江西省信丰中学2011-2012学年高二第二次月考(全科)

资源下载
  1. 二一教育资源

江西省信丰中学2011-2012学年高二第二次月考(全科)

资源简介

本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考(英语)
第一部分:听力(共两节,满分30分)
第一节(共5小题;每小题1.5分,满分7.5分)
听下面5段对话。每段对话后有一个小题,从题中所给的A、B、C三个选项选出最佳选项,并标在试卷的相应位置。听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。
1. What is the man going to do
A. To find a place to eat B. To look for a hotel C. To take a taxi
2. What do we know about the speakers
A. They want to have a cup of coffee B. They agree to have a cup of coffee the next day
C. The woman couldn’t accept the man’s suggestion
3. What is the relationship between the speakers
A. Neighbors B. Strangers C. Friends
4. What are the two speakers talking about
A. A railway station B. A cinema C. A film
5. When will Mr Brown have to be at the airport
A. By 8:30 B. By 9:30 C. By 10:30
第二节(共15小题;每小题1.5分,满分22.5分)
听下面5段对话或独白。每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。每段对话或独白读两遍。
听第6段材料,回答第6—8题。
6.Why is the girl calling
A. She wants to go to Mr Ward’s school B. She expects to see Mr Ward
C. She wants to attend Mr Ward’s lecture
7. Why does the girl want to take the course
A. Because she finds it easy for her B. Because she is a science student
C. Because she can’t study it in her own school
8. What is the problem
A. The class is already full B. The girl speaks poor English C. The girl lives far away
听第7段材料,回答第9—11题。
9. What do we know about the woman’s present company
A. It is an advertising company B. It has been moved out of London
C. It is an American company
10. Why does the woman decide to give up her job
A. She’d like to do something different B. She has never liked working here
C. She has found another job
11. What do we know about the woman
A. She has worked in the company for four years B. She may go abroad
C. She has been to America several times
听第8段材料,回答12、13题。
12. Where does the conversation take place
A. In a drug store B. In a pet shop C. In a zoo
13. What is the man complaining about
A. The woman sold him a dead cat B. The cat always sleeps
C. The cat is too tired to move
听第9段材料,回答第14—16题。
14. What is the man looking for
A. A bookstore B. A town guide C. A shoe repair shop
15. What do we know about the man
A. He is shown the wrong way B. He remembers the way wrongly at first
C. He doesn’t understand what the woman said
16. How does the woman seem to be
A. In a hurry to leave B. Curious about the man C. Plaeased to help the man
听第10段材料,回答第17—20题。
17. What has happened to Okinawa ,Japan
A. A typhoon B. A snowstorm C. An earthquake
18. How many emergency relief wokrers have been sent to the rescue in Naha
A. 700 B. 500 C. 160
19. What happened to the girl on her way to school
A. She was caught by the police B. She was beaten by her father
C. She was kidnapped
20. What is the last news about
A. Music B. Sports C. Weather
第二部分:英语知识运用(共两节,满分45分)
第一节:单项填空(共15小题,每小题1分,满分15分)
从A、B、C、D四个选项中,选出可以填入空白处的最佳选项.
21. All these changes will lead to____ better Xinfeng middle school,____ that can surprise and inspire all the alumni.
A. a; the one B. a; one C. the; one D. the; one
22. He had been so absorbed___ watching the car passing by that he didn't notice his friends ____.
A. to; coming B. in; to come C. on; coming D. in; coming
23. It's_____ that we should have to queue, when we have already got our tickets.
A. accessible B. voluntary C. appropriate D. ridiculous
24. I shall never forget those years ____ I studied in the school with my classmates and teachers,__________ has a great effect on my life.
A. that; which B. when; which C. which; that D. when; who
25. The children were not ___ for the accident. After all, they were still so young.
A. to blame B. to be blamed C. blaming D. blame
26. Soon they ____________ the water which ____________ the pipe.
A. ran out; ran out of B. ran out of; ran out of
C. ran out; ran out D. ran out of; ran out
27. Had Jack received six more votes in the election last week, he______ the chairman of the students’ union now.
A. must have been B. would have been C. were D. would be
28. I met one of my students the other day. After several years, she changed a lot and looked different from ____ she used to be.
A. that B. whom C. what D. who
29. She hesitated at the gate of the canteen, _________ whether to enter or not.
A. to wonder B. wondered C. wondering D. wonder
30. __________ the final exams, I would have gone to the concert yesterday.
A. In spite of B. But for C. Because of D. As for
31. The man is teaching in our school, but,believe it or not,he __ as a business man for 8 years.
A. worked B. was working C. had worked D. has been working
32. With many major economic problems________ to be solved, there is no point predicting the growth rate of this year now.
A. remaining B. remained C. have remained D. having remained
33. Although the necklace is just made of ordinary stones, it still ________ young people.
A. appeals to B. attracts to C. accounts for D. applies for
34. At the routine office meeting, the headmaster insisted that the problems _________ paid special attention to.
A. referred to being B. referred to be C. refer to being D. refer to be
35. ----My family usually goes skating for vacation. I like skating, but I want to try something different this year.
----
A. Let’s go. B. Cheer up. C. Like what D. Take care.
第二节:完形填空(共20小题;每小题1.5分,满分30分)
阅读下面短文,从短文后各题所给的四个选项(A、B、C、 D)中,选出可以填入空白处的最佳选项。
You may not realize it, but you are doing much more than just studying when you are at school. School is also the place 36 you socialize and learn to get along with people. But this is 37 easy. What can you do 38 you just don’t like one of your classmates
If you discover that you have problems 39 your classmates or friends, the most important thing to learn is tolerance. Tolerance is the 40 to recognize and respect the 41 in others. We cannot change the way that other people act, 42 it is important to learn to live happily with them.
Practicing tolerance will allow everyone to form better 43 with each other. Getting to know someone 44 help you understand why they do things 45 from you. It is important to remember that just because something is different does not mean that it is bad. 46 teaches us to keep an even temper and open mind.
One thing to 47 is the old saying, “Treat others how you want 48 ”. You would like to be treated kindly by your classmates, so it is 49 to treat them with equal kindness. If you tolerate 50 it does not mean that you have to like it. No one is asking you to 51 who you are or what you believe in. Tolerance just means that you will be 52 of the differences in others and not try to make them change.
It is important to 53 tolerance because it will make everyone’s lives easier. Learn to 54 people for their different abilities and interests. The world is a very 55 place, and practicing tolerance in your own school and city can help make a difference.
36. A. which B. where C. that D. when
37. A. very B. no C. not always D. really
38. A. unless B. since C. because D. if
39. A. getting along withB. making apologies toC. getting away from D. fleeing from
40. A. chance B. benefit C. patience D. ability
41. A. imaginations B. thoughts C. consequence D. differences
42. A. so B. and C. but D. although
43. A. moods B. habits C. relationships D. feelings
44. A. must B. may C. should D. can
45. A. fortunately B. easily C. differently D. attentively
46. A. Patience B. Experience C. Tolerance D. kindness
47. A. keep in touch B. keep in mind C. keep up with D. keep to yourselves
48. A. to treat B. being treated C. to be treated D. to be treating
49. A. attractive B. important C. desperate D. fantastic
50. A. something B. anything C. everything D. nothing
51. A. change B. remind C. promise D. decide
52. A. convenient B. respectful C. negative D. considerable
53. A. ignore B. cancel C. prevent D. practice
54. A. accept B. receive C. thank D. remember
55. A. diverse B. same C. individual D. apparent
第三部分:阅读理解(共20小题,每小题2分,满分40分)
阅读下面短文,从每题所给的A、B、C、D四个选项中,选出最佳选项。
A
Having good etiquette (礼节) at the workplace is very important to be a favorite in an office. However, it's observed that many people aren't aware of the workplace etiquette and this creates a very bad impression in the office. So it's important to know some workplace etiquette tips.
Among all the workplace etiquette guidelines, the most important is to be punctual to your office. Though going late due to an emergency is okay, habitual late comers are never appreciated in any organization. By arriving at your office on time, you show that you're aware of your responsibilities and have respect for the organization. In case you feel that you would be late, call the concerned authority and report the matter to him or her.
Also, a proper knowledge of the workplace email etiquette is a must. In the official emails, you need to mention the subject concisely, while at the same time include all the important details which are to be shared. You should use good and grammatically correct language while writing emails.
A knowledge of telephone etiquette in the workplace is very important as well. While talking on the telephone, be polite and listen to what they're saying carefully. Only then should you say what you feel. Speak in a voice which would be heard clearly at the other end.
The workplace guidelines are important even while you're dining or celebrating with your co-workers. If you get a call in between, receive it after you're permitted by the others by saying "excuse me". Don't talk loudly while eating. Greeting people well and try to make them feel comfortable while, being in your company.
These guidelines will help you become the best employee of a company. All the best!
56.The intended readers of the passage are___.
A.managers in charge of a company B.students of a business class
C.people who are out of work D.general readers
57.Why should you try to be punctual
A.To prove you are not a habitual late comer B.To respect the rules of the organization
C.To show that you are a responsible worker D.To win other workers’ respect.
58.How should you write an official email
A.Write the subject clearly and simply. B.Include all the details in the email.
C.Make the language as beautiful as possible. D.Make emails as brief as possible.
59.Which of the following is considered NOT acceptable about making phone calls
A.Using polite languages. B.Listening with patience and care.
C.Speaking clearly. D.Answering a call whenever it comes in.
60.In the writer’s opinion, workplace etiquette .
A.is easy to master B.is considered important by all employees
C.can be helpful in doing your work well D.will bring you good luck and good salaries
B
After lots of hope, the new iPhone 3GS has arrived, boasting an improved camera, better battery life, and speedier performance. But is it a must
The iPhone 3GS is available in two versions: 16GB and 32GB. The 16GB version costs $199, while the 32GB version costs $299. From the outside, the iPhone 3GS looks exactly like the iPhone 3G. Like the iPhone 3G, the new model comes in black and white versions, and sports a 3.5-inch touch screen. Most of the changes to the iPhone 3GS have been made on the inside. Apple says that battery life is better, but the biggest boost is in the iPhone's speed: The iPhone 3GS runs twice as fast as the iPhone 3G. Instead of a lot of software installed on it, the iPhone 3GS comes with the most recent version of the iPhone Software -- version 3.0 – installed, but it does come with easy access to Apple's App Store. The speedier performance of the iPhone 3GS extends to surfing the Web, too. You can see entire Web pages, and can zoom(急速移动) in and out with ease.
The notable new messaging feature on the iPhone 3GS is support for MMS. You can send pictures and videos by SMS, rather than having to send them via e-mail. Other new and very-handy e-mail features include the ability to search through your e-mail messages and contacts, as well as the option to use a landscape-oriented keyboard when composing messages.
The camera has been upgraded from 2 megapixels(兆像素) to 3 megapxiels, and adds auto-focus. If you already own an iPhone 3G, the iPhone 3GS may not be worth the additional cost, since you can get many of its cool features for free with the iPhone 3.0 software upgrade. But if you've been using an older iPhone or smart phone, or are new to the smart phone world, the iPhone 3GS will amaze you with its speed and plentiful features.
61. The difference between 3G and 3GS lies mainly in ________.
A. their colors B. their outside shapes
C. their screens D. their batteries and speeds
62. What can we infer from the second paragraph about 3G
A. It offers an easy access to the web pages .B. It has two versions: either black or white.
C. In spite of slow speed, it functions the same as 3GS.
D. It has the latest iPhone software installed.
63. What does MMS probably refer to in the passage
A. Multi-media Messaging Service. B. Membership Management System.
C. Major Messaging Software. D. Multi-Media Software Store.
64. According to the text, what is the notable advantage 3GS has in messaging
A. Pictures and videos can be sent more quickly.
B. Pictures and videos can be sent through SMS.
C. It’s more convenient to send and receive messages.
D. It’s more convenient to compose messages via keys.
65. What is the best title of the text
A. 3GS is a must nowadays. B. 3GS is the best choice nowadays.
C. Is 3GS a must nowadays D. Is 3GS worth your money
C
A person may have an idea about himself that will prevent him from doing good work. He may have the idea that he is not capable of it. A child may think he is stupid because he does not understand how to make the most of his mental faculties(机能), or he may accept another person's mistaken estimate(评价) of his ability. Older people may be handicapped(阻碍) by the mistaken belief that they are incapable of learning anything new because of their age.
A person who believes that he is incapable will not make a real effort, because he feels that it would be useless. He won't go at a job with the confidence necessary for success. He is therefore likely to fail, and the failure will strengthen his belief in his incompetence. Alfred Adler, a famous doctor, had an experience which illustrates this. When he was a small boy he got off to a poor start in arithmetic. His teacher got the idea that he had no ability in arithmetic, and told his parents what she thought in order that they would not expect too much of him. In this way, they too developed the idea, “Isn't it too bad that Alfred can't do arithmetic?” He accepted their mistaken estimate of his ability, felt that it was useless to try,and was very poor at arithmetic, just as they expected.
One day Adler succeeded in solving a problem which none of the other students had been able to solve. This gave him confidence. He rejected the idea that he couldn't do arithmetic and was determined to show them that he could. His new found confidence stimulated him to go at arithmetic problems with a new spirit. He now worked with interest, determination and purpose, and he soon became extraordinary good at arithmetic.
This experience made him realize that many people have more ability than they think they have, and that lack of success is as often the result of lack of knowledge of how to apply one's ability, lack of confidence, and lack of determination as it is the result of lack of ability.
66.Why might a person be prevented from doing good work ________.
A. Because he thinks he is old enough to make the most of his mental facilities
B. Because he accepts another person's mistaken estimate of his ability
C. Because he has the idea that he is incapable of doing everything
D. Because he believes in what other people think of him
67.A person who believes in his low ability will ________.
A. spare no efforts to do things B. fail to go at a job but never lose heart
C. change to learn other course instead of mathematics D. show complete lack of confidence
68.As a boy, Alfred Adler was poor at arithmetic because ________.
A. he lost his self- confidence B. he was weak in thinking
C. his parents expected too much of him D. his teacher had no confidence in herself
69.Which of the following is the most important factor to Alder's success?________
A. Spirit and experience B. Interest and self -respect
C. Confidence and determination D. Purpose and knowledge
70.Alder's experience made him realize that ________.
A. people are not as capable as they think B. people can be more capable than they think
C. lack of confidence leads to failure D. lack of ability results in lack of determination
D
Exercise may hold the key to youth, according to a study published recently which showed people who keep fit are up to nine years biologically younger than those who do not.
The findings are the first to show in humans how keeping fit affects the ageing process.
The study of 2,401 twins found that a sedentary (惯于久坐的) lifestyle raises the risk of a range of problems from heart disease to cancer and appears to play a key role in the ageing process.
It all appears to boil down to the length of structures called telomeres-which protect the DNA on the chromosomes(染色体), the researchers from King's College London wrote in the Archives of Internal Medicine.
Many studies have shown telomeres get shorter over time, suggesting the cells are ageing or dying. The study, which extracted a DNA sample from their volunteers, found people who exercised more each week had longer telomeres.
Exercise lowers the risk of a range of problems such as heart disease, diabetes(糖尿病)
and cancer, the researchers said.
“It is not just walking around the block. It is really working up a sweat,” said Tim Spector, a genetic epidemiologist(流行病学家) who led the study, in a telephone interview.
The study found people who exercised vigorously 3 hours each week had longer telomeres and they were 9 years biologically younger than people who did under 15 minutes.
Spector’s team, who also adjusted for body weight, smoking, economic status and physical activity at work, also said moderate exercise for 1-1/2 hours each week provided a four-year advantage.
The reason why exercise has this effect is not clear but we believe physical activity somehow defends against the natural process.
71. Which of the following would be the best title of the passage
A. Lifestyle affects people’s health B. Physical activity prevents diseases
C. Exercise keeps you younger D. Sitting long suffers from cancer
72. According to the study, people sitting long .
A. are tending to be more healthy B. are more likely to live longer
C. are inclined to be taken ill D. are getting old more slowly
73. The underlined phrase “boil down to” most probably means .
A. lie in B. lead to C. aim at D. show up
74. Which of the following statements are NOT true
A. Telomeres get shorter as time goes on.
B. Slight walking prevents people getting ill.
C. Exercise energetically reduces the chance of diseases.
D. Body weight, smoking and economic status affect people’s health.
75. It can be inferred from the passage that .
A. people’s health is decided by their body weight and economic status
B. scientists have known why exercise affects the ageing process
C. the more violently one exercises, the healthier one gets
D. the longer telomeres one has, the more slowly one gets old
第四部分:写作(共两节,满分35分)
第一节 阅读表达 (共5小题,每小题2分,满分10分)
阅读下面短文,请根据短文后的要求进行答题。(请注意问题后的字数要求)
[1]Swimming is one of those activities that can be learned early in life. Little children can learn to swim as soon as they walk. In fact, you need the same skills in walking as in swimming. However, I believe that five is the best age to learn. By five or six, a child knows fear of water, a very important thing to know. It’s wise to be afraid, to recognize true danger. Young ones understand that the water can sometimes be very dangerous.
[2]To really benefit from swimming, every swimmer should learn ______:butterfly, backstroke, breaststroke, and crawl. I feel that one of these—the breaststroke—is different from the others, since some young swimmers use this stroke naturally, without any training.
[3]In swimming, there are certain rules every swimmer should follow:
(1)Never swim alone! No matter how good you are in the water, don’t risk drowning by swimming alone. If you swim by yourself, with no life guards or friends with you, you may get into trouble.
(2)Don’t go beyond your abilities. Most swimmers know enough not to swim too far from the bank or the beach. Showing off by doing dangerous tricks is no good. Swim safely and you will continue to swim and alive.
(3)Don’t smoke. Swimming depends on a healthy body; good lungs are part of it.
(4)Work at any activity that builds muscles.
76.What is the main idea of the passage (no more than 10 words)
___________________________________________________________
77.Please complete the following statement with proper words .(no more than 5 words)
____________________________and the recognition of its danger are sensible.
78.Fill in the blank in Paragraph 2 with proper words. (no more than 7 words)
______________________________________________________________
79.Why should not you swim alone according to the passage ( no more than 10 words)
_________________________________________________________________
80.What does the word “it” (Line 8, Paragraph 3) probably refer to (no more than 3 words)
_________________________________________________________________
第二节 书面表达(满分25分)
“贫困对于儿童是好的教科书”,但是有些家长的心情十分矛盾。
一方面,家长们想为孩子创造舒适的生活和学习环境。另一方面,又怕如此娇生惯养,孩子被宠坏,缺乏好素质,将来没出息。
要求:
1.请以“Hard life is good for children”为题,讲述“吃苦”的好处,给出一些建议,帮助家长消除疑虑。
2.词数:120左右(不包括已给出的短文开头)
Hard life is good for children
Nowadays,quite a lot of parents are in a dilemma(窘境).On one hand
____________________________________________________________________
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考
(数学理)
一、选择题(每小题5分,共50分)
1.若为实数,则“”是的( )
A.充分而不必要条件 B.必要而不充分条件
C.充分必要条件 D.既不充分也不必要条件
2. 下列说法正确的是(  )
A.命题“若x2=1,则x=1”的否命题为:“若x2=1,则x≠1”
B.“x=-1”是“x2-5x-6=0”的必要不充分条件
C.命题“存在x∈R,使得x2+x+1<0”的否定是:“对任意x∈R, 均有3x2+x+1<0”
D.命题“若x=y,则sinx=siny”的逆否命题为真命题
3. 已知直二面角α-l-β,点A∈α,AC⊥l,C为垂足.点B∈β,BD⊥l,D为垂足.若AB=2,AC=BD=1,则D到平面ABC的距离等于(  )
A. B. C. D.1
4.有3个兴趣小组,甲、乙两位同学各自参加其中一个小组,每位同学参加各个小组的可能性相同,则这两位同学参加同一个兴趣小组的概率为 ( )
(A) (B) (C) (D)
5. 设圆C与圆x2+(y-3)2=1外切,与直线y=0相切,则C的圆心轨迹为(  )
A.抛物线 B.双曲线 C.椭圆 D.圆
6.设双曲线的左准线与两条渐近线交于A,B两点,左焦点在以AB为直径的圆内,则该双曲线的离心率的取值范围为(  )
A.(0,) B.(1,) C. D.(,+∞)
7.已知抛物线y2=4x上两个动点B、C和点A(1,2),且∠BAC=900,则动直线BC必过定点( )A,(2,5) B,(-2,5) C,(5,-2) D,(5,2)
8.放射性元素由于不断有原子放射出微粒子而变成其他元素,其含量不断减少,这种现象成为衰变,假设在放射性同位素铯137的衰变过程中,其含量(单位:太贝克)与时间(单位:年)满足函数关系:,其中为时铯137的含量,已知时,铯137的含量的变化率是(太贝克/年),则
A. 5太贝克 B. 太贝克 C. 太贝克 D. 150太贝克
9. 已知平面α截一球面得圆M,过圆心M且与α成60°二面角的平面β截该球面得圆N.若该球面的半径为4,圆M的面积为4π,则圆N的面积为(  )
A.7π B.9π C.11π D.13π
10.设直线与函数的图像分别交于点,则当达到最小时的值为( )
A.1 B. C. D.
二、填空题(每小题5分,共25分)
11.盒中装有形状、大小完全相同的5个球,其中红色球3个,黄色球2个。若从中随机取出2个球,则所取出的2个球颜色不同的概率等于_______。
12.观察下列等式
1=1
2+3+4=9
3+4+5+6+7=25
4+5+6+7+8+9+10=49
……
照此规律,第个等式为 。
13. 若椭圆+=1的焦点在x轴上,过点作圆x2+y2=1的切线,切点分别为A,B,直线AB恰好经过椭圆的右焦点和上顶点,则椭圆方程是________.
14.曲线C是平面内与两个定点F1(-1,0)和F2(1,0)的距离的积等于常数a2(a>1)的点的轨迹,给出下列三个结论:
①曲线C过坐标原点;
②曲线C关于坐标原点对称;
③若点P在曲线C上,则△F1PF2的面积不大于a2.
其中,所有正确结论的序号是________.
15.如图,直角坐标系xOy所在的平面为α,直角坐标系x′Oy′(其中y′轴与y轴重合)所在的平面为β,∠xOx′=45°.
(1)已知平面β内有一点P′(2,2),则点P′在平面α内的射影P的坐标为________;
(2)已知平面β内的曲线C′的方程是(x′-)2+2y′2-2=0,则曲线C′在平面α内的射影C的方程是______________.
三、解答题(共75分)
16.(12分)在交AC于 点D,现将
(1)当棱锥的体积最大时,求PA的长;
(2)若点P为AB的中点,E为
17.(12分)已知函数.
(1)求的单调区间;
(2)若对,,都有,求的取值范围。
18.(12分)设λ>0,点A的坐标为(1,1),点B在抛物线y=x2上运动,点Q满足=λ,经过点Q与x轴垂直的直线交抛物线于点M,点P满足=λ,求点P的轨迹方程.
19.(12分)设数列{an}的前n项和为Sn,且方程x2-anx-an=0有一根为
Sn-1,n=1,2,3,….
(Ⅰ)求a1, a2; (Ⅱ){an}的通项公式.
20.(13分)如图,在四棱锥P-ABCD中,PA⊥平面ABCD,底面ABCD是菱形,AB=2,∠BAD=60°.
(1)求证:BD⊥平面PAC;
(2)若PA=AB,求PB与AC所成角的余弦值;
(3)当平面PBC与平面PDC垂直时,求PA的长.
21.(14分)如图,椭圆C1:+=1(a>b>0)的离心率为,x轴被曲线C2:y=x2-b截得的线段长等于C1的长半轴长.
(1)求C1,C2的方程;
(2)设C2与y轴的交点为M,过坐标原点O的直线l与C2相交于点A,B,直线MA,MB分别与C1相交于点D,E.
①证明:MD⊥ME;
②记△MAB,△MDE的面积分别为S1,S2.问:是否存在直线l,使得=?请说明理由.
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考
(物理)
一、选择题(每小题4分,共48分,每小题至少有一个正确答案,多选或错选得零分,少选、漏选得2分)
1.下列静电学公式中,F、q、E、U、r和d分别表示电场力、电量、场强、电势差以及距离① ② ③ ④ 则下列说法中正确的是( )
A、它们都只对点电荷或点电荷的场才成立
B、①②③只对点电荷或点电荷的场成立,④只对匀强电场成立
C、①②只对点电荷成立,③对任何电场都成立,④只对匀强电场才成立
D、①②只对点电荷成立,③④对任何电场都成立
2.阴极射线管电视机的玻璃荧光屏表面经常有许多灰尘,这主要是因为( )
A.灰尘的自然堆积
B.玻璃有较强的吸附灰尘的能力
C.电视机工作时,屏表面温度较高而吸附灰尘
D.电视机工作时,屏表面有静电而吸附灰尘
3、两个放在绝缘架上的相同金属球,相距r,球的半径比r小得多,带电量大小分别为q和3q,相互斥力为3F。现将这两个金属球相接触,然后分开,仍放回原处,则它们之间的相互作用力将变为( )
A、F B、4F/3 C、F/3 D、4F
4. 如图所示,匀强电场的场强E=3×105V/m,A、B两点相距0.2m,两点连线与电场的夹角是600,下列说法正确的是( )
A. 电荷量q=+2×10-4C的电荷从A点运动到B点电势能增大6J
B.电荷量q=-2×10-4C的电荷从A点运动到B点电场力做功为-6 J
C. 若取A点的电势为0,则B点的电势φB=3×104V
D. A、B两点间的电势差是UAB=6×104V
5.下列说法正确的是 ( )
A.若在某区域内通电导线不受磁场力的作用,则该区域的磁感应强度一定为零
B.磁感应强度越大的地方,线圈面积越大,则穿过线圈的磁通量越大
C.磁感线总是由N极出发指向S极
D.在闭合电路中,电动势等于路端电压与电源内部电势降落之和
6.如图,接通电键K的瞬间,用丝线悬挂于一点,可自由转动的通电直导线AB 将 ( )
A.A端向上,B端向下,悬线张力不变
B.A端向下,B端向上,悬线张力变小
C.A端向纸内,B端向纸外,悬线张力变小
D. A端向纸外,B端向纸内,悬线张力变大
7.在研究微型电动机的性能时,应用如图所示的实验电路.当调节滑动变阻器R并控制电动机停止转动时,电流表和电压表的示数分别为0.50A和2.0V.重新调节R并使电动机恢复正常运转,此时电流表和电压表的示数分别为2.0A和24.0V。则这台电动机正常运转时输出功率为( )
A.32W B.44W C.47W D. 48W
8.一质子以速度V穿过互相垂直的电场和磁场区域而没有发生偏转,则 ( )
A.若电子以相同速度V射入该区域,将会发生偏转
B.无论何种带电粒子(不计重力),只要以速度V射入都不会偏转
C.若质子的速度V′D.若质子的速度V′>V,它将向上偏转,其运动轨迹既不是圆弧也不是抛物线。
9.如图所示,在加有匀强磁场的区域中,一垂直于磁场方向射入的带电粒子轨迹如图所示,由于带电粒子与沿途的气体分子发生碰撞,带电粒子的动能逐渐减小(带电量不变),则正确的是 ( )
A.带正电,是从B点射入的 B.带负电,是从B点射入的
C.带负电,是从A点射入的 D.带正电,是从A点射入的
10如图所示,在垂直纸面向里的匀强磁场的边界上,有两个质量和电量均相同的正、负离子(不计重力),从点O以相同的速度先后射入磁场中,入射方向与边界成角,则正、负离子在磁场中 ( )
A.运动时间相同
B.运动轨迹的半径相同
C.重新回到边界时速度的大小和方向相同
D.重新回到边界的位置与O点距离不相等
11.回旋加速器是获得高能带电粒子的装置. 其核心部分是分别与高频交流电源的两极相连的
两个D形盒,两盒间的狭缝中形成周期性变化的电场,使粒子在通过狭缝时都能得到加速,
两D形金属盒处于垂直于盒底的匀强磁场中.关于回旋加速器,下列说法中正确的( )
A.带电粒子做一次圆周运动,要被加速两次,因此交变电场的周期应为圆周运动周期的二倍
B.用同一回旋加速器分别加速不同的带电粒子,一般要调节交变电场的频率
C.狭缝间的电场对粒子起加速作用,因此加速电压越大,带电粒子从D形盒射出时的动能越大
D.磁场对带电粒子的洛伦兹力对粒子不做功,因此带电粒子从D形盒射出时的动能与磁场的强弱无关
12磁流体发电是一项新兴技术,它可以把气体的内能直接转化为电能,下图是它的示意图.平行金属板A、B之间有一个很强的匀强磁场,磁感应强度为B,将一束等离子体(即高温下电离的气体,含有大量正、负带电粒子)垂直于B的方向喷入磁场,每个离子的速度为v,电荷量大小为q,A、B两板间距为d,稳定时下列说法中正确的是( )
A.图中A板是电源的正极 B.图中B板是电源的正极
C.电源的电动势为Bvd D.电源的电动势为Bvq
二、填空题(每空3分,共18分)
13.请分别写出游标卡尺和螺旋测微器对应的读数
14某同学测量一只未知阻值的电阻。
(1)他先用多用电表进行测量,按照正确的步骤操作后,测量的结果如图甲所示。请你读出其阻值大小为_____________。为了使多用电表测量的结果更准确,该同学接着应该换用____________挡,并重新调零后再测量。
(2)若该同学再用“伏安法”测量该电阻,所用器材如图乙所示,其中电压表内阻约为5kΩ,电流表内阻约为5Ω,变阻器阻值为50Ω。图中部分连线已经连接好,为了尽可能准确地测量电阻,请你完成其余的连线。
(3)该同学按照“伏安法”测量电阻的要求连接好图乙电路后,测得的电阻值将____________(填“大于”、“小于”或“等于”)被测电阻的实际阻值。
三、计算题:(本题共3小题,共计34分。解答时请写出必要的文字说明、方程式和重要的演算步骤.只写出最后答案的不能得分.有数值的题,答案中必须明确写出数值和单位)。
15(10分).如图所示为质谱仪的原理图,A为粒子加速器,电压为U1;B为速度选择器,磁场与电场正交,磁感应强度为B1,板间距离为d;C为偏转分离器,磁感应强度为B2。今有一质量为m、电量为q的正离子经加速后,恰好通过速度选择器,进入分离器后做匀速圆周运动,求:
⑴粒子的速度v
⑵速度选择器的电压U2
⑶粒子在B2磁场中做匀速圆周运动的半径R
16.(12分)如图所示,两平行金属导轨间的距离L=0.40 m,金属导轨所在的平面与水平面夹角θ=37°,在导轨所在平面内,分布着磁感应强度B=0.50 T、方向竖直向上的匀强磁场.金属导轨的一端接有电动势E=4.5 V、内阻r=0.50 Ω的直流电源.现把一个质量m=0.06 kg的导体棒ab放在金属导轨上,导体棒恰好静止.导体棒与金属导轨垂直、且接触良好,导体棒与金属导轨接触的两点间的电阻R0=2.5 Ω,金属导轨电阻不计,g取10 m/s2.已知sin 37°=0.60,cos 37°=0.80,求:
(1)导体棒两端的电势差.
(2)导体棒受到的安培力和摩擦力.
(3)若斜面光滑,欲使导体棒静止在斜面上,求所加匀强磁场的最小值及方向.
17(12分)如图所示,一束带电量为q的粒子(电性未知)以垂直于磁感应强度B并垂直于磁场边界的速度v0射入宽度为d的匀强磁场中,穿出磁场时速度方向和原来射入方向的夹角为θ=300.求:
(1)请判断粒子电性并求出粒子的质量;
(2)粒子穿越磁场的时间;
(3)欲使粒子从右边界射出,其速度v必须满足什么条件.
参考答案及评分标准
13.104.05 1.880
14(1) 1000欧姆 X100
(2)
(3) 大于(2分)
15 (13分)
(2)粒子在磁场中做圆周运动 洛伦兹力提供向心力
(2分)
得: (2分)
所以穿越磁场的时间 ( 1分)
(3)粒子从右边界射不出去的临界图 如右图所示:
由图知粒子的半径r=d (2分)
此时粒子的速度 (1分)
所以粒子要从右边界射出去速度满足v > (2分)
17. (15分)
⑴粒子经加速电场U1加速,获得速度V,由动能定理得:
qU1=mv2 解得v= ( 4分)
⑵在速度选择器中作匀速直线运动,电场力与洛仑兹力平衡得Eq=qvB1即 (2分)
U2=B1dv=B1d (3分)
⑶在B2中作圆周运动,洛仑兹力提供向心力, (2分)
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
mm
mm mmmmmmmmmmm
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考
(化学)
一、选择题(本题共18小题,每小题3分,在每小题只有一个选项正确)
1、下列物质的水溶液能导电,但属于非电解质的是( )
A.CH3CH2COOH B.Cl2 C.NH4HCO3 D.SO2
2、25 ℃时,水的电离达到平衡:H2OH++OH-; △H>0,下列叙述正确的是 ( )
A.向水中加入稀氨水,平衡逆向移动,c(OH-)降低
B.向水中加入少量固体硫酸氢钠,c(H+)增大,KW不变
C.向水中加入少量固体CH3COONa,平衡逆向移动,c(H+)降低
D.将水加热,KW增大,pH不变
3、能证明醋酸是弱酸的是( )
①醋酸能使紫色石蕊试液变红.②醋酸能被氨水中和③醋酸钠溶液的pH大于7
④常温下,0.10mol·L-1醋酸溶液中的c(H+)为1.32×10-3mol·L-1
A. ① ③ ④. B. ② ③ C. ③ ④. D. ① ④
4、下列过程或现象与盐类水解无关的是( )
A.纯碱溶液去油污 B.铁在潮湿的环境下生锈
C.加热氯化铁溶液颜色变深 D.浓硫化钠溶液有臭味
6、下列各组离子一定能大量共存的是( )
A.在含有大量AlO2-的溶液中:NH4+、Na+、Cl-、H+ B.在强碱溶液中:Na+、K+、CO32-、NO3
C.在pH=12的溶液中:NH4+、Na+、SO42-、Cl-
D.在c(H+)=0.1mol·L-1的溶液中:K+、I-、Cl-、NO3-
7、化学用语是学习化学的重要工具,下列用来表示物质变化的化学用语中,正确的是( )
A.电解饱和食盐水时,阳极的电极反应式为:2Cl - -2e -==Cl2 ↑
B.氢氧燃料电池的负极反应式:O2 + 2H2O + 4e- == 4OH -
C.粗铜精炼时,与电源正极相连的是纯铜,电极反应式为:Cu-2e- == Cu2+
D.钢铁发生电化学腐蚀的正极反应式:Fe-2e - == Fe2+
8、下列溶液中各微粒的浓度关系不正确的是( )
A.0.1 mol·L-1 HCOOH溶液中:c(HCOO-)+c(OH-)=c(H+)
B.1 L 0.l mol·L-1CuSO4·(NH4)2SO4·6H2O溶液中:c(SO42-)>c(NH4+)>c(Cu2+)>c(H+)>c(OH-)
C.等体积、等物质的量浓度的醋酸和醋酸钠混合后的溶液中:c(CH3COO-)>c(Na+) >c(H+)>c(OH-)
D.0.1 mol·L-1NaHCO3溶液中:c(Na+)+c(H+)+c(H2CO3)=c(CO)+c(OH-)
9、下列说法不正确的是( )
A.已知冰的熔化热为6.0 kJ/mol,冰中氢键键能为20 kJ/mol,假设1 mol冰中有2 mol 氢键,且熔化热完全用于破坏冰的氢键,则最多只能破坏冰中15%的氢键
B.已知一定温度下,醋酸溶液的物质的量浓度为c,电离度为α,。若加入少量醋酸钠固体,则CH3COOHCH3COO-+H+向左移动,α减小,Ka变小
C.实验测得环己烷(l)、环己烯(l)和苯(l)的标准燃烧热分别为-3916 kJ/mol、-3747 kJ/mol和-3265 kJ/mol,可以证明在苯分子中不存在独立的碳碳双键
D.已知:Fe2O3(s)+3C(石墨)2Fe(s)+3CO(g),△H=+489.0 kJ/mol。
CO(g)+O2(g)CO2(g),△H=-283.0 kJ/mol。
C(石墨)+O2(g)CO2(g),△H=-393.5 kJ/mol。
则4Fe(s)+3O2(g)2Fe2O3(s),△H=-1641.0 kJ/mol
10、据报道,我国拥有完全自主产权的氢氧燃料电池车将在奥运会期间为运动员提供服务。某种氢氧燃料电池的电解液为KOH溶液。下列有关电池的叙述不正确的是( )
A.正极反应式为:O2+2H2O+4e- ===4OH- B.工作一段时间后,电解液中的KOH的物质的量不变
C.该燃料电池的总反应方程式为:2H2+O2===2H2O
D.用该电池电解CuCl2溶液,产生2.24LCl2(标准状况)时,有0.1mol电子转移
11、一种常用的泡沫灭火器构造如下图。内筒a是玻璃瓶,外筒b是钢瓶,平时泡沫灭火器内筒外筒盛有液态试剂,当遇火警时,将灭火器取下倒置,内外筒液体试剂立即混合产生大量CO2泡沫灭火,从液态试剂在灭火器中长久放置和快速灭火两个角度分析,盛放药品正确的是( )
A.a中盛饱和Na2CO3溶液,b中盛Al2(SO4)3溶液
B.a中盛饱和NaHCO3溶液,b中盛Al2(SO4)3溶液
C.a中盛Al2(SO4)3溶液,b中盛饱和Na2CO3溶液
D.a中盛Al2(SO4)3溶液,b中盛饱和NaHCO3溶液
12、一定条件下,下列反应中水蒸气含量随反应时间的变化趋势符合题图10 的是
A.CH3CH2OH (g)CH2=CH2(g)+H2O(g); △H>0
B.CO2(g)+H2(g)CO(g)+H2O(g); △H>0
C. CO2(g)+2NH3(g)CO(NH2)2(s)+H2O(g); △H<0
D.2C6H5CH2CH3(g)+O2(g)2 C6H5CH=CH2(g)+2H2O(g); △H<0
13、研究人员最近发现了一种“水”电池,这种电池能利用淡水与海水之间含盐量差别进行发电,在海水中电池总反应可表示为:5MnO2+2Ag+2NaCl=Na2Mn5O10+2AgCl,下列“水” 电池在海水中放电时的有关说法正确的是:( )
A.正极反应式:Ag+Cl--e-=AgCl B.每生成1 mol Na2Mn5O10转移2 mol电子
C.Na+不断向“水”电池的负极移动 D. AgCl是还原产物
14、某小组为研究电化学原理,设计如图2装置。下列叙述不正确的是()
A、a和b不连接时,铁片上会有金属铜析出
B、a和b用导线连接时,铜片上发生的反应为:Cu2++2e-= Cu
C、无论a和b是否连接,铁片均会溶解,溶液从蓝色逐渐变成浅绿色
D、a和b分别连接直流电源正、负极,电压足够大时,Cu2+向铜电极移动
15、25℃、101kPa 下:①2Na(s)+1/2O2(g)=Na2O(s) △H1=-414KJ/mol
②2Na(s)+O2(g)=Na2O2(s) △H2=-511KJ/mol
下列说法正确的是( )
A.①和②产物的阴阳离子个数比不相等 B.①和②生成等物质的量的产物,转移电子数不同
C.常温下Na与足量O2反应生成Na2O,随温度升高生成Na2O的速率逐渐加快
D.25℃、101kPa 下,Na2O2(s)+2 Na(s)= 2Na2O(s) △H=-317kJ/mol
16、室温下,将1.000mol·L-1盐酸滴入20.00mL 1.000mol·L-1氨水中,溶液pH和温度随加入盐酸体积变化曲线如下图所示。下列有关说法正确的是( )
A. a点由水电离出的c(H+)=1.0×10-14mol/L
B. b点:c(NH4+)+c(NH3·H2O)=c(Cl-)
C.c点:c(Cl-)= c(NH4+)
D.d点后,溶液温度略下降的主要原因是NH3·H2O电离吸热
17、某温度时,BaSO4在水中的沉淀溶解
平衡曲线如图所示。下列说法正确的是( )
A.加入Na2SO4可以使溶液由a点变到b点
B.通过蒸发可以使溶液由d点变到c点
C.d点无BaSO4沉淀生成
D.a点对应的Ksp大于c点对应的Ksp
18、可逆反应①X(g)+2Y(g)2Z(g) 、②2M(g)N(g)+P(g)分别在密闭容器的两个反应室中进行,反应室之间有无摩擦、可滑动的密封隔板。反应开始和达到平衡状态时有关物理量的变化如图所示:
下列判断正确的是
A.反应①的正反应是吸热反应 B.达平衡(I)时体系的压强与反应开始时体系的压强之比为14:15
C. 达平衡(I)时,X的转化率为 D. 在平衡(I)和平衡(II)中M的体积分数相等
第Ⅱ卷(共计46分)
二、填空题:
19、(6分)纯水中c(H+)=5.0×10-7mol/L,则此时纯水中的c(OH-) =_______________;若温度不变,滴入稀硫酸使c(H+)=5.0×10-3mol/L,则c(OH-) =_______________;在该温度时,往水中滴入NaOH溶液,溶液中的C(OH-)=5.0×10-2 mol/L,则溶液中c(H+)= 。
20.(8分)(1)今有2H2+O22H2O反应,构成燃料电池,则负极通的应是________,正极通的应是________,电极反应式为________,__________。
(2)若把KOH溶液改为稀H2SO4作电解质溶液,则电极反应式为________,________。
(3)现有电解质溶液:①Na2CO3 ②NaHCO3 ③CH3COONa ④ NaOH(填编号,以下相同)
①当四种溶液的pH相同时,其物质的量浓度由大到小的顺序是
②在上述四种电解质溶液中,分别加入AlCl3溶液,无气体产生的是
21、(10分)氯碱厂电解饱和食盐水制取NaOH溶液的工艺流程示意图如下所示,完成下列填空:
(1)在电解过程中,与电源正极相连的电极上电极反应为____________,与电源负极相连的电极附近,溶液pH_________(选填“不变”、“升高”或“下降”)。
(2)工业食盐含Ca2+、Mg2+等杂质,精制过程发生反应的离子方程式为
____________________________________________________________。
(3)如果粗盐中SO42-含量较高,必须添加钡试剂除去SO42-,该钡试剂可以是_________。
a. Ba(OH)2 b. Ba(NO3)2 c. BaCl2
(4)为了有效除去Ca2+、Mg2+、SO42-,加入试剂的合理顺序为_________(选填a、b、c)
a. 先加NaOH,后加Na2CO3,再加钡试剂
b. 先加NaOH,后加钡试剂,再加Na2CO3
c. 先加Na2CO3,后加NaOH,再加钡试剂
22、(14分)科学家利用太阳能分解水生成的氢气在催化剂作用下与二氧化碳反应生成甲醇,并开发出直接以甲醇为燃料的燃料电池。已知H2(g)、CO(g)和CH3OH(l)的燃烧热△H分别为-285.8kJ·mol-1、-283.0kJ·mol-1和-726.5kJ·mol-1。请回答下列问题:
(1)用太阳能分解10mol水消耗的能量是_____________kJ;
(2)甲醇不完全燃烧生成一氧化碳和液态水的热化学方程式为_____ _______;
(3)在溶积为2L的密闭容器中,由CO2和H2合成甲醇,在其他条件不变得情况下,考察温度对反应的影响,实验结果如下图所示(注:T1、T2均大于300℃);
下列说法正确的是________(填序号)
①温度为T1时,从反应开始到平衡,生成甲醇的平均速率为:v(CH3OH)=mol·L-1·min-1
②该反应在T1时的平衡常数比T2时的小 ③该反应为放热反应
④处于A点的反应体系从T1变到T2,达到平衡时增大
(4)在T1温度时,将1molCO2和3molH2充入一密闭恒容器中,充分反应达到平衡后,若CO2转化率为a,则容器内的压强与起始压强之比为______;
(5)在直接以甲醇为燃料电池中,电解质溶液为酸性,负极的反应式为________、正极的反应式为________。理想状态下,该燃料电池消耗1mol甲醇所能产生的最大电能为702.1kJ,则该燃料电池的理论效率为________(燃料电池的理论效率是指电池所产生的最大电能与燃料电池反应所能释放的全部能量之比)
三、计算题
23.(8分)常温下电解200 mL NaCl与CuSO4的混合溶液,所得气体的体积随时间变化如下图所示,根据图中信息回答下列问题。(气体体积已换算成标准状况下的体积,且忽略气体在水中的溶解和溶液体积的变化)
(1)图中曲线________(填Ⅰ或Ⅱ)表示阳极产生气体的变化。
(2)计算NaCl和CuSO4的物质的量浓度。
(3)计算t2时所得溶液的pH。
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考(政治)
本卷分为第Ⅰ卷(选择题)和第Ⅱ卷(主观题)两部分
满分:100分,测试时间:100分钟。
一、最佳选择题。在以下各题所列出的四个选项中,选出最符合题意的一项。每小题2分,共50分。
1、下列关于世界观的表述正确的是( )
A.世界观是人们对整个世界以及人和世界关系的根本观点、根本看法
B.世界观只有哲学家才有
C.对世界某一方面的看法就是世界观 D.世界观就是哲学
2、“几十年的经验使我深刻体会到,学点哲学的确可以使人做事情少犯错误,做研究少走弯路。”下列观点与“国家最高科技奖”获得者李振声的上述感悟相一致是( )
A.哲学是各门具体科学的基础 B.哲学是人类对某一具体领域规律的概括
C.哲学是科学的世界观和方法论D.哲学具有指导人们认识世界和改造世界的功能
3、唯物主义和唯心主义是两种根本对立的哲学派别。其根本区别在于 ( )
A.是否承认世界具有可知性 B.是否承认意识对物质具有能动作用
C.是否承认物质决定意识 D.是否承认意识能够直接作用于物质
4、下列说法正确反映思维和存在的关系的是( )
A、眼开则花明,眼闭则花寂 B、“形存而神存,形谢则神灭”
C、神灵天意决定着社会的变化 D、“物是观念的集合”
5、对于日全食的时间和最佳观测地点,全球及我国许多的天文机构及专家早有了精确的预报,与古时人们对其现象与本质不能认识形成鲜明对比。这体现了哲学基本问题上的
A.辩证法与形而上学的统一 B.思维与存在何为第一性
C.唯物主义与唯心主义的对立 D.思维与存在有没有同一性
6、任何哲学都是 ( )
①一定社会和时代的精神生活的构成部分 ②一定社会和时代的经济和政治在精神上的反映 ③自己时代的精神上的精华 ④社会变革的先导
A. ①③④ B. ①② C. ①②③ D. ②③④
7、邓小平同志有两句名言:一句是“摸着石头过河”,另一句是“看准了的,就大胆地试,大胆地闯。”也就是说,要具备理论创新的勇气,敢于走前人没有走过的道路,大胆地向前闯,大胆地去实践。这体现了马克思主义哲学是( )
A、科学性和革命性的统一 B、辩证的自然观和历史观的统一
C、继承性和发展性的统一 D、客观性和主观性的统一
8、哲学上的物质概念是指( )
A、具体的物质形态 B、无法被人感知的客观存在
C、人们能看得见、摸得着 D、在意识之外独立存在的客观实在
9、马克思主义认为,社会的存在与发展不同于自然界,社会活动是有意识的活动。但从本质上看,社会的存在与发展是客观的。这是因为( )
①人类社会是物质世界长期发展的产物 ②构成社会物质生活条件的基本要素是客观的 ③人类社会的存在与发展基础是客观的 ④人的意志不能影响和决定社会的发展
A、①   B、①②  C、①②③  D、①②③④
10、“世间的一切事物都是运动的。”这说明( )
A、运动是绝对的、有条件和永恒的 B、运动是绝对的、永恒的和无条件的
C、静止是相对的、无条件的和暂时的 D、静止是不存在的
11、物质和运动的辩证关系是( )
A、物质是运动的主体 B、所有的物质都是运动的
C、所有的运动都是物质的运动
D、所有的物质都是运动的物质,所有的运动都是物质的运动
12、人有悲欢离合,月有阴睛圆缺,此事古难全。这说明( )
A.自然界和人类社会都是有规律的 B.自然界和人类社会遵循同样的规律
C.自然规律和社会规律都是古今不变的D.自然现象和人类社会现象都是循环往复的
台风是一种破坏力很强的灾害性天气系统,台风过境时常常带来狂风暴雨天气,引起海面巨浪,严重威胁航海安全。登陆后,可摧毁庄稼、各种建筑设施等,造成人民生命、财产的巨大损失。
13、利用气象卫星资料,可以确定台风中心的位置,估计台风强度,监测台风移动方向和速度,以及狂风暴雨出现的地区等。以上内容( )
A.是被实践证明了的正确认识 B.是对规律的认识和利用
C.属于真理的范畴 D.是正确的世界观
14、目前科技无法阻止台风的到来,也无法改变台风行进的路线,但人们可以预测台风的到来并做好防范工作,把损失减至最低。这表明( )
A.规律是客观的,但人们在客观规律面前不是无能为力的
B.只要充分发挥主观能动性,就能战胜台风
C.客观实际的发展离不开充分发挥主观能动性
D.人们只有不断提高科技水平,才能改变台风形成的规律
15、由于强热带风暴极大影响了灾区的生产生活,台风登陆地政府采取了一系列措施,将灾害带来的损失降低到了最低限度。这反映出 ( )
A.世界上任何事物之间都存在联系 B.物质和意识的辨证关系
C.实践是认识发展的根本动力 D.事物是绝对运动和相对静止的统一
16、我国著名科学家严济慈在回答发展科学、做学问的主要经验时,经常讲:“敢于好高骛远,善于实事求是”。 从哲学上看,敢于“好高骛远”是指( )
A.充分发挥主观能动性 B.不切实际的幻想
C.主观能动性的发挥受主观因素的制约
D.主观能动性的发挥受客观规律和客观条件的制约
17、上述“敢于好高骛远,善于实事求是”两句话结合起来就是要求我们( )
A.坚持从实际出发和实事求是的统一B.坚持发挥主观能动性和尊重客观规律的统一
C.必须不断积累正确的主观因素 D.办事情必须尊重客观条件
18、《三国演义》写尽了十八般兵器,但没有写到手枪;《封神榜》写尽商纣宫廷的奢华,却没有提到互联网、高尔夫。这是因为( )
 A.意识活动没有主动创造性 B.人们的意识无法反映未来
 C.意识的内容来自客观存在 D.人的意识无法把握事物的本质
19、 “日有所思,夜有所梦”,说的哲理是( )
①梦是客观事物作用于人脑留下的印象
②梦是一种意识活动,但归根到底还是人脑对客观事物的一种反映
③梦的素材是人脑自生的
④人脑是产生意识的物质器官,有了人脑就能产生意识
A.①④ B.①② C.③④  D.②③
20、“其实胸中之竹,并不是眼中之竹也,因而磨墨展纸,落笔倏作变相,手中之竹又不是胸中之竹也。”郑板桥的这句话蕴含的道理是 ( )
A.意识活动具有主动创造性 B.意识活动具有客观实在性
C.意识活动具有生动形象性 D.意识活动具有主观随意性
21、《国务院关于稳定消费价格总水平保障群众基本生活的通知》最近发布,要求各地政府采取措施,有步骤稳定市场物价,以保障群众基本生活。这体现了( )
A.意识活动具有目的性和计划性 B.发挥主观能动性必须尊重客观规律
C.意识是客观存在的反映 D.意识对客观事物具有促进作用
22、能够统一天下的秦始皇,造了一个举世闻名的长城去防御敌人,可就是没想到制造导弹去攻击敌人。从哲学的角度看,这是因为实践具有的特点是( )。
A.客观性 B.主观能动性 C.物质性 D.社会历史性
23、“荆人欲袭宋,使人先表澭水。澭水暴益,荆人弗知,循表而夜涉,溺死者千有余人,军惊而坏都舍。”从哲学上讲,荆人失败的主要原因是:( )
A.没有充分发挥人的意识的能动作用    B.没有按客观规律办事
C.不懂得实际情况是变化发展的    D.缺乏正确的理论指导
24、当今世界石油资源日益紧缺,寻找其他可再生资源代替石油已是大势所趋。南京工业大学两位在读的博士生李恒和孙鹏经过无数次试验,最终在秸秆、薯干、甘蔗等价格低廉的植物中找到了石油的替代品。这说明( )
①实践是人们能动地改造主观世界的活动  ②实践是认识发展的动力
③科学实验是人类最基本的实践活动  ④实践是认识的基础
A.①② B.②③ C.②④ D.③④
25、“吾生也有涯,而知也无涯。”庄子的名言给我们的哲学启示是( )
A.认识具有反复性 B.认识具有条件性
C.认识具有无限性 D.认识对实践具有反作用
二、非选择题(共50分)
26.近年来,随着经济社会的发展,低碳经济、低碳技术、低碳城市、低碳生活等概念不断涌现,低碳理念渐渐深入人心;同时,低碳理念也催生了“低碳一族”,促进了资源节约型环境友好型社会的建设。
结合材料,运用物质和意识的辩证关系分析说明树立低碳理念的正确性。(12分)
27.20l0年7月12日,如火如荼的南非世界杯落下了帷幕。
西班牙队创造了历史,他们第一次闯入世界杯决赛就捧起了大力神杯。西班牙的华丽足球让人们印象深刻,有媒体报道了西班牙夺冠的主要秘诀:
秘诀一:“强大的头脑和激情”热情奔放的西班牙人,球风也同样地“西班牙”、激情不仅使他们赢得了观众,也赢得比赛。
秘诀二:“重视训练的科学性”。西班牙队每天科学合理的安排训练,让队员始终保持着良好的状态。
从西班牙队获胜秘诀中,你获得哪些有关唯物论的哲学感悟?(12分)
28.2011年4月12日,是人类载人航天活动50周年纪念日。我国家的载人航天还处于发展阶段,载人航天飞行获得圆满成功,这是我国航天人尊重科学,以科学的精神、科学的理念、科学的方法、科学的机制推动工作,大胆探索创新、自强不息、勇于超越、埋头苦干的结果。
载人航天飞行的成功,探索出一套符合我国国情和重大科技工程的科学管理模式和方法,积累了新形势下组织实施重大科技工程的重要经验;突破了一大批具有自主知识产权的核心技术和关键技术,取得了一系列重大科技创新成果;证明了我国载人航天工程的计划、程序、步骤等举措是科学的。
(1)结合材料说明我国航天人是如何把尊重客观规律和发挥主观能动性结合起来的?(7分)
(2)我国载人航天工程的成功实施,反映了实践决定认识的哪些道理?(9分)
29、长期以来人们习惯视沙漠为害,是资源的“荒地”。如何治理沙漠、化害为利?人们进行了不懈的探索,积累了许多有益的经验。上个世纪80年代,中国科学家认为,“沙漠是资源”并提出了“沙产业理论”,提出创建“利用阳光,通过生物,延伸链条,依靠科技,对接市场”的沙产业。这是人类认识自然的一次重大突破。在“沙产业理论”的指导下,我国沙产业不断发展壮大,不少企业将自己的目光投向了广袤无垠的沙漠,利用沙漠资源创造经济效益,使被动的治沙转变成主动的沙漠生态构建。随着实践的发展,人们的认识再次升华:科学开发利用沙漠,沙漠是可以化害为利造福人类的。上述材料体现了《生活与哲学》第六课“求索真理的历程”中的哪些道理?(10分)
信丰中学2011—2012学年第一学期第二次月考
高二政治参考答案
一、最佳选择题。在以下各题所列出的四个选项中,选出最符合题意的一项。每小题2分,共50分。
1—5 ADCBD 6—10 BADCB 11—15 DABAB 16—20 ABCBA 21—25 ADCCC
二、非选择题(共50分)
28. (16)(1)①规律具有客观性,要求我们尊重客观规律,按客观规律办事。我国航天人尊重科学,以科学的精神、科学的理念、科学的方法、科学的机制推动工作,做到了按客观规律办事。(4分)
②认识和利用规律必须发挥主观能动性。航天人大胆探索创新,自强不息,勇于超越、埋头苦干,充分发挥了主观能动性。(3分)
(2)①实践是认识的来源。载人航天工程的成功实施,探索出一套符合我国国情和重大科技工程的科学管理模式和方法,积累了新形势下组织实施重大科技工程的重要经验。(3分)
②实践是认识发展的动力。载人航天工程的成功实施,突破了一大批具有自主知识产权的核心技术和关键技术,取得了一系列重大科技创新成果。(3分)
③实践是检验认识真理性的唯一标准。载人航天工程的成功实施,证明了我国探月工程的计划、程序、步骤等举措是科学的。(3分)
29、(10分)(1)对于治理沙漠、化害为利,人们进行了不懈的探索,积累了许多有益的经验。这体现了实践是认识的来源(2分)
(2)中国科学家提出了“沙产业理论”,提出创建沙产业这是人类认识自然的一次重大突破。这体现了实践是认识发展的动力。(2分)
(3)在“沙产业理论”的指导下,我国沙产业不断发展壮大,创造经济效益,这体现了
实践是检验认识的真理性的唯一标准;实践是认识的最终目的和归宿. (3分)
(4)随着实践的发展,人们的认识再次升华:科学开发利用沙漠为人类造福。体现了认识具有反复性、无限性、上升性。与时俱进,开拓创新,在实践中认识和发现真理,在实践中检验和发展真理. (3分)
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网本资料来自于资源最齐全的21世纪教育网www.21cnjy.com
江西省信丰中学2011-2012学年高二第二次月考(数学文)
一、选择题(本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的。)
1、若集合,集合,则“”是“”的( )
(A)充分不必要条件 (B)必要不充分条件
(C)充分必要条件 (D)既不充分也不必要条件
2、抛物线的焦点坐标是( )
A.(2,0) B.(- 2,0) C.(4,0) D.(- 4,0)
3、一射手对同一目标独立地射击四次,已知至少命中一次的概率为,则此射手每次射击命中的概率为( )
A. B. C. D.
4、设和为双曲线()的两个焦点, 若,是正三角形的三个顶点,则双曲线的离心率为( )
A. B. C. D.3
5、抛掷两粒均匀的骰子,已知第一颗骰子掷出6点,问掷出点数之和大于等于10的概率( )
(A) (B) (C) (D)
6、右图是2007年在广州举行的全国少数民族运动会上,七位评委为某民族舞蹈打出的分数的茎叶统计图,去掉一个最高分和一个最低分后,所剩数据的平均数和方差分别为( ).
A., B., C., D.,
7、已知函数的导函数的图像如下,则 ( )
A.函数有1个极大值点,1个极小值点
B.函数有2个极大值点,2个极小值点
C.函数有3个极大值点,1个极小值点
D.函数有1个极大值点,3个极小值点
8、命题:在中,是的充分不必要条件;命题:是的充分不必要条件,则( )
A.真假 B.假真 C.“或”为假 D.“且”为真
9、连掷两次骰子得到点数分别为m和n,记向量的夹角为的概率是( )
A. B. C. D.
10.函数f(x)的定义域为R,f(-1)=2,对任意,,则的解集为(A)(-1,1) (B)(-1,+∞) (c)(-∞,-l) (D)(-∞,+∞)
二、填空题(每题5分,共25分)
11、曲线在点()处的切线方程为 ;
12、为了了解高三学生的身体状况.抽取了部分男生的体重,将所得的数据整理后,画出了频率分布直方图(如图),已知图中从左到右的前3个小组的频率之比为1︰2︰3,第2小组的频数为12,则抽取的男生人数是     .
x 0 1 3 4
y 2.2 4.3 4.8 6.7
13、已知x、y的取值如右表:
从散点图分析,y与x线性相关,且回归方程为,则 .
14、给出下列四个命题:
①命题“”的否定是“”;
②线性相关系数r的绝对值越接近于1,表明两个随机变量线性相关性越强;
③若,则不等式成立的概率是;
④函数上恒为正,则实数a的取值范围是。
其中真命题的序号是 。(填上所有真命题的序号)
15、如右图,是一程序框图,则输出结果为 .
三、解答题本大题共6小题,共75分。解答应写出文字说明,证明过程或演算步骤
16. (本小题满分12分)
某河流上的一座水力发电站,每年六月份的发电量Y(单位:万千瓦时)与该河上游在六月份的降雨量X(单位:毫米)有关.据统计,当X=70时,Y=460;X每增加10,Y增加5;已知近20年X的值为:140,110,160,70,200,160,140,160,220,200,110,160,160,200,140,110,160,220,140,160.
(I)完成如下的频率分布表:
近20年六月份降雨量频率分布表
降雨量 70 110 140 160 200 220
频率
(II)假定今年六月份的降雨量与近20年六月份的降雨量的分布规律相同,并将频率视为概率,求今年六月份该水力发电站的发电量低于490(万千瓦时)或超过530(万千瓦时)的概率.
17、(本小题满分12分)
已知命题p:方程表示焦点在y轴上的椭圆,命题q:双曲线的离心率e(1,2),若p , q有且只有一个为真,求m的取值范围。
18、(本小题满分12分)
设的导数为,若函数的图像关于直线对称,且.
(Ⅰ)求实数的值 (Ⅱ)求函数的极值
19.(本小题满分12分)甲、乙两校各有3名教师报名支教,其中甲校2男1女,乙校1男2女.(I)若从甲校和乙校报名的教师中各任选1名,写出所有可能的结果,并求选出的2名教师性别相同的概率;
(II)若从报名的6名教师中任选2名,写出所有可能的结果,并求选出的2名教师来自同一学校的概率.
20. (本小题满分13分)
已知函数
(1)若在上是减函数,求的最大值;
(2)若的单调递减区间是,求函数y=图像过点的切线与两坐标轴围成图形的面积。
21. (本小题满分14分) 已知椭圆的左、右焦点分别为,离心率,右准线方程为。
(I)求椭圆的标准方程;
(II)过点的直线与该椭圆交于两点,且,求直线的方程。
21世纪教育网
w w w.21世纪教育网 高 考 资源 网
www.
x
y
x4
O oO
体重
50 55 60 65 70 75
0.0375
0.0125
15题图
21世纪教育网 -- 中国最大型、最专业的中小学教育资源门户网站。 版权所有@21世纪教育网

展开更多......

收起↑

资源列表