资源简介 6.3.3 余角和补角INCLUDEPICTURE "学习目标下.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/学习目标下.tif" \* MERGEFORMAT INCLUDEPICTURE "../../学习目标下.tif" \* MERGEFORMAT INCLUDEPICTURE "../../学习目标下.tif" \* MERGEFORMAT INCLUDEPICTURE "../学习目标下.tif" \* MERGEFORMATeq \o(\s\up7( INCLUDEPICTURE "知识梳理.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "知识梳理.tif" \* MERGEFORMAT ),\s\do5( ))知识点一 余角和补角1.如果两个角的和等于90°(直角),就说这两个角互为余角,简称这两个角互余,其中一个角是另一个角的余角.2.如果两个角的和等于180°(平角),就说这两个角互为补角,简称这两个角互补,其中一个角是另一个角的补角. 练习1 如果一个角的余角是60°,那么这个角的补角的大小是( A ).A.150° B.130°C.90° D.30°【解析】因为一个角的余角是60°,则这个角为30°,所以这个角的补角的大小是180°-30°=150°.故选A.总结 余角(补角)是指两个角的数量关系,是成对出现的,单独一个角或两个以上的角不能称其为余角(补角);一个角的余角(补角)可以有多个,但它们的度数是相等的;互余或互补的角只与数量有关,与位置无关.知识点二 余角和补角的性质3.同角(等角)的余角相等.4.同角(等角)的补角相等. 练习2 若∠1与∠2互补,∠2与∠3互补,则∠1与∠3的关系满足( B ).A.∠1+∠3=90°B.∠1=∠3C.∠1+∠3=180°D.∠1-∠3=90°总结 应用余角和补角的性质时应注意:①如果互补的两个角相等,那么这两个角都是直角;②“同角”指同一个角,“等角”指度数相等的角,同角一定是等角,但等角不一定是同角.eq \o(\s\up7( INCLUDEPICTURE "课后练习.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "课后练习.tif" \* MERGEFORMAT ),\s\do5( ))INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 基础巩固1.若∠α=54°30′,则∠α的余角的大小是( B ).A.35°38′ B.35°30′C.125°30′ D.125°38′【解析】因为∠α=54°30′,所以∠α的余角是90°-54°30′=89°60′-54°30′=35°30′.故选B.2.若∠A=120°,则它的补角的余角为( C ).A.20° B.25°C.30° D.35°【解析】因为∠A=120°,所以它的补角为180°-120°=60°,所以它的补角的余角为90°-60°=30°.故选C.3.下列结论:①互余且相等的两个角都是45°;②同角的余角相等;③若∠1+∠2+∠3=180°,则∠1,∠2,∠3互为补角;④锐角的补角是钝角;⑤锐角的补角比其余角大80°.其中正确的个数为( B ).A.2 B.3C.4 D.54.如图,小明将一个直角三角形纸片的直角顶点放在直线l上的点O处,固定直线l,当纸片绕着点O在直线l上方旋转时,∠1与∠2的度数会发生改变,则∠1与∠2的关系是( C ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX216.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX216.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX216.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX216.tif" \* MERGEFORMAT INCLUDEPICTURE "SX216.tif" \* MERGEFORMATA.互为补角 B.相等C.互为余角 D.以上都不对5.一副三角板按如图所示的方式摆放,则∠1补角的度数为( D ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX330.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX330.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX330.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX330.tif" \* MERGEFORMAT INCLUDEPICTURE "SX330.tif" \* MERGEFORMATA.45° B.135°C.75° D.165°INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 能力达标6.如图,∠AOC=∠BOD=90°,∠AOD=126°,则∠BOC的大小为( C ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX217.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX217.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX217.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX217.tif" \* MERGEFORMAT INCLUDEPICTURE "SX217.tif" \* MERGEFORMATA.36° B.44°C.54° D.63°【解析】因为∠AOC=90°,∠AOD=126°,所以∠COD=∠AOD-∠AOC=36°.又因为∠BOD=90°,所以∠BOC=∠BOD-∠COD=90°-36°=54°.故选C.7.如图,利用量角器测量角,有如下4个结论:①∠AOC=90°;②∠AOB=∠BOC;③∠AOB与∠BOC互为余角;④∠AOB与∠AOD互为补角.上述结论中,所有正确结论的序号是( D ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX221.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX221.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX221.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX221.tif" \* MERGEFORMAT INCLUDEPICTURE "SX221.tif" \* MERGEFORMATA.①② B.③④C.①②③ D.①③④8.如图,∠AOB=90°,OB是∠DOE的平分线,点C,O,D在同一条直线上.若∠DOE=68°,求∠AOC的度数.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX218.TIF" \* MERGEFORMAT INCLUDEPICTURE "../../SX218.TIF" \* MERGEFORMAT INCLUDEPICTURE "../../SX218.TIF" \* MERGEFORMAT INCLUDEPICTURE "../SX218.TIF" \* MERGEFORMAT INCLUDEPICTURE "SX218.TIF" \* MERGEFORMAT【解】因为OB是∠DOE的平分线,且∠DOE=68°,所以∠BOD=∠DOE=34°.又因为∠AOB=90°,所以∠AOD=90°-∠BOD=56°,所以∠AOC=180°-∠AOD=124°.INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 挑战创新9.(实践探究题)如图,以直线AB上一点O为端点作射线OC,使∠BOC=70°,将一个直角三角形的直角顶点放在点O处(∠DOE=90°).eq \o(\s\up7( INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX290.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX290.tif" \* MERGEFORMAT INCLUDEPICTURE "SX290.tif" \* MERGEFORMAT ),\s\do5(图1)) eq \o(\s\up7( INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX290A.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290A.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290A.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX290A.tif" \* MERGEFORMAT INCLUDEPICTURE "SX290A.tif" \* MERGEFORMAT ),\s\do5(图2))eq \o(\s\up7( INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX290b.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290b.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX290b.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX290b.tif" \* MERGEFORMAT INCLUDEPICTURE "SX290b.tif" \* MERGEFORMAT ),\s\do5(图3))(1)如图1,若直角三角板DOE的一边OD放在射线OB上,则∠COE=________°.(2)如图2,将直角三角板DOE绕点O逆时针方向转动到某个位置,若OC恰好平分∠BOE,求∠COD的度数.(3)如图3,将直角三角板DOE绕点O转动,如果OD始终在∠BOC的内部,试猜想∠BOD和∠COE有怎样的数量关系?并说明理由.(1)【答案】20【解析】因为∠BOC=70°,∠DOE=90°,所以∠COE=∠DOE-∠BOC=90°-70°=20°.(2)【解】因为OC平分∠BOE,∠BOC=70°,所以∠COE=∠BOC=70°.因为∠DOE=90°,所以∠COD=∠DOE-∠COE=90°-70°=20°.(3)【解】∠COE-∠BOD=20°.理由如下:因为∠COE+∠COD=∠DOE=90°,∠BOD+∠COD=∠BOC=70°,所以∠COE+∠COD-(∠BOD+∠COD)=90°-70°,所以∠COE+∠COD-∠BOD-∠COD=20°,所以∠COE-∠BOD=20°.6.3.3 余角和补角eq \o(\s\up7(),\s\do5( ))知识点一 余角和补角1.如果两个角的和等于90°(直角),就说这两个角互为余角,简称这两个角互余,其中一个角是另一个角的余角.2.如果两个角的和等于180°(平角),就说这两个角互为补角,简称这两个角互补,其中一个角是另一个角的补角. 练习1 如果一个角的余角是60°,那么这个角的补角的大小是( ).A.150° B.130°C.90° D.30°知识点二 余角和补角的性质3.同角(等角)的余角相等.4.同角(等角)的补角相等. 练习2 若∠1与∠2互补,∠2与∠3互补,则∠1与∠3的关系满足( ).A.∠1+∠3=90°B.∠1=∠3C.∠1+∠3=180°D.∠1-∠3=90°eq \o(\s\up7(),\s\do5( ))基础巩固1.若∠α=54°30′,则∠α的余角的大小是( ).A.35°38′ B.35°30′C.125°30′ D.125°38′2.若∠A=120°,则它的补角的余角为( ).A.20° B.25°C.30° D.35°3.下列结论:①互余且相等的两个角都是45°;②同角的余角相等;③若∠1+∠2+∠3=180°,则∠1,∠2,∠3互为补角;④锐角的补角是钝角;⑤锐角的补角比其余角大80°.其中正确的个数为( ).A.2 B.3C.4 D.54.如图,小明将一个直角三角形纸片的直角顶点放在直线l上的点O处,固定直线l,当纸片绕着点O在直线l上方旋转时,∠1与∠2的度数会发生改变,则∠1与∠2的关系是( ).A.互为补角 B.相等C.互为余角 D.以上都不对5.一副三角板按如图所示的方式摆放,则∠1补角的度数为( ).A.45° B.135°C.75° D.165°能力达标6.如图,∠AOC=∠BOD=90°,∠AOD=126°,则∠BOC的大小为( ).A.36° B.44°C.54° D.63°7.如图,利用量角器测量角,有如下4个结论:①∠AOC=90°;②∠AOB=∠BOC;③∠AOB与∠BOC互为余角;④∠AOB与∠AOD互为补角.上述结论中,所有正确结论的序号是( ).A.①② B.③④C.①②③ D.①③④8.如图,∠AOB=90°,OB是∠DOE的平分线,点C,O,D在同一条直线上.若∠DOE=68°,求∠AOC的度数.挑战创新9.(实践探究题)如图,以直线AB上一点O为端点作射线OC,使∠BOC=70°,将一个直角三角形的直角顶点放在点O处(∠DOE=90°).eq \o(\s\up7(),\s\do5(图1)) eq \o(\s\up7(),\s\do5(图2))eq \o(\s\up7(),\s\do5(图3))(1)如图1,若直角三角板DOE的一边OD放在射线OB上,则∠COE=________°.(2)如图2,将直角三角板DOE绕点O逆时针方向转动到某个位置,若OC恰好平分∠BOE,求∠COD的度数.(3)如图3,将直角三角板DOE绕点O转动,如果OD始终在∠BOC的内部,试猜想∠BOD和∠COE有怎样的数量关系?并说明理由. 展开更多...... 收起↑ 资源列表 6.3.3 余角和补角 - 学生版.doc 6.3.3 余角和补角.doc