资源简介 6.2.2 线段的比较与运算eq \o(\s\up7(),\s\do5( ))知识点一 尺规作图1.在数学中,我们常限定用无刻度的直尺和圆规作图,这就是尺规作图. 练习1 按要求作图,并保留作图痕迹.如图,已知线段a,b,c,用直尺和圆规作线段AD,使AD=2a+b-c.知识点二 线段的基本事实2.两点的所有连线中,线段最短.简单说成:两点之间,线段最短. 练习2 如图所示,从学校到公园有①②③④四条路线可走,其中最短的路线是( ).A.④ B.③C.② D.①知识点三 线段长度的运算3.连接两点的线段的长度,叫作这两点间的距离.4.一个点把线段分成相等的两条线段,这个点叫作线段的中点. 练习3 如图,C为线段AD上一点,B为CD的中点,且AD=16 cm,BD=4 cm,求AC的长.eq \o(\s\up7(),\s\do5( ))基础巩固1.如图,用圆规比较两条线段的大小,其中正确的是( ).A.AB=AC B.AB>ACC.AB2.七年级(1)班的同学想举行一次拔河比赛,他们想从两条绳子中挑出一条较长的绳子,同学们说出了几种方法,则( )是最合适的方法.A.把两条绳子放在同一条直线上,观察另一端的情况B.把两条绳子接在一起C.把两条绳子的一端对齐,然后向同一方向拉直两条绳子,另一端靠外的即为较长的绳子D.以上三种方法都可以3.下列四个生活、生产现象:①用两个钉子就可以把木条固定在墙上;②植树时,只要定出两棵树的位置,就能确定同一行树所在的直线;③从A地到B地架设电线,总是尽可能沿着线段架设;④把弯曲的公路改直,就能缩短路程.其中可用“两点之间,线段最短”来解释的现象有( ).A.①② B.①③C.②④ D.③④4.如图,已知线段AB=20 cm,M是AB的中点,点N在AB上,NB=4 cm,那么线段MN的长为( ).A.10 cm B.8 cmC.6 cm D.4 cm5.如图,已知C为线段AB的中点,D为CB上一点,下列关系表示错误的是( ).A.BD+AC=2BC-CDB.2CD=2AD-ABC.CD=AC-BDD.AB-CD=AC-BD6.如图所示,C是线段AB的中点,点D在线段AB上,且AD=DB.若AC=3,求线段DC的长.能力达标7.已知点A,B,C在同一条直线上,线段AB=5,BC=3,则线段AC的长度是( ).A.8 B.2C.2或8 D.以上都不对8.如图,点C在线段AB上,M是线段AB的中点,AB=12.(1)尺规作图:延长线段AB,并在延长线上作一点D,使得BD+BC=AB;(不写作法,保留作图痕迹)(2)在(1)的条件下,若CM=2AC,求线段AD的长度.挑战创新9.综合与实践【基础巩固】(1)如图1,点E,B,F都在线段AC上,AE=EB,F是BC的中点,则图中共有线段________条.图1【深入探究】(2)在(1)的条件下,若BF=AC,试探究EF与AC之间的数量关系,并说明理由.【拓展提高】(3)如图2,在(2)的基础上,G是AE的中点,若AC=20 cm,求GF的长.图26.2.2 线段的比较与运算eq \o(\s\up7( INCLUDEPICTURE "知识梳理.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "../知识梳理.tif" \* MERGEFORMAT INCLUDEPICTURE "知识梳理.tif" \* MERGEFORMAT ),\s\do5( ))知识点一 尺规作图1.在数学中,我们常限定用无刻度的直尺和圆规作图,这就是尺规作图. 练习1 按要求作图,并保留作图痕迹.如图,已知线段a,b,c,用直尺和圆规作线段AD,使AD=2a+b-c.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX236.TIF" \* MERGEFORMAT INCLUDEPICTURE "../../SX236.TIF" \* MERGEFORMAT INCLUDEPICTURE "../../SX236.TIF" \* MERGEFORMAT INCLUDEPICTURE "../SX236.TIF" \* MERGEFORMAT INCLUDEPICTURE "SX236.TIF" \* MERGEFORMAT【解】线段AD如图所示.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX310.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX310.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX310.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX310.tif" \* MERGEFORMAT INCLUDEPICTURE "SX310.tif" \* MERGEFORMAT总结 此题主要考查了复杂作图,关键是掌握在射线上截取线段等于已知线段.知识点二 线段的基本事实2.两点的所有连线中,线段最短.简单说成:两点之间,线段最短. 练习2 如图所示,从学校到公园有①②③④四条路线可走,其中最短的路线是( B ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX153.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX153.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX153.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX153.tif" \* MERGEFORMAT INCLUDEPICTURE "SX153.tif" \* MERGEFORMATA.④ B.③C.② D.①知识点三 线段长度的运算3.连接两点的线段的长度,叫作这两点间的距离.4.一个点把线段分成相等的两条线段,这个点叫作线段的中点. 练习3 如图,C为线段AD上一点,B为CD的中点,且AD=16 cm,BD=4 cm,求AC的长.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX166.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX166.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX166.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX166.tif" \* MERGEFORMAT INCLUDEPICTURE "SX166.tif" \* MERGEFORMAT【解】因为B为CD的中点,BD=4 cm,所以BC=BD=4 cm,所以CD=8 cm.又因为AD=16 cm,所以AC=AD-CD=16-8=8(cm).总结 在线段长度计算问题中,要结合图形中已知线段和所求线段的位置关系求解,要做到步步有根据.eq \o(\s\up7( INCLUDEPICTURE "课后练习.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "../课后练习.tif" \* MERGEFORMAT INCLUDEPICTURE "课后练习.tif" \* MERGEFORMAT ),\s\do5( ))INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 基础巩固1.如图,用圆规比较两条线段的大小,其中正确的是( C ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX168.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX168.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX168.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX168.tif" \* MERGEFORMAT INCLUDEPICTURE "SX168.tif" \* MERGEFORMATA.AB=AC B.AB>ACC.AB2.七年级(1)班的同学想举行一次拔河比赛,他们想从两条绳子中挑出一条较长的绳子,同学们说出了几种方法,则( C )是最合适的方法.A.把两条绳子放在同一条直线上,观察另一端的情况B.把两条绳子接在一起C.把两条绳子的一端对齐,然后向同一方向拉直两条绳子,另一端靠外的即为较长的绳子D.以上三种方法都可以3.下列四个生活、生产现象:①用两个钉子就可以把木条固定在墙上;②植树时,只要定出两棵树的位置,就能确定同一行树所在的直线;③从A地到B地架设电线,总是尽可能沿着线段架设;④把弯曲的公路改直,就能缩短路程.其中可用“两点之间,线段最短”来解释的现象有( D ).A.①② B.①③C.②④ D.③④4.如图,已知线段AB=20 cm,M是AB的中点,点N在AB上,NB=4 cm,那么线段MN的长为( C ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX169.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX169.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX169.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX169.tif" \* MERGEFORMAT INCLUDEPICTURE "SX169.tif" \* MERGEFORMATA.10 cm B.8 cmC.6 cm D.4 cm5.如图,已知C为线段AB的中点,D为CB上一点,下列关系表示错误的是( D ).INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX171.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX171.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX171.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX171.tif" \* MERGEFORMAT INCLUDEPICTURE "SX171.tif" \* MERGEFORMATA.BD+AC=2BC-CDB.2CD=2AD-ABC.CD=AC-BDD.AB-CD=AC-BD【解析】因为C是线段AB的中点,所以AC=BC,AB=2BC=2AC,所以CD=BC-BD=AC-BD,BD+AC=AB-CD=2BC-CD.因为CD=AD-AC,所以2CD=2AD-2AC=2AD-AB.所以选项A,B,C均正确,不符合题意.而选项D中,AB-CD=AC+BD,所以选项 D错误,符合题意.故选D.6.如图所示,C是线段AB的中点,点D在线段AB上,且AD=DB.若AC=3,求线段DC的长.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX173.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX173.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX173.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX173.tif" \* MERGEFORMAT INCLUDEPICTURE "SX173.tif" \* MERGEFORMAT【解】因为C是线段AB的中点,所以AB=2AC.因为AC=3,所以AB=6.因为点D在线段AB上,AD=DB,所以AD=AB,所以AD=2,所以DC=AC-AD=1.INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 能力达标7.已知点A,B,C在同一条直线上,线段AB=5,BC=3,则线段AC的长度是( C ).A.8 B.2C.2或8 D.以上都不对【解析】①当点C在线段AB上时,AC=AB-BC=5-3=2;②当点C在线段AB的延长线上时,AC=AB+BC=5+3=8.综上所述,线段AC的长度是2或8.故选C.8.如图,点C在线段AB上,M是线段AB的中点,AB=12.(1)尺规作图:延长线段AB,并在延长线上作一点D,使得BD+BC=AB;(不写作法,保留作图痕迹)INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX174.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX174.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX174.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX174.tif" \* MERGEFORMAT INCLUDEPICTURE "SX174.tif" \* MERGEFORMAT(2)在(1)的条件下,若CM=2AC,求线段AD的长度.【解】(1)因为AC+BC=AB,所以若BD+BC=AB,则BD=AC.所作点D如图所示:INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/SX297.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX297.tif" \* MERGEFORMAT INCLUDEPICTURE "../../SX297.tif" \* MERGEFORMAT INCLUDEPICTURE "../SX297.tif" \* MERGEFORMAT INCLUDEPICTURE "SX297.tif" \* MERGEFORMAT(2)因为M是线段AB的中点,AB=12,所以AM=AB=×12=6.又因为CM=2AC,所以AC=AM=×6=2.由(1)知BD=AC,所以AD=AB+BD=AB+AC=12+2=14.INCLUDEPICTURE "三角.tif" INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "../三角.tif" \* MERGEFORMAT INCLUDEPICTURE "三角.tif" \* MERGEFORMAT 挑战创新9.综合与实践【基础巩固】(1)如图1,点E,B,F都在线段AC上,AE=EB,F是BC的中点,则图中共有线段________条.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/H12.tif" \* MERGEFORMAT INCLUDEPICTURE "../../H12.tif" \* MERGEFORMAT INCLUDEPICTURE "../../H12.tif" \* MERGEFORMAT INCLUDEPICTURE "../H12.tif" \* MERGEFORMAT INCLUDEPICTURE "H12.tif" \* MERGEFORMAT图1【深入探究】(2)在(1)的条件下,若BF=AC,试探究EF与AC之间的数量关系,并说明理由.【拓展提高】(3)如图2,在(2)的基础上,G是AE的中点,若AC=20 cm,求GF的长.INCLUDEPICTURE "../../../../广东慧源同步上册/广东慧源七年级上册数学/H13.tif" \* MERGEFORMAT INCLUDEPICTURE "../../H13.tif" \* MERGEFORMAT INCLUDEPICTURE "../../H13.tif" \* MERGEFORMAT INCLUDEPICTURE "../H13.tif" \* MERGEFORMAT INCLUDEPICTURE "H13.tif" \* MERGEFORMAT图2【答案】(1)10.【解】(2)5EF=3AC.理由:设BF=x,因为BF=AC,所以AC=5BF=5x.因为F是BC的中点,所以BC=2BF=2x,所以AB=AC-BC=5x-2x=3x.因为AE=EB,所以BE=AB=2x,所以EF=BE+BF=2x+x=3x,所以5EF=3AC.(3)设BF=x,因为AC=20 cm,所以由(2)得AC=5x=20 cm,所以x=4 cm,所以AE=BE=x=4 cm,EF=3x=12 cm.因为G是AE的中点,所以GE=AE=x=2 cm,所以GF=GE+EF=2+12=14(cm),即GF的长为14 cm. 展开更多...... 收起↑ 资源列表 6.2.2 线段的比较与运算 - 学生版.doc 6.2.2 线段的比较与运算.doc