br
COOCH3
(2
d

(3)
?Sef
(2
d

(4)
!""#
!$
%
!$
&'
%
!"#$
"
"
!$
%
'
&$'(2
d
) 
!
!
"
(2
d

(5)BD(2
d

(6)
!
"
# $!
%
!
"
&
!"#$
$!
'
$!
"
&!
$()&
"
!
$!
*
$!&
!
%
$ $!
%
!+,
!%&$
$!
*
$!
%
+,
!%&$
$!
*
$!
$!$!
*
!%&$
$!
*
$!
*
!
*
$
!
*
$
(3
d


23
】(1)
QR.nw?a?§?vz!??
。A
?!"?Q
C8H10,??v?????? A
?an??§

???a
2?
v?????????§×?z??

?§×?????:Q
1?
??U

?¤?

???m

?§×????]1????

???q?Q
!"

#
20 
$



?師
CH3
CH3

÷

?9?Q
1,2-
?¤?

U??¤?
)。(2)
?

v?Ⅰ”??:?mDg¤?
ef

?Sn?Q??>n?z??

ug¤??v???
÷?m

????


?師Q
CH2Br
COOCH3
。(3)
???×d3
,F
n
!
!
"#
$
%
,G
n
!
!
"#
$
,F
x??g?]v
??×?z??bc?Sef?。(4)E
???q 帨

?師?Q
CH CH? 2
COOH

??

v
?Ⅱ”,E???q?avv??>!?,}n?@A°gI2ef8,CSvv??,y8#?
v??d?:5n?x??>n???

cF。
h?

?m

c
????Q
!""#
!$
%
!$
&'
%
!"#$
"
"
!$
%
'
&$'。
?????¤pg
I2}n?@A°efc< F?"?
?Sn

?efy8c
?Qyd???

?a5?"????q
?n
!
!
"

(5)
)e????:①?}V?T;?h?,B??;②???:T;?v???
:5#??y???U???
。G
?2?
z??

???@A②,
h???})e???
,A
GHI

?

c<

???

vv????

???

hi?,B
GRS

?m

?gzObc?vv??

h??
m

??:g
4molH2bc?!
!
"#
$
%

???>x?
???g
NaOH
bcef

÷
1mol
?

???g
2molNaOH
ef

7

???q??a#
???

g
NaOH
bcK2ef

h?
1mol
?

?????
2molNaOH,D
GRS

(6)
ú/?U|é>

?

v?Ⅲ”??,C ??H3
?
C CH
?

CH
?
3H3C
?ef?Q
CH3 ?CH
CHCH3。C}????U×??v7?y8?ef?

c<
CH3 ?CH CHCH3,h??B9??7Qef?,Q????;????? ? ? ; ? ? ? ? ? < ? u ! ü ?

? < ? à B q ? ±

!
"
# $!
%
!
"
&
!"#$
$!
'
$!
"
&!
$()&
"
!
$!
*
$!&
!
%
$ $!
%
!+,
!%&$
$!
*
$!
%
+,
!%&$
$!
*
$!
$!$!
*
!%&$
$!
*
$!
*
!
*
$
!
*
$

!"

#
21 
$

!'
7.【
01
】B

23

\]=!^_?ACA

\]7??????n]=!^C7?d2
,A
GHI

?vp
?V~Z2c<
CO2F,ZX§'%&,BGRS;Elu!??W?h:(X?m?l
,D
GHI

8.【
01
】C

23
】G
?!?
、(
?

·?

??
,A
GHI
;G
?:bc?Sef
,B
GHI
;FeCl3~\??]
0

?·?

g?n~\?t?
,C
GRS

?§×?
—OH、—COOH、—OOCCH3???a10?,
l

úY

?a

?
,D
GHI

9.【
01
】C

23

qrp????i??

?y?8?Y?ACA

?y?89qrp??????u
Z[
,A
GRS

j1

UiSs
SO2nmln,BGRS;???:!pl%?p?~\^_,B
j1?jJx~\
,E
j1?jpl%?p?~\

lS?O???
,C
GHI
;1,2-
?Q
??~i??!v

?Uú?f7d?#?\?a5?
,D
GRS

10.【
01
】D

23
】CN-
K2"c
HCN,
??
CN-
?\Khi???÷:??
,A
GRS

??
KCl
nQ?
?2
Ca2+,
?

\K

?A???~mQ
CaCl2,BGRS;“?Y”f???g Ca
2+
efy8
??
K+
??m

??U?

(?
X”
?:n
K2CO3,CGRS;".Q?a??K?!??,?

n?{f7

f3Qúbq?

????

??

NO

?1
,D
GHI

11.【
01
】D

23

q??y?
Na2A>NaHA~\,NaHA?K2???,~\xlo,?Y??}??à?
±
NaHA
~\??W
,A
GHI
;X
?>

??
pNa
?y

?
c(Na+)
?y

}

????A
NaOH
??
,c(Na+)
??

???:}?

?
,B
GHI
;pNa=2
8
,c(Na+)=10-2mol·L-1,
?

?
Na2A?q?Q0.5×10
-2mol·L-1,Y
?
NaHA
?q?Q
1×10-2mol·L-1,A2-
K2
??ti
HA-,
?
c(HA-)>c(A2-),C
GHI

??

??}?à
,pNa=1,pOH=5,
??
c(Na+)=10-1mol·L-1(
¤óQ
NaHA
?q?
),c(OH-)=10-5mol·L-1,
??
HA-+H2
幑幐

H2A+OH
-,
÷
HA-
?K2??
Kh=
10-5×10-5
0.1 ≈10
-9,
÷
H2A?=??? Ka1=
KW
Kh

10-5,
???AìQ
10-5,D
GRS

12.【
01
】C

23

?=?ef??

?=8?Q??

?=?

Q??

=?

QR?

R??=]%i?
?
,A
GRS

?=8
,Mg
bcu!efc<
MgF2,BGRS;?=8,=?bQ??,g=@R
??:

7
CH4P~=???WO(UO2)?n?QR?,3R?g=?b?:,CGHI;?
=8

=?

?=?ef?Q
Bi-3e" +3F???" BiF3,?;?0.3mol=???0.1molBi(?
ái
20.9gBi),D
GRS

13.【
01
】D

23

}???

tx¨Q
NaOH。
:(.?~\,??O??:n
SO2、Cl2。=2?!w
K~\c
zO>?O

?

?:n
NaClO、Na2SO3。R?O?z!?(&'??
?O\()?^?

??

Q???

]O?K~\±xl

J×?N
,X
Qu??
,Y
Qw?
?
,Z
Qr

U?

??
。Cl"(S2-)、N3-、O2-、Na!
???G?,?
,A
GHI
;H2O?C??l
?
NH3t,BGHI;?O?¤Q?O,÷?C??~\???,CGHI;NaClO、Na2SO3:K
2

?tK?=?
,D
GRS

26.【
01
】(1)1?5(2
d

(2)
?^J>
(1
d

(3)6I2+11KClO3+3H2 ???O 6KH(IO3)2+5KCl+3Cl2↑(2d) KClO3(1d)
(4)
:???O

U?O
、HNO3)gNaOH~\?56??(????,2d) ^_"c??O

U?O
、HNO3),? ?%&§'(1d)
(5)①?L~\(1d) ②97.3(2d) ③D%(2d)
!"

#
22 
$


23
】(1)?
u!?xlSWnu!vc
÷3ef?!"???Q
I2O5
???
+5CO
I2+5CO2,??u!?g?????m?A%?Q1?5。(2))LM?9?n?^J>。
(3)
?_

ef?????Q
6I2+11KClO3+3H2 ???O 6KH(IO3)2+5KCl+3Cl2↑。(4)e
`?<=

l??????^

?an?7Un:???O

U?O
、HNO3)g NaOH~\?
56??
;NaOH
~\?7Un^_"c??O

U?O
、HNO3),? ?%&§'。(5)①3*
?VW?w±?n?L~\
。②???? KIO3~3I2~6Na2S2O3?? n(Na2S2O3)=
0.1mol·L-1×0.015L=0.0015mol,
??
0.550g
xp?".
m(KIO3)=(0.0015÷6×10
×214)g=0.535g,0.535g÷0.550g×100%≈97.3%。③jNa2S2O3??~\?*?9`a
'N

????D?

?%ü".?mAd?D%

27.【
01
】(1)-122.7(2
d

(2)0.1025(2
d
) 625(2
d
) >(2
d
)  32A32A+9B(3d)
(3)
?@@A??
,CO2&';!`??~O n(H2)/n(CO2)???7??(2d) ?@@
A??
,CO2&';!`?ef[??j%7ZX(2d)

23
】(1)
??YZ?[d3

9???①CO2(g)+3H2(g幑幐) CH3OH(g)+H2O(g) ΔH1=
-49.1kJ·mol-1;②2CH3OH(g幑幐) CH3OCH3(g)+H2O(g) ΔH2=-24.5kJ·mol
-1
tu
B°+?①×2+②?üC!"???Q③2CO2(g)+6H2(g幑幐) CH3OCH3(g)+3H2O(g) 
ΔH3=-49.1×2+-24.5=-122.7kJ·mol
-1。
(2)①   2CH3OH(g幑幐) CH3OCH3(g)+H2O(g)
wx
(mol)  1.02      0     0
a?
(mol) 1.00 0.50 0.50
&'
(mol) 0.02 0.50 0.50
H2O(g)?&?efd`Q
1.02-0.2

2 =0.1025mol·L
-1·min-1;
?ef3[?°?&'??Q
K=
0.50
2 ×
0.50


0.02
2 )

=625;
??{sLd???
CH3OH(g)0.02mol、CH3OCH3(g)1.0mol,÷
Qc=
0.50+1.0
2 ×
0.50


0.02+0.02
2 )

<K,
??efR{?G

?Refd`?i|efd`
;②?????
2CH3OH(g幑幐) CH3OCH3(g)+H2O(g)+?,¤??;!` α(CH3OH)=

18×2

18×2+

32

32A
32A+9B。(3)eqd3,?@@A??,?[???!,CO2&';!`??~O n(H2)/
n(CO2)???7??;án(H2)/n(CO2)?y8,CO2&';!`?ef[??j%7ZX。
28.【
01
】(1)CuSO4(2d) Pb-2e
-+SO2-???4 PbSO4(2d)
(2)
úbq?

????
(2
d

(3)3SO2+2AuCl

4 +6H2 ???O 2Au+3SO
2-
4 +8Cl
-+12H+(2
d

(4)
U?\

~2xXI

Uu??p~2xXI
)(2
d

(5)PbSO4(s)+CO
2-
3 (aq幑幐) PbCO3(s)+SO
2-
4 (aq)(2d) 1.6×10
-6(2
d


23

b?Jò????c?a
Cu、Au(
?

>
PbSO4F¤m,dJ??h?X??ü?rp?~\

rp?~\K?úbq?

Z[??

??

NO

?1Uürp??
?
;Au(
?

>
PbSO4F¤mKvpwXN、q?pu!?,??ü??p?~\,?\?rpc

???ü?rp?

???I?Cn?

?eK~?

ü??a
AuCl-4 ?~\,
!"

#
23 
$

AuCl-4 ??!SO2??ü?Au。(1)=2Jòb?8n?Urp?~\7=2m~\;=2J
ò?b?7??obcu!ef

?\m?>T#l?
Cu
t??h?obc~2

h?b
???>?obc0=??u!ef

=?ef?Q
Pb-2e-+SO2-???4 PbSO4。(2)f7

nerp?~\Uürp???

h?3f7núbq?

????

??

NO

?1F?
_
。(3)SO2?? AuCl

4 ???>u!?????S,h?fs?é%Yu!"?n SO
2-
4 ,
??"?n
Au,
??u!??efü0=??è?EG(&

N???=??è?(&

h?
ü??ef???Q
3SO2+2AuCl

4 +6H2 ???O 2Au+3SO
2-
4 +8Cl
-+12H+。(4)
?\

n}
??rp?8?°??\

??a-A?ò3Y?rp?

h?u?×??rp?~\tug
§

aTi?dTU

h?òó???:>

f3nù?ü???n?\
2,
??\

n}?
p?~\??rpc
?~\
H+
`abce
f

h??a?A??p~\

????i??\á
(5)
;???#????~??

??rYvp??rp????~

h?jrp???v
pw

bc?n??~2;!?ef

?????C?H????

???Q
PbSO4(s)+
CO2-3 (aq幑幐) PbCO3(s)+SO
2-
4 (aq);á~\c(SO
2-
4 )=0.2mol·L
-1
8
,c(CO2-3 )=
Ksp(PbCO3)
Ksp(PbSO4)
×c(SO2-4 )=
1.46×10-13
1.82×10-8
×0.2mol·L-1=1.6×10-6mol·L-1。
35.【
01
】(1)1s22s22p63s23p5
U
[Ne]3s23p5(2
d
) 
?j
(1
d
) N>O>C(2
d

(2)CO2(1d) H2O(1d) CO2n??ld?7Kn?ld?,? CO2}K~2???,
NH3n?ld??:gKd??(3)X-
kàlk>
(1
d
) c(2
d

(4)Na2O(1d) 
2.48×1032
d3ρ
mol-1(2
d


23
】(1)
=?}yn:ì×MT?{?yn??j+÷S??

???#n=?:???
??)§Q
N>O>C。(2)H2O、CO2、NH3??d?,¨?????=???d?Q 4? 、
2? 、4? ,
?¨??¤!??ò?d?Q
sp3、sp、sp3。
Kd?n

?d?
。NH3?gKd?
^?
e7(?~2?f?
;CO2n??ld?7Kn?ld?,? CO2}K~2?
?
。(3)
RC??n???n?????m??>n
X-
kàlk>

???????%

?
???<

?a???

?in?d?????~iK

?

G??/H
。(4)
?qI????
?

#ò????5?Q
2?1,
?!"?Q
Na2O,n????a 4? “Na2O”?<ó6,??
???Q
10-30d3cm3,
???mAQ

NA
×62g,10-30d3cm3×ρg·cm-3=4NA
×62g,NA =
2.48×1032
d3ρ
mol-1。
36.【
01
】(1)
?¤?
(1
d
) 
?Sef
(1
d

(2)
vv??

!?
(1
d
) 帨

?師 
?
CH? ?O
CH
?

?C
??

?OH
(1
d

(3
師 師
?
師) ?2 C
CH
?

?
OH
?CHO +O2
R!?
→???
師 師
?
師△ ?2 C
CH
?

?
OH
?COOH(2d)
(4)
m
(1
d
) 
}??!R!u!?y8

vv???!:u!
(2
d

(5)5(2
d

師 師
?
師  CH2? CH CH? 2 (1d)
(6
師 師
?
師)
AlCl3
CH3
→?
師 師
?
師Cl CH? 3
Cl2
→?
師 師
?

Po
CH2? Cl
NaOH/H2
→????
師 師
?


CH2? OH(3d)
!"

#
24 
$


23
】(1)F
???q
師 師
?
師?Q CH2? OH,!"9?n?¤?,⑤QD}qrp、?C@A
°bc?Sefc<
E。(2)E
???
師 師
?
師Q ?C
CH
?

?COOH,?a??:?nvv??、!
?

師 師
?
師 ?D C
CH
?

?
OH
?COOH?a!?>·?,:bc??c

?師
?Q
?
CH? ?O
CH
?

?C
??

?OH
。(3
師 師
?
師) ?C
CH
?

?
OH
CH2? OHK?ef③,n·?:5?v??×a 2?
z???v??bcu!efc師 師
?
師?ü? ?C
CH
?

?
OH
?CHO,g O2}R!?、?C?@A
°e f ? ü
D,
} Y e f ④
師 師
?
師? ! " ? ? ? ?2 C
CH
?

?
OH
?CHO +O2
R!?
→???
師 師
?


?2 C
CH
?

?
OH
?COOH。(4)④、⑤#??:p?,hQ}??!R!u!?y8,vv???
:!u!
。(5)
g
師 師
?
師 ?A C
CH
?

CH? 2 sa?a?y?:??QR!???yd????a

?

?§×??:5n?¤?>n?
— ?CH CH2,a????,???n?§×:5
— ?CH CHCH3U—CH2 ?CH CH2,? 5?,??E?àzáQ???,????%?Q
1?1?2?2?2?2
???q
師 師
?
師?Q CH2? CH CH? 2 。(6)??|é??d3,??

BC?
師 師
?
師* CH2? Cl,??U¤????ef,TU?>n?¤?bc??efc<
¤?

?
師 師
?
師? < ? à Q
AlCl3
CH3
→???
師 師
?
師Cl CH? 3
Cl2
→?
師 師
?

Po
CH2? Cl
NaOH/H2
→????
師 師
?


CH2? OH。


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M__?u
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M¤s??dú9?q
:2Fe3+ ???+Cu 2Fe2++Cu2+
C.
?J???q?R
:Fe3++3HCO-???3 Fe(OH)3↓+3CO2↑
D.
?
KSCN
?q???
:Fe3++3SCN ???- Fe(SCN)3↓
10.NAw??8??[I9?。??????9w
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?d#°G?L

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LMM??j
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?q_d?s?q

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MnO2+e
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 ①BP?A?BP~A?@P?A?@P~A =1?1?1?1(2Z) ②BP
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23
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23

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23
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(1)
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01
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23

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KL

X
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16.【
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23

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23

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R1
R2
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KL

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18.【
01
】B

23

??°|??·??yF=GMm
R2
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2=

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2mv
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2B2L2
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2(1%)
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3m/s(1%)
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2m1v

1(1%)
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x1=

18m(1%)
?!ik?stlm{v3,?

v2
+Lv3
=t(1
%

??
v3=

3m/s(1%)
?k!ipq
?x2,???@?"H
μm2gx2=

2m2v

3(1%)
??
x2=

45m(1%)
??!ipqká?
30m(1%)
!"

#
4 
$

(3)
lm{

?j??t1,???U?"Hμm1gt1=m1v1(1%)
??
t1=

3s(1%)
lm{

k?

?T&Poy

?S?k?
t2=
2L
v2
+2Lv3
=3.6s(1
%

!ik?

?}???t3,???U?"Hμm2gt3=m2v3(1%)
??
t3=

15s(1%)
??jpq{

k"??t=t2+t3-t1=3.4s(2%)
33.(1)【
01
】BCD

23

uv??_6w|xyhzy{\<|}???

?_xy%5
KL

MN

t?^U<"~y

g@????HU?y?|U

KL

XY

?\??¨??y?HU

??\??|;??j
?y??G

?\??¨??

KL

XY

???
?t?drs?U

2?Y??Wà

b#????
KL

XY

%5?èk?|á?
??
?%5??W?8k
??%5???8

%5???8P?G

KL

MN

(2)
2
:(i)
??y|?p

k<¨[W
p0,?y|?p Ak<¨[W pA,????U/?
?

y|?p

k
2T0(1%)
??"~y?p??H
pAV0

2T0

p0×2V0
2T0
(2
%

??
pA=

2p0(1%)
(i)
?9y??p

y?p

Bm<_;¨?j

???y?e?à
W=pAΔV=

2p0×(2V0-V0)=

2p0V0(2%)
y??p

?jy?p

P?jy?p
C,
yΔU=k(2T0-

2T0)=

2kT0(2%)
?????#t????
,ΔU=Q-W(1%)
yrsQ=12p0V0+

2kT0(1%)
34.(1)【
01
】ABC

23

?+??

??????v


????v


KL
A、B
?XY

?
v=cn??,??vA|???h???·??êBm??E

KL

MN

?9??v


?????v??èt?
?

??v

???Bm?E

KL

MN

(2)
2
:(i)
ò??

?}

???

?|
t=0
!"

#
5 
$

!
"
!
#
(2
%

???U/??
,134λ1=L
??λ1=

7m(1%)
?+???

??<^§
T=1.2s
????v1=
λ1
T=
10
21m/s(2%)
(i)
ò??

?}

???

?|
t=0
!
"
!
#
(2
%

???U/??
,114λ2=L
??λ2=

5m(1%)
????v2=
λ2
T=

3m/s(2%)
!"

#
6 
$

!#
14.【
01
】D

23
】?
O
(23892U)??W?O(
206
82Pb)
1H+

1H
→42He+

0n_O????,
234
90Th→
234
91Pa+

-1e_ β????,S?KL BMN;????}?
m=mo(

2)
t/T,23994Pu239
94PuV20???"??

32g,S?KL CMN;
238
94U→
234
92U+

2HeWα????,S?KLDXY。
15.【
01
】D

23

???k?W
t,
?T&?kv,?
??W
v′。
???@
Ek=

2mv

?
:v′=

2v:v′=-

2v,?? v′
2-v2=-2gx
?
:v= 8gx
槡3

??k?°±
:t=v′-v-g,2? t1=
2x
3槡g:
t2=
6x
槡g

KL

XY

16.【
01
】A

23

???G?

<^U
m。
?

??

QDé

G?
1、2
??·?W??

8G?W
F。
??89:???$??

<,???



???U/??

?\

120°,
f?9?k?$?G?

<,?·??$?}

??????????
?
F=mg,
??$?G?

<,?8GW
F1=mg。?2??3QD{,G?2<`?U?W
-q,
??????
F=kQq
r2
?

G?
1、2
?????8G"_
F,
·?W??

??89:??
$??

<,???



???U/??


60°,
P???????????

?$?G?

<,?8G?W
F2 槡=3mg,S? F1?F2=
1?槡3,KLAXY。
17.【
01
】D

23

¤?
R2?§<`¨W槡

8Um,???¨???,4F??§<`¨W
槡2
4Um,?????
°?§<`¨IW
槡2
4Um,?`¨°I1
I2
=12,I1R1=2I2R2,
?
R1
R2
=4,
KL

XY

18.【
01
】B

23

ò

?
I0?}áè,?cn?F?y a、bn?F}

?Q??}??@?
bc
???

KL

MN

ò

?
I0?}á?,?an?F?yc?W??

?}?
ca
?}
,?
y


?}?
ab
?}

?Q??}?@?
bc
??
?

??@?
bc
???

KL

XY
、C
MN

ò

n?F?ybc
???

?

?


?

,?
a8G??°±
I>I0,KLDMN。
!"

#
7 
$

19.【
01
】AD

23

?

??t?

??<_cde

\^§
T,
°±
GMm
r2
=m4π
2r
T2

2?
M=4π
2r3
GT2

???
?ρ= M4
3πR

=3πr

GT2R3

KL

XY

??

KL<9:

???D??^U

?@??DC?<
^U???

KL

MN

????DC?<^U?????

KL

MN

?
GMm
r2
=mv

r? v=
2πr
T,?"? M=
v3T
2Gπ

C????ρ= M4
3πR

=v
3T
2Gπ
·

4πR3
= 3v
3T
8Gπ2R3

KL

XY

20.【
01
】AC

23

?
MN
??k

á?9`d

`?h`??
E=BLv,MN
<`?á?9`d
?
`??<`¨
Blv
2,?MN?§`¨<8GU=
Blv
2;P?????,???}???},?a??
ó??

???}?W`a?}

??

y
M,
??a?`?<(_?

V

y
d,
KL

XY

KL

MN

?WX????
,?
a
I=Blv2R,?MN?yB2l2v
2R,????
????

????}??}?

KL

XY

KL

MN

21.【
01
】BD

23

????h

G??,-?R
¤?,-á;

F8¨?UkG?|F~?

??W×

F831Uk

|F%?

??IW×

,??@
á;

?????@?;

/?
KL

MN

,-n9F831Uk

G??
ú
?,-?H<,??@W
mgh-45mgh=

5mgh,KL

XY

G??,-QD{q???h

?}q????

{????

????<à?
P=mgv
??8{?G

KL

MN

G??,-QD{q???h

?/?:Ek+EP+
E′P=?N,G?8

KL

XY

22.【
01
】(1)BCD(2
%
) (2)1.39(2
%
) (3)2k(2%)

23
】(1)
?9?i

S?
????#?U??

<^U

KL

M
N

???à<1át?§?%

??8???_?#??
?W???i

?y?(?&è???4

KL

XY

?i

éê???k°

?Q?`d

PTJG?

?Dt
9ì?

èkí???°<=7_?#??<

KL

XY

÷?????<^U

?????
<8G

?D?9ì?

??ò????e??j
KL

XY

(2)
?/ó????a`0.02s,
f?Wá???7??"H?u?÷H?D

!"

#
8 
$

???7???t=0.06s,
?ú?J
Δx=at2?a=
(x4+x5+x6)-(x1+x2+x3)
9t2
=[(3.80+3.30+2.80)-(2.30+1.80+1.30)]×10
-2
9×0.062
m/s2=1.39m/s2;
(3)
?BC4"+??

?i


????#????
a=2Fm,
?
a-F
+>c?

+>k=2m,S??i<^UWm=

k。
23.【
01
】(1)0.0200(0.0199~0.0201
?!%
)(1
%
) (2)
¤+S=
(2
%
) B(2
%

!
!
"
!
#
$
%
!
#
!
&
"#
$
(3)48(47~49
?!%
)(2
%
) 7.5×10-7(2
%


23
】(1)?
?"d=0.01×20.0mm=0.200mm=0.0200cm。
(2)
#Fk?$ó`a·?TU
S2_%g<,B!#F¤+S=。W4?GBCN?,?K?
&'?%<`a·
A1。
(3)
?+(??

?F??
k=29Ω0.60m=48Ω/m。`a·???)ik,R1? R2?§<`¨á
;
,Rx?R?§<`¨Iá;,*?? R1、R<`aá;,?? R2、Rx<`aIá;,?H
R2
R1

Rx
R,??Rx=ρ

π(d2)


?
R=4ρ
R1
πd2R2
L,
?
k=
4ρR1
πd2R2

2?ρ=7.5×10-7Ω·m。
24.
2
:(1)
lmé{ì??

v1、v2,????@??H:
m1gR=

2m1v

1(1%)
-m1gh′=0-

2m1v

2(1%)
?????????

T1-m1g=m1
v21
R(1%)
T2-m1g=m1
v22
R(1%)
gh2?

T1
T2
=259(2%)
!"

#
9 
$

(2)
?G?lm??

???U????H

m1v1=-m1v2+m2v3
2?
:v3=3m/s(1%)
G?

lm{

5??}??A??y??

H

h=12gt

vy=gt
2?
:t=0.8s,vy=8m/s(1%)
???}??

l{|????q?Z???F??

????????H

F=m2a
???????

H

vx=v3+at
2?
:vx=7m/s(1%)
?

?Ck:v= v2x+v

槡 y
?

?Ck:Ek=

2m2v
2(1
%

2?
:Ek=226J(2%)
25.
2
:(1)
\5T&|`óh?+????

?\5#t???ókv,
?
v 槡=2v0(1%)
???@?"H
qEy=12mv
2-12mv

0(2%)
?
v0=200m/s(1%)
(2)
?\5#t?V?

,(x1,0),?
x1=v0t1(1%)
y=12vyt1(1%)
vy=v0(1%)
?
x1=2y=0.08m(1%)
???U/??

\5|?óh?]^??r=槡22x1(1%)
????#???H
qvB=mv

r(2%)
?
B=10T(1
%

?9\5÷H?
y=-b
?D

??

bmin=r+槡

2r=
槡1+2
25 m(1%)
(3)
????
\5#????

,<_`¤+

!"

#
10 
$

!"#$
%!"
!!"
%"&
'
(
#
)*
+
,

N/úW
amin=2x1+r-槡

2r=
槡3+2
25 m(2%)
\5|`óh??t?=3t1=3
x1
v0
=12×10-4s(1
%

\5|?óh??
?
=2×34×
2πm
qB =6π×10
-4s(2
%

????<0k?
t=t?+t
?
=(12+6π)×10-4s(2%)
33.(1)【
01
】ACE

23

12?<34_?*h
?t!"??h?%5?
?
???8

KL

XY

??6%

?
KL

MN

?Wxy·?%5???
89xyg7%5???

x?%5????·?W??

S?xy·??Hs?
K
L

XY

uv????8????94%5???<|6?

KL

MN

?@??t?d
rs?U?7?c?àf??????j

_???#???
KL

XY

(2)
2
:(i)
?;
=pky¨[W8¨[

?W
p0,
?;?kH
:p1S+F=p0S(1%)
2?
p1=0.5×10
5Pa(1
%

?/ó??

y
=p
:p0=1.0×10
5Pa,V0=L0S,T0=300K;(1%)
?p
:p1=0.5×10
5Pa,V1=L1S,T0=300K(1%)
??óA???
:p1V1=p0V0,(1%)
?
:p1L1S=p0L0S,(1%)
IR7?2?
:L1=1.2m<1.5m
;<>?kB1
1.2m(1
%

(i)
?Chy??D%k;
y?;¨?j
?FGH????

V1
T0

V2
T2

?h
V2=HS(2%)
?
T2=375K(1%)
34.(1)【
01
】ACE

23
】t=1.2s


?8r0|
x=25m
n<^?X|?8r0I?}?J?

??J??
??
??

,X}??

KL

XY

?j+??

?1W
20m,
?k+??

??
!"

#
11 
$

^§W
1.2s,
???
v=201.2m/s=
50
3m/s,KLBMN;?9^§W1.2s,??t=0k¤??
t=1.2s

?J????,t=0


?


,X}

?


,??}

??^?

?^?

Koy?8r0

KL
C、E
LXY
;P、Q
?^
?
??J??}?0_á?

KL

MN

(2)
2
:(i)
¤+

?v|
BC
??r,
??/óH
sinr=1n(1%)
???U/H
sinr=
槡3
2L
(槡

2L)
2+(12L)槡

=槡32(1%)
???E?
n=23槡3(1%)
!
"
#
$
%
&
'
!
"
?
sinr=槡32?:r=60°(1%)
???U/?θ=30°(1%)
?
n=sinαsinθ
(1
%

?
sinα=槡33(1%)
(i)
???U/

v?

???y
CD
?s= Lcosθ
= 槡233L(1%)
v|MNyh??v=cn(1%)
???t=sv=
sn
c=
4L
3c(1%)
!"

#
12 
$

!$
14.【
01
】C

23

??=??W×
??

tde
= 1
槡2-3


tcd
= 1
槡 槡3-2
,t′=tcd+tde=
( 槡2-2)t。
15.【
01
】A

23

???O<45)P??
,?
5|?p_c???k?}e?E`??

KL

XY

`5|_c?wxk

???rs:JDt???
I???????B?

¤`
5?),
KL

MN
;?
5?eQ_c

%@

wxygQ_c

~@

k

?@?8

b45<@U?G

KL

MN
;?
5R?45O?Z?]^??

?H

%_

~?

8^§


?|eQ_c??<^§?|gQ_c??<^§8

KL

MN

16.【
01
】D

23
】a
?S|?`??F
+h
FP=FQ=BIL,θ=30°,???Q? F=
2FPcos30° 槡=3BIL,?}5?}?,KLDXY。
!
"
#
"
#
!
#
! !
$
17.【
01
】C

23

!y\át??f=μmg;?9át,#@V??v??,HF=f=μmg;?9!
y

????#???μmg=ma,?a=μg;!y?Z???F??,H t=va=

μg

?kát<
rE
s=vt=v

μg

??}?

W=Fs=μmg·v

μg
=mv2,
KL

XY

18.【
01
】D

23

C?|
12h
180°,
#2??#??D?|

?
?k???°
±

4T+nT=12h,?T=
48
4n+3h(n=0、1、2、3…)。?n=0k, §HF8NT=16h,?n<
WN?è

?^§?è

bN??
16h
G

??????^§?èX??^§G

KL

MN

???%3??

?????@)ù
12h
V?

???t?

KL

MN

??<^§G9è
X??<^§

_cdeG9èX??<_cde

??
a=GM
r2
??

?????X??
KL

MN

???T=16h,
?FGπ
8rad/h,K
L

XY

19.【
01
】AC
!"

#
13 
$


23

?
DE
?|
0~L
YZgk

?F[????hHG\]1?6c68

?k?RF?U
/

=&(_
DE
?1?

S?`a?k?
XY

KL

MN

?W_Z??
?

??

????;N?}

?
F=B
2L2v
R ?,?? LR??^7U/,?W? DE?|0~2L
YZgk

?F[????hHG\]1??k???Z??{?Z?G

S?

?k???
??6c6_{?G?6c6`

KL

XY

KL

MN

20.【
01
】ACD

23

?
t=Lv0

PQ/ó??
A、B
|`óh
KL

XY

??;9?????

\5??`ó???

??
a=qEm??
aA
aB
=12×

1=2,KLCXY;??d=

2at

??
,A、B
?`óFdA
dB

aA
aB
=2,
KL

MN
;A、B
<`?@??U??;9`
ó??à??

???@?"??
W=q
2E2t2
2m ,S?
WA
WB
=11×

22
=1,
KL

XY

21.【
01
】AC

23

?i?

??y

?
?Q???G{?8

?????G{?8

????
8{?G

KL

XY

KL

MN

?i?

??yF8?@n

???@?"H

,

mgLsinθ-μmgLcosθ=Ekm-0;?i?A??y?A???W


2sinθ
-μmgL2cosθ=Ekm′-0;?W,′>

2W,,gh2?Ekm′>
Ekm
2,KL CXY;?i? A??y B
?
,-,??@
?9?i|

?k

,-?n9???p

S?,-,??@EP,KLDMN。
22.【
01
】(1)B(2
%
) (2)3.0(2
%
) 0.53(2
%


23
】(1)
?è?T&BC{a??`¨??°
?`?`aW

k
,?
¨??°H=
7

?W
0,
?D<
U-I
+>h
,?
¨?`a
bb-.Hc?

de+h?u+
>??KL

fQ
。(2)
?`¨??°

§?Qy`?h

§

?`¨??°?U<_???
?°?§<`¨

b?9X?QFQ?4

???U<7Nê?W?N

??kWg?N??

??¤+kS=<
U-I
+>??
,?
d`??W
3.0V,
?KQ`?E=U+
IR+( )r,
?
U=2V
k
,I=0.095A,
?
E=2+0.095R+( )r,
2?
r≈0.53Ω。
23.【
01
】(1)D(3
%
) (2)D(3
%
) (3)BD(3
%


23
】(1)
???k°?Q?a`d

h??@????k

;???<^U??i

???
#?U^U

S??#??\??

?????#?á??7
?#¤?j

KL

f
Q/ó

(2)
|Ck??@????k

?@?HU

Nc????

S?l?
v=gt、v2=2gh
?????_
MN
%??¤?j?Q?U

|????kl?h?k¤
!"

#
14 
$

(3)
BC??h??mnC?|??

?¤*??

ì??orp??),
?q?
??@
?BCN??9/?N?

?@?????G*?
?\????
?@??÷??U???N
KL
B、D
XY

24.
2
:(1)
???U/??

\52h,
5?rEW

?+????}??
2h=v0t,h=

2at
2(1
%

???#?????
Eq=ma(1
%

gh2?
E=
mv20
2qh(1%)
(2)
\5yü

?

?

,X?}<%??
vy=at=
Eq
m·
2h
v0
=v0(1%)
????

,X?}vy
v0
=1,
?α=45°(1%)
\5?
MP
MP
?R?ó

??9
NP
ED?ó

\5|?óhv槡=2v0(1%)
_cde
R 槡=2h(1%)
f
Bqv=mv


2?
B=
mv0
qh(2%)
(3)
?/ó?

?`\5|?óh]^??<^§
T=2πRV =
2πm
qB,?`\5|?óhi??W
45°,
???k?
t=18T=
2πm
Bq·

8=
πh
4v0
(3
%

25.
2
:(1)
??i
A、B
?,-%?ì?vA、vB
W}?WX?}

??U?????
mA+m( )B v=mAvA+mBvB(1%)
?i

}

??
???@?"?
-μmAgs=0-

2mAv

A(1%)
tFuvì?,-TJ<,??@
Ep=

2mAv

A+

2mBv

B-

2 mA+m( )B v
2(1
%

2?
vA=3m/s,vB=-3m/s,Ep=24J。(1%)
(2)
?i

|w??}???y

{}???y??x?y?

?{??x?}??T


???k?WΔt。
?i

???8G
a=μg=2.5m/s2(1%)
???????
-v1=vA-a·Δt(1%)
xA=
vA+ -v( )1
2 ·Δt(1%)

?
=(-v1)·Δt(1%)
?i??x??<á?????
s1=xA-x
?
(1
%

!"

#
15 
$

|á?????hlmQ=μmAgs1(1%)
???z?

IR7??
Q=32J。(1
%

(3)
??i

??=??W
v2,??k?Wt,?x=v2t(1%)
h=12gt
2(1
%

?
t=0.4s(1
%

ò?x?{k???vm,?iA?}?t???,?y??k=??·
W
vm
?μmAgL=

2mAv

m-

2mAv

A(1%)
2?
vm=6m/s(1%)
!

(1)
ò?x?{k???v2≤vm=6m/s,?A|?x????x?á???{,@??
x?@Vyè??

??=??;9
v2,??E?x=v2t=0.4v2;(2%)
(2)
ò?x?{k???v2>vm=6m/s,?A|?x??}?t?????,??=?
?;9
vm=6m/s,??E?x=vmt=2.4m。(2%)
33.(1)【
01
】ABD

23

?\?¨????HU

??\?
KL

XY

y|;¨?j??h

ò???D%

%5??????8

?W¨[??

S??°g)???r???y%5
lm
KL

XY

????·?_???
????·?
_??<

|J?R?4

·???_t?<

KL

MN

%5????8k

%5???\
????G

b_%5?@?t??G

U?#?%5??Xà"_?à

KL

XY

y<
??D%k

??"~ypV
T=C,?9y???¤??j,S?y<¨[?t?
?8

KL

MN

(2)
2
:(i)
??óA??H
p0 N( )+1V=pV(1%)
?
p= N( )+1p0(1%)
??wmg+ N( )+1p0S=p0S+f(1%)
?
f=Np0S+mg。(2%)
(i)
??óA??

H
p0 4N( )+1V=p′V(1%)
?
p′= 4N( )+1p0(1%)
??w<

???#???

H
4N( )+1p0S- p0S+f+( )mg=ma(1%)
?
a=
3Np0S
m -2g。(2%)
34.(1)【
01
】ACE
!"

#
16 
$


23

?h?<^§?_
T=1s,
?
v=λT?,?1λ=vT=0.2×1m=0.2m,KLAXY;PC
-PB=50cm-40cm=10cm=0.1m=0.5λ,f t=0k¤???[
J?;9??J??\

?W
70cm,
KL

MN

KL

XY

??

?y

t=PCv=
0.5
0.2s=2.5s,??B?yPPB
v=
0.4
0.2s=2s,|t=2.5sk¤,??Ⅰ??
?Ⅱ????, ?PV??8}q??,|t=4.5sk¤,V?4?u^§, ?V??8}
q??

KL

XY

??1W
20cm,
????y
40cm


KL

MN

(2)
2
:(i)
?
v=cn?
v|?hv′=3c4(2%)
v|??hv″=2c3(2%)
(i)
?Dv?+

¤+S=
!
!!
!"
#
$%
"
&'
!
#
#
v·?|?\*<%~?Bm??Ek

H
sinC=1n1
=34(1%)
|????<%~??

?
sinC
sinθ

n2
n1
(2
%

?
sinθ=23(1%)
?v?r=dtanθ+2dtanC=(槡255 +
槡67
7)d(2%)
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#
17 
$

!%
14.【
01
】A

23

?|??
?k
A、B
?|}??Z???

?
A、B
??
???\?V???

???}÷He?

???}??????

èk
A、B
?I÷H,??
?

15.【
01
】D

23

(*h?u;U???`?#F
?φ′=φ=0;?ó[??4
"??
E=2kQ
r2
,E′=2k Q


2)
2=8k

r2
,E′=4E。
16.【
01
】D

23

??B?Wt?y

?y·???

??R?????

R?
H
GMm′
r2
=m′v

r,?M=
v2r
G,KLA、B?MN;???<
deW
R,
?/ó?#°±
2GM
槡R
>c,
?H
R<2GM
c2
=2v
2r
c2

KL

MN

KL

XY

17.【
01
】C

23

?opwxrs<@U/úW
-13.6
22
eV-(-13.6)eV=10.2eV
????opwx
yn9#?@
KL
A、D
?MN

tu45n9
n=4

F÷??BD

?
v5
(4-3,3-2,2-1),
KL

MN

#?Bm?:?>k

45lm?é
??
45?BmY??,?lm

??
?opwxy#tzBp

KL

XY

18.【
01
】C

23

G?

?????

??????}?H
x=v1t,y=

2gt
2,
fH
tan30°=yx,?v1=
槡3
2gt。G
?

·????|???

?H
tan30°=
v2
vy

v2
gt,?v2=
槡3
3gt。????v1?v2=3?2。
!
"
#
$
"
!
%
"#!
"#!
!
"
$
"
$
%
"#!
"#!
"
"
$
19.【
01
】AC

23

?+??
,0~4h
k?g

j??Z???F??

KL

XY
;0~1h
g

j<=??

j
=40km/h,
???

j
=-10km/h2,
k<=??

k
=60km/h,
???

k
=-40km/h2,
?
!"

#
18 
$

j

k??á?kSV?t,
?

k
t+12ak t
2=v
j
t+12aj t
2+5,
2?
t1=

3h,t2=
1h;
?+>??
,1h~3h
g

j

k??rEá;
,3h
kj

k??P?á?
;3h~4h
g

k
?|j?é?

?Pá?

KL

MN

KL

XY
;3h~4h
g
,x
j
2=

2(10+0)×1km=
5km,x
k
2=

2(20+0)×1km=10km,k???j?5km,KLDMN。
20.【
01
】BD

23

???????

???
ab
?`ab→a,?N b§`?? a§~,KL AM
N

?@U??????
ab
?ù????<à;9`?

\????lm
KL

XY

??U?"
-BILΔt=0-mv0,?u??h??`?UIΔt=

2RΔt,f E=
ΔΦ
Δt
=BLx
Δt

gh
?
IΔt=BLx2R,???2mv0R
B2L2

KL

MN

KL

XY

21.【
01
】BC

23

?i

??y

?k

??9$
Q?W×

?$5?}

??H?$}
q<%?
mgsin53°,
????#???H
mgsin53°=ma,
?
a=gsin53°,
KL

MN

?i

?

???y

?
?5
?Xà

???@??

KL

XY

$??
??}R
53°,
+hl=Lsin53°=83m,S??iA??yP?k,?iAq?<%?
h=xOPsin53°=Lcos53°sin53°=
10
3×

5×

5m=

5m,!i Bq?<%? H=
10
3m-

3m=

3m,??iAyüP?k,!iB,???@
?????
MgH+mgh=12mv
2,
?
v 槡=52m/s,KLCXY、KLDMN。
22.【
01
】(1)1.060(2
%
) (2)
?v9??v`¤t、
v`¤y

?s(2
%

(3)d

2gst2
(2
%


23
】(1)d=10mm+12×0.05mm=10.60mm=1.060cm。
(2)
?#?c!i??v`¤k
S??#?U?v9??v`¤t,
?#?U!
i??v`¤?{
S??#?U!i??v`¤?{??
?v`¤y

?
s。
(3)
??Z???F??}?H
v2=2μgs,?hv=dt,?μ=
d2
2gst2

23.【
01
】(1)
d)
(1
%
) 
;GIH
(1
%
) (2)B(1
%
) (3)①#Q`?h??????°

?09

§
(2
%
) ②`???N|?Ué??092kΩ??(2%) (4)89
!"

#
19 
$

(1
%
) R1(1%)

23
】(1)A、B
?rè?%?§?4?è<`a·g?,A
è?§?<_d)J
,B
è?§?<_;GHIJ

(2)B
è?
?W

è?
LM`??`?N

2
!
·`aW
Ig
2k,?9e`?0`??8,??°?D<`¨?8,?`a·?`??%g<
0`¨?8
,?
??<`¨?89`a·<`¨

??%g`?%3S???
,?
UN?89
`a·g?(BN
。B
è?§?;GHI
÷H/?N?

(3)B
è?:①TUKQé,??????°`?h?D`¨?FGN?8T&LM

??`a?8

??`a·
;②`???N|?Ué
??09
2kΩ??。
(4)
??%3??
,A
è??1h

S?y<`a·g??UN89`a·g?(BN

WL
M??

??°<0`??K?
R1。
24.
2
:(1)
G?|?°?}F1F1=mω

0R。(2%)
(2)
?G??°±?D]?kv1,????Uv21=(ω1R)
2+v2(2
%

?|???h,-?G??àW
W,
H?@?"H
W1+W=

2mv

1-

2mω

1(R-x)
2(2
%

?h
W=Ep
2?
W1=

2m(ω

1R
2+v2)-12mω

1(R-x)
2-Ep。(1%)
(3)
?G??°?}?`}gE?x1k,?}a???H
F-kx1=mω

2(R-x1)(1%)
?
F=mω22R+(k-mω

2)x1(1%)
?9

<8G??

?
x1|U,?H
k=mω22(1%)
F=mω22R(1%)
S????<à
W2=mω

2Rx。(1%)
25.
2
:(1)
\5|???[?W

qvB=mv

r(2%)
2?
r=mvqB(1%)
!"

#
20 
$

?W\5??H??

?
v1= 槡
23qBd
3m ,v2=
2qBd

S?
R1= 槡
23
3d,R2=2d。(2%)
(2)
|t??<\5??<_`=ó¤+S=
! !"
"
#
$
???U/?
??W
v1<\5EDx=2d?~k<-.W
y1=2R1- R

1-d槡( )
2 = 槡233d(3%)
??W
v2<\5EDx=2d?~k<-.W
y2=2R2- R

2-d槡( )
2 = 槡( )4-23d(3%)
S?Δy=y1-y2= 槡
83
3( )-4d。(3%)
(3)
?u\5_`¤+hBFS=

?ó?~¤+h
??2??
x=2d
?~ED<
?·\5F'??Rt·

I??

,X?}??
。(6
%

!
!"
"
#
$
"#!
!"#$%&!
'()*+!#
$,--.
33.(1)【
01
】(1)a(1
%
) 
÷
(2
%
) 120(2
%


23

??
pV
T=C(CW?U)??,?pa??F~,S??<%5???@FG;b、c??á
è
,b
<¨[?

<8

??¨[
?ph?°??r???rk?g?y
y%5m?
V?
ca
??

e~?y?<à
W=pΔV=100J,?????#t?
?ΔU=Q+W??Q=120J。
(2)
2

T&k

?C?7%yy?W

2,? [W p0;q7%yy?W

2,? [W p0+
mg
S。
(1
%

!"

#
21 
$

{c

?C?7%yy?W
9V
10,?¨[Wp;q7%yy?W

10,? [Wp+
mg
S。(1%)
?R<*0y?W

10×49,? [Wp0
??7%y

??óA??H
p0·

2+p0·
49V
10=p·
9V
10(3%)
?q7%y

??óA??H
(p0+
mg
S)·

2=(p+
mg
S)·

10(3%)
2?
m=
p0S
4g。(2%)
34.(1)【
01

?
(2
%
) y=0.4sin(2.5πt+π)(m)(3%)

23

?+???1λ=4m,V0.2s}é????

?
v=λf?,f=vλ
=1.25Hz;
?
y=Asin(ωt+φ0),??x=2mn<^?y=0.4sin(2.5πt+π)(m)。
(2)
2

v?¤+S=
!
"
#
$
%
&
'
(
)!
)
*
+
(i)
vFyü
AC
?<

?

REbW
i、
?EbW
r,
?/ó?
i+r+90°=180°(1
%

i=30°(1
%

??E??H
n=sinrsini(1%)
2?
n 槡=3(:1.73)。(1%)
(i)
vF?Ey
AB
?<

?

REb
i′=60°
?W
sini′=槡32>

n,S?v|M?Bm??E?êED×??(2%)
vF?Ey
BC
?<

?

·???9
BC
?#??ED×??
PQ=dtan30°=槡33d,QM=2PQ,MN=(

sin30°-2d) 槡cos30°=3(L-d)
v|??hv=cn(1%)
?v?

?ERy#??ED×??V?t,
?H
PQ+QM+MN=vt(2
%

?
t=3Lc。(1%)
!"

#
22 
$

!&
14.【
01
】C

23

?9??F<97??

???i???h

????
KL

MN

??
??????
,?
a?

?aD

a}

?

????`?

<`a?}}?

KL

MN

]
??R|7????R

i???h\]??F?R`a

|?óh<)t9???????
???
S?uT`?
S,
]????i?

KL

XY

KL

MN

15.【
01
】A

23

5\α\5|?óh?Z?]^??,???????}a?,? qvB=mv

r??@
Ek=

2mv
2=q
2r2B2
2m ,?
EkH
Ekα

q2Hmα
mHq

α
=1?1。
16.【
01
】B

23

????imgcos30°=槡32mg,KL AMN;?in9?8?p,??
????bW
120°,
?????Q?W
mg,
????i
?????img,
KL

XY

??
F=mg=mgsin30°+μmgcos30°,2? μ
=槡33,KLCMN;??i\??槡3
2mg,KLDMN。
17.【
01
】C

23

??B?Wt?y

?y·??

???·?<|t^UW

GMm
R2
=mg,
fH

R=
c2
2G,gh2?g=
c2
2R,IR7?
??????<7UW
1012m/s2,
KL

XY

18.【
01
】D

23

?`?I=PU=
40
24A=1.67A,KLAMN;t?LED?<à?W40W,)??
?2??
10
Gk?

)???<`@?W
W=Pt=40W×10h=400W·h=0.40kW·h,
KL

M
N

??@`?t?v@ijW`@<à?
P=P0S×15%=1.0×10
3×1×15% W=150W,
KL

MN

??`?Y??°`

????@`?t?7?9??`??`

?@U
E=(1-0.2)qU=
0.8×300×24W·h=5760W·h,
f??@`?<

?2t????E

à?W
150W,
?k?
t=
5760
150h=38.4h,KLDXY。
19.【
01
】BD

23

ò??8???vRE<[?

?9)uv5<@U??

??v`5!"

#
23 
$

?

b?rk?gED
??v`a?8

KL

MN

?Dà????×A?
??

?_?Hv?|U

KL

XY

Bmv`G???#k???

?#REv[o????

KL

MN

ò????°???E

?`¨·S%?<`¨?G

?`¨_?
}`¨

??`¨?Gk

v`5???yü

[?R`a
,?
a·=7??8

KL

XY

20.【
01
】ACD

23
】P
?<ó[
Ep=
kQ1
(2L)2

kQ2
L2
=0,
KL

XY

?

?<ó[W×

?

???
,E1>
E2,? óF}?,?{?`óF`??~??φb>φc,?b、c?ó[
KL

MN
;P
???
E2>E1,? óF}?,? P?`?%9 a?,ò?t??
`?
+q
?

??

,E/

?

??`?@??

KL

XY

ò?t??`?
-q
?

?>
?TJ

?`???
aP
}?????



?{?y}?<`ó??????

???V?

?k?@F8

KL

XY

21.【
01
】CD

23

G?
A、B、C、D、E
?R
KL

MN

?9G?

???8

G?

|?u??h?ê?

S??$
DB
?G?

??à

f?$
BE
?G?

?
W?V?{W??

???à{?Xà

S?G?


KL

MN
;BE
???$?}??á;

?G?

?CkG?


??à@U/
mgh=12mv

?
?G?

2槡gh,KLCXY;?G?A?}?
S??V?;9??

KL

XY

22.【
01
】(1)
8
(1
%
) 

(1
%
) (2)R-1I(1%) ¤+áS=(1%) (3)1.0(1%) 
89
(1
%


23
】(1)
G`??
W4@A`?h=°:
F=#?`??LyF8

?`??,?
??
?k
,?
??(?_
?`?4

S?#?i5?à

???i?

(2)
ò#l?+>
?#?|?u?U?RF??
??
?F
?`d<`??W
E,?
???W
R0,?WX??HE=I(R+R0),???"<R=

I-R0,????D,R\

IR???U/

/h!D<-.?5

B??,??20
G?

PQ·h<

è<7?

b
,?)G?I·
1Ω??·?,è??·?h<7????é|-./h

??ê?#QRt9?F

¤+áS=

!"

#
24 
$

!
!
" # $ % &
&
"!
"&
#!
"
!
'(
)"
"'!
(3)
?+h(-1,0)
??

?
-1=-R0,2?`??ò`dHg?
r,
?WX???jW
R=EI-R0-r,B??+h??g?(1-r),
???UN)8

23.【
01
】(1)


t2
)2-(dt1
)2
2h (3%) (2)X?(1%) (3)0.44(3%) (4);9(2%)

23
】(1)
!i

??v`¤
C、D
kvC=

t1
,vD=

t2

?

y

??

?Z??
?F??}?H
v2D-v

C=2ah,????a=


t2
)2-(dt1
)2
2h 。
(2)
?
A、B
?!y\
10
uG???R

???#????
2nmg=(10m+
2M)a,
?+=+>??

!y
(3)
???#????
a= 2mg10m+2Mn,?+= a-n+>??,+>2mg
10m+2M=
1.00
5 =0.2,2?M=0.44kg。
(4)
òH??
f,
???#????
2nmg-f=(10m+2M)a,
???
a= 2mg10m+2Mn-

10m+2M,
+>

S?!i^U


24.
2
:(1)
?|
ac
r0k??`??F8
Em=BLv(2%)
??`aF8
Im=
Em
R(2%)
IR7N

??
Im=0.4A(2%)
(2)
???/
Oac
YZ

?
x≤0.2mk,HG1?L1=2x(1%)
!"

#
25 
$

???/
acb
YZ

?
0.2m<x≤0.4mk,HG1?L1=2(0.4-x)(1%)
??`??
E=BLv(1
%

??`a
i=ER(1%)
?
i=
2xA(0≤x≤0.2m)
(0.8-2x)A(0.2m<x≤0.4m{ )(2%)
25.
2
:(1)
?i?

???y

?
???@?"H
Fd=12m1v
2(2
%

IR7?2?
v=6m/s(1
%

G?yü

?k
,?
?¤+S=
!
!
"
#$
!
%
!
?
qE=m2gtanθ(2%)
2?
E=7.5×104N/C(1
%

(2)
G?S????`ó?
;

m2g
cosθ
(1
%

G?yü

?k

???#???H

;
=m2
v2P
r(1%)
IR7??
vP=2.5m/s(1%)
?i?G?Bm,?Xl

?l{?i

G?v1、v2,
?}??}WX?}

??U?????
m1v=m1v1+m2v2(1%)
?@U???

2m1v
2=12m1v

1+

2m2v

2(1%)
ghIIR7??
v1=-2m/s(“-”·=v1G?l{??y

?
??@?"H
qE(x-rsinθ)-m2g(r+rcosθ)=

2m2v

P-

2m2v


 (2
%

IR7??
x=0.85m(1
%

(3)
G??

??D
???}?Z????

H
L-rsinθ=vPcosθt-


qE
m2
t2(2
%

5??}?Z????

H
r+rcosθ=vPsinθt+

2gt
2(2
%

ghIIR7??
L=0.5625m(1
%

33.(1)【
01
】(i)3T0(2%) (i)2kT0+6p0V0(3%)

23
】(i)
?p

??p
d?
[á;

H
Va
Ta

Vd
Td
!"

#
26 
$

?
Td=3T0。
(i)
?/ó??
Ua=kT0,Ud=3kT0
????#t??

H
Ud-Ua=Q+W
?h
W=-3p0(Vc-Vb)
gh??
Q=2kT0+6p0V0。
(2)
2
:(i)
?

??ì?í%??Δh?W5cm,?
p1=p0-ρgH=60cmHg(1%)
p2=p0-ρgΔh=70cmHg(1%)
??"~y?p??H
p1h0
T1
S=
p2h′
T2
S(1
%

?h
T1=300K,h′=55cm,h0=50cm
?
T2=385K,t=T2-273=112℃(2%)
(i)
?K??*BW?ò?>

H
p1h0=p3h″
?
p3=
p1h0
h″=100cmHg(1%)
???*B1??W
30cm
k

???í?q?4
h2=20cm
PK??*BW?ò?>

???;h?=9cm+50cm+15cm=74cm(1%)
?;
k

??*B¨[
p4=p3+55cmHg=155cmHg
*B%?
h4=74cm-x+20cm(1%)
???óA??H
p0h?S=p4h4S(1%)
2?
x=58.2cm(1
%

34.(1)【
01
】BDE

23

?9??????^??

¤?Jdp?J?

|?^h??
K
L

MN

?????v?E??

????

?Ev
?E?>6??

KL

X
Y

??v_A?v

??)J?{

v<[??G

?òv_`??,?
???;9v?

ó?
“B
?

h

KL

MN

??ùúU9
`?ó
?j<`ólm?ó\?j
KL

XY

??÷
?üG?

??

?A???/?|ê=>BD>?kBv11

?
c=λf,?Qs(2)
2
:(i)
?v·V?E{yüg???

?

¤+
?/ó?

REb
i=45°,
?Eb
r=∠BAO(1%)
???U/H
sinr=0.5(1
%

!"

#
27 
$

!
"
#
$
!#
%
??E??H
n=sinisinr(1%)
IR7?2?
n 槡=2(1%)
(i)
?|

?i′
k

v·V?E{yüg???

?

I|

?·Bm??E

?v
·|g???!
"
#
!"
$!
%
&
?
sin∠ACD=1nIR7??∠ACD=45°(1%)
?△ACO,?X!?"Hsin(180°-∠ACD)AO =
sin∠CAO
CO (1%)
?h
AO=2R,CO=R
2?
sin∠CAO=sin∠ACD2 =
槡2
4(1%)
??E??H
n= sini′sin∠CAO
(1
%

2?
sini′=0.5,
??ki′=30°(2
%

!"

#
28 
$

!'
14.【
01
】D

23

?+P"??

8G#à
KL

MN

8G#àé#à$Q??
,a、b
??

b_?}?è

KL

MN
;a、c
??è,i?

b??á;

?ωa=ωc,f
*
va=vb,ra>rb,??v=ωr??ωa<ωb,???yωc<ωb,KLCMN;?9 ωa=ωc、ra>rc,
??
a=ω2r??aa>ac;?9va=vb,ra>rb,??a=
v2
r??aa<ab,??b?<}a???F
8

KL

XY

15.【
01
】D

23

??°?+????

|??=???}
?
v⊥ =at;Q??<8GWv= v

0+v

槡 ⊥ = v

0+( )at槡
2,
?Q??<8G?k??RX?

KL

MN

??=???}?
????????
KL

MN

?
?_.U

?rk?g??8G

PQQ??<8G
v= v20+v

槡 ⊥ = v

0+( )at槡
2,
????°?rk?g???j<

KL

MN

???U?"

??????k

|?rk?g?U<%U

KL

XY

16.【
01
】B

23

q45op<@U
E1=-13.6eV,??êq45?@BDv5@UW
-0.96E1,?wxyF%@@UE=0.04E1=-0.54eV,?n|n=5@;??
FG17.【
01
】C

23

|??????q?]^??

???}????}??

S??@|
P1、P3r0。¤
????ì?}?
?????????}áè

Q??8

}a??8

????8<
C??_

S?|
P3?&??ó;¤????ì?}e??G

}a??G

?|??G
|
P1r0&??ó。
18.【
01
】C

23

?+>??

át??
2s
{?TG!i

KL

MN

?+>??
,0~2s
gátE
x=2×12 m=1m,S?L=2x=2m,KLBMN;|2~3s,?+>??a2=
Δv
Δt
=4m/s2,
f
a2=
F-μ2m2g
m2

2? μ2=0.5,KL CXY;| 0~2s,?G!i,H F
?
+Tsin37°=m1g,
Tcos37°=f1,ff1=μ1F
?

1át
a1=
Δv
Δt
=0.5m/s2,a1=
F-f1-μ2(m2g+F
?

m2

gh2? μ1
=819,KLDMN。
19.【
01
】AD

23

sr?

?'y
1,
±F?(7?ú

??D`¨?G
,?
???§<`¨?G

)*<
!"

#
29 
$

i??`

KL

XY

sr?

?'y
2,
±F?(7?ú

?D`¨?G

?D`a?G

?
??¨°`a<+?U/??

4F?<`a?G

KL

MN

K?sr

k

±F?(7W
1000,
??`¨\(7
±F?110V,
?`???§`¨W
110V,
KL

MN

K?sr

k

±F?(7W
2000,
?`???§`¨HGNW
220V,?
??P=110W,
?`a
I=PU=0.5A,? ??g????<à?Pr=I
2r=2.5W,
?`??107.5W,
KL

XY

20.【
01
】BD

23

??
C= εS4kπd??

?`?^,R[t?6-
,?
?°`?68

KL

MN

???°
????????k

????#?????

,?8G??
,?
?^á?`?°?

?`?°`???

??[<`¨??

?`?°<`U??

??`?h÷H`a

KL

XY

ò??°4c}?Z???

.???k

Ui?/?

?01}???

?f¨?,
-

KL

MN

???°?>?.?}???ì?

Uá???°#}???

?q,R[
t?`?^?-

??`?ê?8

?9`¨??

??
Q=CU
??

[t?<`U?8
,?
?
°n9?`?p

KL

XY

21.【
01
】CD

23
】cd
?"ayü
F[h
b
c、d
?????|`??

*

?
`?%9

?`?

KL

MN

?F[
H
mg=2BIl=4B
2L2v
R ,? v=
mgR
4B2L2

KL

MN

??
q=ΔΦR??F[?>?TJy?????W×,??F[?c?<`?UW
BL2
R,KLCXY;ò=&kcd??F[
2L,??>?TJy?????W×?t?
?

??@U??H
mgL=12mv
2+Q,
?
Q=mgL-m
3g2R2
32B4L4

KL

XY

22.【
01
】(1)A(2
%
) (2)4.55(2
%
) (3)14kf
2(s3-s1)
2(2
%


23
】(1)
W4í?Y?
????T2?3PTJ4?

KL

XY

(2)
5.?jD=45mm+5×0.1mm=45.5mm=4.55cm。
(3)
y

?vA=
s3-s1
2T =
s3-s( )1 f
2 ,???6U/??,y A?ks3-s( )1 f
2 ,?WG?q?B?%?

s2
=Dd=k,IRmgH=

2mv

??
2gs2=

4kf
2 s3-s( )1
2。
23.【
01
】(1)B(2
%
) (2)
¤+S=
(2
%
) (3)
?8
(1
%
) 
?"`????"??f?8
(2
%
) (4)0.57(2
%

!"

#
30 
$

!
"
#
!
"
$
!
"

23
】(1)
]BC#??7?§<`¨?×ú8?8

????°?§?%¨QJ

?9?7
g?
Rx=
U2
P≈
32
0.8=11.25Ω,R

x≈121<RA·RV=1×3000,???§?`a·eQJ,K? B
`?

(2)
BC`?K?`a·
????°<%¨?

B!#F¤+S=

(3)I-U
+>h)u?<]F??·=`?<97

?????`¨
4?_
?"`?????
(4)
?+kO??7<`a
I=0.26A,U≈2.2V,??724.
2
:(1)
?:??A??y??

H
h=12gt
2(1
%

v2=2gh(1
%

?:?TJ/lmS?t=0.6s(2
%

?:lév=6m/s(2
%

(2)
?{?:?á;BmY??,?lm
??U????H
m1v= m1+m( )2 v
y
(2
%

F{?:?á;t?}q??/>?
??@?"?
m1+m( )2 gL-fL=0-

2 m1+m( )2 v

y
(2
%

IR7??
f=10200N(2
%

25.
2
:(1)
?@U???
Ep=

23mv

1(1%)
1、2
G?lm???U???
3mv1=3mv1′+mv2(2%)
1、2
G?????@???

23mv

1=

23mv1′
2+12mv

2(2%)
gh2?
v2=
3gs
槡2
(1
%

(2)
?/ó?

Q
= (mg)2+(qE)槡
2=54mg(2%)
?
DEF
_cdeW
R,
?|

?G?üy;GF%?

?9
G?·?@??
DEF
_c??

?|

?H

4mg=m
v2E
R(2%)
!"

#
31 
$

???@?"?
-54mg·(R-Rsin53°)=

2mv

E-

2mv

B(2%)
2?
R=67s(2% )
(3)
¤+

??

?\F????
BC

?α=53°
!
!
!
"
!
#$!
"
#
$
%
&
'# (
$
)*
!
+
?W
mg
qE=

3,?G?S?Q??|

?G????}?Q??}yF

G???F??
(1
%
).
???U/?
LBC=R+

cos53°=
16
7s(2%)
?

?y

????@?"H
mgLBC=

2mv

C-

2mv

B(2%)
2?
vC=
85gs
槡14
(1
%

33.(1)【
01
】CDE

23

uv??_6w|xyhzy?\<|}???

_?8Uxy%5m??R<

_x
y%5|}?????

KL

MN

?5zR
S?
1kg0℃
1kg
0℃
<
KL

MN

?=|????
ò??D%

%5<|}??
??
?y%5?°??r???
KL

XY

?/???
e~rs*V?±>1
?g7z7%?p@U?êáè

KL

XY

??y?Hz
}è?

??y?zu?}
KL

XY

(2)
2

?e~8¨W
p0,b}?E?x
?
A,
H
pA1=p0,VA1=LASa(1%)
pA2=p,VA2=(LA-d)Sa+xSb(1%)
?9_;??j

??óA??H
pa1Va1=pa2Va2(2%)
?
B,
H
pB1=p0,VB1=LBSb(1%)
pB2=p,VB2=(LB-x)Sb(1%)
?9_;??j

??óA??H
pB1VB1=pB2VB2(2%)
gh??z???
x=43d(2%)
34.(1)【
01
】ACE

23

??/ó??

?<^§W
0.2s,t=0


???8r0T&}???@??

V?

=0.25s,e
?#??yüF%?
。t=0.55s
k
,x
,??

?
6.0m
<|^?#??yüF%
!"

#
32 
$

?

??^?
??{
0.3s(
tud^§
),
?

2λ=6m,S??1 λ=4m,?? v=
20m/s,
KL

XY

KL

MN

??<^§
T=0.2s,
{t^??ét^?A
0.05s=T4,T
&J?

??á?^??λ
4,?W1m,KLCXY;?Wc、dá??%?t?1,S
??

?|?8r0}?J?k
,d
?r9?B

KL

MN
;g
??

?KJ??%?t^§

÷JtuJ?

??

?V?12cm
k
,g
?V?16cm,
KL

XY

(2)
2
:(i)
???U/?

?

??REAC
??60°
?W
sin60°=槡32>

n=
槡3
3,S?vF|AC??Bm??E,VBC??E{ED

??·??v
!"
#
!
$
%
&
'
(
???U/?
DF=L5tan60°=
槡3L
5(1%)
FG=
L-L( )5
cos30°=
槡83L
15 (1%)
GH= 槡43L15 (1%)
vF|×??hv=cn(1%)
v?

?REy?
AC
?DESV?t=DF+FG+GHv (1%)
2?
t=3Lc(1%)
(i)
?·vFER×??k??
d1=AE-AD=

5(1%)
?·vF|???h??kt?@V??U/

V
AC
??E{d2=
d1
cos60°sin30°=

5(1%)
V
BC
??E{d3=
d2
sin60°sin60°=

5(1%)
??·vF?
AC
?
5(1%)

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